The question of chemical gases, is there a contradiction between gas and liquid

1.The momentum of its molecules is the same when the temperature is the same. Since the CO2 molecule is more massive than the HE molecule, the HE molecule moves at a large rate.

2.Density = = m v, since 1molCO2 is more mass than 1molhe, the density of CO2 is greater.

3.Due to the communication with the atmosphere, the pressure of the two bottles may or may not be the same after a period of time.

There are three scenarios:1When the pressure inside the bottle is higher than the atmospheric pressure, the pressure decreases faster than CO2 because the HE molecule moves faster than CO2.

So if the pressure reduction is not over at 10 seconds, the pressure of CO2 is higher than that of HE. 2.In the case of 1, if the pressure reduction has ended, the pressure of the two bottles is equal.

3.If the external pressure is higher than the internal pressure, then the outside air enters the bottle, and the pressure is the same for both bottles because the air enters the bottle at the same rate.

1.In the same way, the temperature and volume are the same, the pressure is the same, and the velocity is the same, because of its large molecular weight.

3.Again, both bottles can be treated as ideal gases.

1 The speed is the same.

2 CO2 density is high.

3 Not the same!

My answer, it's completely smashed, haha! The master is here to advise!

The density of HEC2 is more different.

1.The smaller the relative molecular mass, the faster the particle movement, so HE is greater than CO2;

The density is greater than he;

3.No, because the rate of movement of HE molecules is greater, the pressure in the volumetric flask containing HE decreases quickly.

Liquids are one of the three major forms of matter. There is no definite shape and is often influenced by the container. However, the volume is fixed under constant pressure and temperature.

In addition, the pressure exerted by the liquid on the edge of the container is different from that of other states. This pressure is transmitted in all directions, not only does it not decrease and burn up, but it also increases with the depth, and the deeper the water, the greater the water pressure.

Gas refers to a shapeless and volumetric fluid that can be deformed and flowable. A gas is a state of matter.

Gases and liquids are fluids: they can flow and can be deformed. Unlike liquids, gases can be compressed.

If there is no limit, the gas can diffuse without limiting its volume. The atoms or molecules of gaseous matter can move freely with each other. The kinetic energy of atoms or molecules of gaseous substances is comparatively high.

The form of the gas can be affected by the volume of the body, the temperature and the pressure of the body.

Here's how to distinguish it:

It is distinguished according to the melting and boiling points of the substance.

The melting point is higher than the normal temperature, about 20 degrees Celsius, it is a solid at room temperature, and if it is lower than room temperature, it is a liquid.

The boiling point is higher than normal temperature, about 20 degrees Celsius, it is a gas at room temperature, and if it is lower than room temperature, it is a liquid.

The drainage method collects oxygen, and oxygen does not use the exhaust method, because the density is close to that of air.

Carbon dioxide is denser than air, and the upward air exhaust method is used.

Air collection, you fill a bottle with water, pour it out and you're done.

Collecting oxygen: Since oxygen is heavier than air, the upward air discharge method can be used, and because oxygen is insoluble in water, the drainage method can also be used

Carbon dioxide collection: Since carbon dioxide is heavier than air, it can also be used to exhaust air upwards, and carbon dioxide can also be collected by discharging saturated sodium bicarbonate solution.

Collect air: You can fill the cylinder with water and let the water flow out slowly, preferably in a place where the air flow is relatively stable.

According to the theorem, PV T is a constant, and the temperature is unchanged in the high resistance problem, and the pressure of AB after compression is the same, so the volume ratio of AB is the size of Dingchang pants, so the length ratio of AB is colonization, that is, 1:3, so 4*(1 (1+3))=1

This kind of question is actually not difficult for you, as long as you do more, it feels pure and wanton, and you will know the answer at a glance.

1cm, because there are 3 volumes of gas in part B and 1 volume of gas in part A, after pushing a certain distance to the left, the gas is compressed, because A is active, so the gas pressure on both sides of A is the same, and the pressure of the same gas is the same density, so each volume of gas will be reduced by a certain amount of volume with the same hand belt, that is, the reduction of 3 volumes of gas is 3 times the reduction of the gas in the morning and middle of body 1, and now the piston moves 4cm to the left, then the other three volumes will move 3cm to the left, A volume of gas moves 1 cm to the left

1 b because the generated P2O5 is solid.

2 C3 Advantages: There is no need to open the bottle, so that the air in the bottle will not come into contact with the outside world, so only the reaction products are obtained after the reaction.

4 A5 A Remember that O2 is an accelerant, not a fuel.

6 Oxygen is flammable.

7 The phenomenon of paraffin wax burning in oxygen: burning violently, emitting (yellow) light, exothermic, if the cold beaker is covered above the flame, there are (small water droplets) generated on the inner wall of the beaker.

8 Combustion and slow oxidation are both oxidation.

9 c

1、b2c

3. It can make oxygen fully react.

4、a5 a

6 Oxidation.

7. Yellow water.

8. Oxidation 9 C

1. B (only consumes gas, does not produce gas).

2. C (the density is smaller than that of air, and the balloon can rise; Combustion does not occur in the air and ** otherwise too dangerous)

3. Avoid the overflow of heated gas 4 and a (the other three have fixed components in the air) when the red phosphorus is inserted into the gas collection cylinder after ignition

5. A (help liquid hydrogen combustion).

6. Oxygen has (oxidation) properties.

7. The phenomenon of paraffin wax burning in oxygen: burning violently, emitting (white) light, exothermic, if the cold beaker is covered above the flame, the inner wall of the beaker has (colorless small droplets) generated.

8. Oxidation reaction 9, c

b c to avoid causing systematic errors a a blue I don't know the color of this light , water droplets oxidation c

b.Red phosphorus is only a solid after combustion, and the rest has a gas that produces helium, which is 2

The product is a solid and has the least effect on the volume determination.

a.Carbon monoxide is a toxic gas in the rest of the air that contains aAccelerant Oxygen has always been a combustible agent.

Flammability white, small water droplets.

Oxidation reactions. c.Because the density of oxygen is greater than that of air, it is below the air, but it is easy to mix because the density is not much different, so the glass sheet should be covered.

With a system of equations, the key to this kind of problem is to find the quantity of two substances, and with the quantity of matter, everything else is easy to find.

Let the quantities of CO and CO2 be x and y

15 = molar mass of Co 28 * x + Molar mass of Co 44 * y molar volume.

Solve the sum of the molar masses of x and y = total mass 15 divided by the amount of matter.

Density = mass 15 divided by volume.

CO volume fraction = divided by total volume.

CO2 volume fraction = divided by total volume.

Therefore, 1, the molar mass of the mixed gas is: 15 grams) 2, the density is: 30 grams of liters).

3. If CO accounts for V1L, CO2 accounts for L.

v1*28+(

Solution: v1 = liter).

That is, the volume fraction occupied by CO is: (

4. The volume fraction occupied by CO2 is:

The molar mass of CO is 28, the molar mass of CO2 is 44, the equation of the column, let the quantity of CO matter be X, the quantity of CO2 substance is Y, 28X+44Y=15, X+Y=, after finding it, the problem will be solved, I hope it will help you.

Let the mass of one of them be x, list the equations according to the molar volume of the gas, and then get x, and then bring in each formula to obtain the number.

1。It is a false statement that hot air has a lower air pressure than cold air in the same volume.

For example, if the mass of the air does not change and the volume does not change, then the temperature increases and the pressure increases. Therefore, the premise of your argument must be that the air quality will fall more than the temperature will increase.

2。Why does the temperature of water in a container increase while the pressure increases?

If the container is closed, the pressure will inevitably increase (assuming that the water above 4 degrees Celsius fills the container), and the water will expand when heated, but now the volume is limited by the closed container, and the pressure will inevitably increase to counteract this tendency. The container is closed but there is space above, and the situation is similar to above (a little more complicated), and the pressure is still increased.

The open container is 1 atmosphere, no matter how the temperature is raised, the pressure remains the same. Even if the liquid level rise is taken into account, it is still 1 atm, and the pressure experienced by the liquid is the external pressure experienced by the liquid as a whole (although the internal pressure increases slightly).

What I'm trying to say is - is the water in the container a gas?

The space of the container is limited, and the hot air with the same mass is larger than the cold air, so the compression is naturally greater.

The air inside the container is heated by a fixed volume, and the air pressure inside the container increases.

In the most rigorous way of calculation, it does not become But in the formula for calculating pressure in junior high school physics, it is closely related to height, the temperature of water increases, the expansion becomes larger, the volume becomes larger, and the height becomes higher.

I think this is how this question is understood:

When mixed with air, the true air pressure Pa at a certain time is not equal to the true air pressure Pa"

At another moment, the real barometric pressure pb is not equal to the true barometric pressure pb"

But the poor answer!

pa-pa"Not equal to pb-pb"

This is due to the fact that the compression of air is not like the liquid pressure by the height of the h-linear table, the compression of air is nonlinear, pv = constant.

Didn't you get into the air?

It means that when the outside world starts to press a ruler and make it clear, the indication is not the original one, and it will definitely change.

It won't change, and it's definitely wrong.

The air is mixed in so that the barometer will change with the external temperature register, and the outside atmospheric pressure will not change but the temperature will change, so that the indication of the air pressure gauge will also change.