When the crystal N2O4 is placed in a closed container for vaporization equilibrium constant problem

Original equilibrium: k==c(no2) 2 c(n2o4), then k c(no2)===c(no2) c(n2o4).

New balance: k c'(no2)===c'(no2)/c'(n2o4)

Since the new equilibrium is obtained by moving the original equilibrium in the direction of generating NO2, i.e., C'(no2)>c(no2).

So: k c(no2)===c(no2) c(n2o4)>k c'(no2)===c'(no2)/c'(n2o4)

i.e.: c(no2) c(n2o4)>c'(no2)/c'(n2o4)

So the answer is a decrease in the ratio.

Take a look at the expression of k!! The question asks the value of c(no2) c(n2o4), not the equilibrium constant k.

and k===[c(no2) c(n2o4)]*c(no2)

kasing123 is still a high school student, right? It seems that the expression of the equilibrium constant is not yet known.

The one upstairs don't mislead others.

As for the equilibrium constant, even if a new equilibrium is reached by adding a number of N2O4, the new equilibrium will still be equal to the old equilibrium. The temperature is constant, and k is constant.

After the first equilibrium is reached, 1molNO2 is introduced again

The new equilibrium state reached, under constant temperature and pressure, is equivalent to the equilibrium reached by increasing the pressure by 1 times on the basis of the original equilibrium, and the increased pressure equilibrium moves in the direction of volume reduction, that is, the equilibrium moves in the direction of positive reaction, NO2

The conversion rate increases, so b% a%, that is, b a, so choose b

N02, the volume increases, it can be considered that two same containers add the same nitrogen dioxide, after the same balance is established, the two containers are superimposed, and the partition is removed, then the volume fraction of N204 is the same as that in the original two containers, and remains unchanged

So choose A

The spawn rate is three times the n2 consumption rateThe rate of formation of H2 represents the rate of the reverse reaction, and the rate of N2 consumption represents the rate of the positive reaction, which is equal in the positive fit.

c.It's all a positive reaction.

d.The volume is fixed, the mass of the gas is conserved, and the density is constant.

b, i.e., the rate of positive reaction is equal to the reverse reaction.

According to the reaction formula, the rate at which NO2 is generated by the forward reaction is twice the rate at which the counter-reaction is used to tease the cherry blossoms into O2 when the reaction reaches equilibrium. If the rate of a is equal, it will also respond to the positive reaction of the fierce plexus, and it cannot be balanced.

Because the proportional coefficient of the two is different.

（1）n2o4（g）?2NO2(G), whose chemical equilibrium constant k=[NO][n

o]；So the answer is: [no][n].

o]；(2) The equilibrium constant in the chart increases with temperature, indicating that the equilibrium is proceeding in the positive direction, and the positive reaction is endothermic reaction.

So the answer is: endothermy;

3) The reaction is an endothermic reaction with the increase of gas volume, which is analyzed according to the principle of chemical equilibrium movement;

A The mass of the mixed gas is conserved, the volume is unchanged, and the density of the mixed gas in the container does not change during the reaction and in the equilibrium state, which does not mean that the reaction reaches the equilibrium state, so A is wrong;

b C(NO2) in the gas mixture does not change, which is a sign of equilibrium, so B is correct;

At the same time as the decomposition of C N2O4, 1mol NO2 is generated, which indicates that the reaction is proceeding in a positive direction, and it cannot be said that the reaction has reached an equilibrium state, so C is wrong.

So the answer is: b;

4) According to the chemical equilibrium three-stage column;

n2o4（g）?2no2（g）

Initiation (mol) 0

Amount of change (mol).

40s（mol）

b=；So the answer is:;

In the chart, 80s-100s are analyzed to reach the equilibrium state, and the equilibrium conversion rate of N2O4 = ?

So the answer is:;

The reaction rate of NO2 is calculated within 20s and 40s = ?

2l40s?20s

s, the ratio of the rates is equal to the ratio of the coefficients of the chemical equation, and the average reaction rate (N2O4)=1 expressed as N2O4

2υ（no2）=?s；

So the answer is: mol?l-1?s-1．

From the information, it can be seen that if the average relative molecular mass of the mixed gas decreases, the equilibrium moves in reverse, a constant capacitance, and N2 is introduced, which has no effect on the reaction, and the equilibrium does not move, so A is wrong;

b enters NO2 and the balance moves in the positive direction, so B is wrong;

c The reaction is an exothermic reaction, the temperature is raised, and the equilibrium moves in reverse, so c is correct;

d When N2O4 is introduced, the pressure increases when the capacity is constant, and the balance moves in the positive direction, so D is wrong;

Therefore, C

The temperature changes, and the balance is bound to move.

And this reaction is also a reaction in which the amount of gaseous matter changes with the equilibrium movement.

Yes, because chemical reactions follow the conservation of mass.

It is the potato that is right, because the mass does not change, the volume does not change, so the density does not change.

If the mass does not change, the average molar mass changes as the quantity of hail changes.

Subject to change. The pressure of the gas is related to the amount of gaseous substances, the number of volumes, and the temperature. In it, both the amount and temperature of the substance change. The volume has not changed, and it is not possible to determine whether it has changed.

Because it is a reversible reaction, the concentration of each substance does not change when the equilibrium is reached, and the color of the reaction mixture does not change.

Because the chemical equilibrium constants of each equilibrium are different, the concentrations of reactants and products are not necessarily equal.

Since it is a reversible reaction, it is impossible for the reactant to be completely converted into a product.

In a reversible reaction, the speed of the positive reaction is equal to that of the reverse reaction.

D is chosen because v is positive = v inverse in equilibrium, i.e. the ratio of coefficients.

Do you understand.

d's coefficient is forced to be 1:2, so d is correct.