How to implement a 10 second countdown in the CMD command and display 10 9 8 7

Updated on technology 2024-05-03
11 answers
  1. Anonymous users2024-02-08

    static atimer = new ;

    static void main(string args)+= new ;

    true;static void ontimedevent(object source, e)

    for (int a = 10; a >0; a++)

    It seems like that's fine

    Then run Build and run it under cmd.

  2. Anonymous users2024-02-07

    echo off

    for /l %%a in (10,-1,0) do (echo %%a

    for l %%b in (1,1,7000) do (ver >nul) : ver command can be used to time exactly, which means that 7000 ver executions are equivalent to 1 second.

    clspause:: This is the program that is executed.

  3. Anonymous users2024-02-06

    echo off

    setlocal enabledelayedexpansionfor /l %%a in (10,-1,1) do (set ss=%%~a

    if !ss!lss 10 set ss=0%% acls & echo 00:00:!ss!

    ping -n "2">nul

    cls & echo bo..o..o..o..o..o..o..o...m...

    echo boom ——! A big **, a huge pit on the ground, and a mushroom cloud in the air.

    pause

  4. Anonymous users2024-02-05

    What is this problem, seeking explanation?

  5. Anonymous users2024-02-04

    @echo off

    set delay=5

    set p=countdown nul

    set /a delay=%delay%-1if %delay% equ 1 goto bgoto a

    The commands that becho needs to execute are written here.

    pause

  6. Anonymous users2024-02-03

    private sub form_load()= "10"

    trueend sub

    private sub timer1_timer()static a as integer

    a = cint(

    a = a - 1

    aif a = -1 then = "10"

    end sub

    It's not very precise, that's about it.

    static is a static variable declaration.

    That is, it always has a memory allocation while the program is running and will always have a memory allocation even if the end value of the procedure or function is the same, and the dim is only valid within the function, and when the function completes, the variable memory is released.

  7. Anonymous users2024-02-02

    Add a timer control on the form with the interval property set to 1000;

    Add another label control.

    Then enter **:

    private sub timer1_timer()static a as integer

    if a = 0 then

    a = 10

    end if

    a = a - 1

    aend sub

  8. Anonymous users2024-02-01

    Add a timer control, interval=1000, and then add a label, caption=10.

    private sub timer1_timer()-1

    ifend if

    end sub

  9. Anonymous users2024-01-31

    Use the "dead" loop: set a time difference, if the difference between the current time and the set time is not greater than the set time difference, the loop will not be exited, so as to achieve the purpose of time delay.

    echo off

    set /a start=%time:~6,2%:prodelay

    set a now=%time: 6,2%set a diff=%now%-%start%rem The following sentence prevents errors when the number of seconds jumps from 59 to 1.

    if %diff% leq 2 goto :prodelayecho ok!

    The ping command is used to achieve delay, which is ingenious and controllable, but the accuracy is not high.

    For example, ping -n 3 >nul can pause for about 2 seconds, and the number after -n is the number of packets sent, plus one for the pause seconds.

    The deviation of this method per second is 1 second.

  10. Anonymous users2024-01-30

    @echo off

    set /a s=50+1

    ping -n %s% >nul

    start "" notepad

    pause for 50 seconds and then run the notepad program.

    set /a s=50+1

    for /l %%i in (1,1,!s!) do (set /a s-=1

    ping -n 2 >nul

    title The countdown begins!s!)

    start "" notepad

    pause

  11. Anonymous users2024-01-29

    Use setinterval to schedule 1 second to execute once each time minus 1 to 0.

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