Forty nine chickens and rabbits, a hundred legs go forward, how many chickens are there? How many ra

Three ways to answer the problem of chickens and rabbits in the same cage:

1. Hypothetical method:

Let's say it's all chicken:

49 2 = 98 pcs.

100-98=2.

2 (4-2) = 1....Rabbit.

49-1=48....Chicken.

The assumption is that it's all rabbit thinking, and the same as above.

2. Equation method: Let the rabbit be x and only calculate it simply.

Solution: There are x rabbits; There are 49-x chickens.

4x+（49-x)×2=100x=1

Answer: Slightly. 3. Leg chopping method:

Half of the chicken and rabbit legs are cut off, leaving 100 2 = 50.

The chicken has one leg left, the rabbit has two legs, and the chicken and rabbit each have one leg to cut off, for a total of 49 legs. The chicken has no leg, and the rabbit has one leg left, 50-49 = 1, then the rabbit has 1, and the chicken has it.

49-1=48....

Hope it helps!

Suppose there are x rabbits, y chickens.

x+y=49

4x+2y=100

Will the equation be solved?

x=1y=48

If 49 are all chickens, then there should be 98 legs, is there 2 missing? So there is one rabbit in the 49.

Scheme 1 has 49-x rabbits and 49-x chickens.

Rabbits are known to have 4 legs and chickens 2 legs.

4x+2(49-x)=100

x = 1 A: 1 rabbit and 48 chickens. Scenario 2

Answer: 1 rabbit and 48 chickens.

There are 49 chickens and rabbits with a total of 100 legs.

There are rabbits (100-49x2) 2=1.

There are 49-1 = 48 chickens.

If it's all chickens, there are 49x2=98 feet, 2 feet less, 1 rabbit has 2 more legs than chickens, so there are 2 2=1 rabbits).

If there are x chickens, then there are 49-x rabbits.

The chicken has 2 legs, and the rabbit core is sold with 4 legs.

2x+4(49-x)=100

2x=96x=48, so there are 48 chickens and 1 rabbit.

One way is to let the rabbit retract 2 feet, all of which have 2 feet to the ground, and a total of 98 feet to the ground for 49 heads, that is, only 2 feet are retracted, and there is only 1 rabbit for all.

The fake pants are all rabbits.

Chicken: (196-100) (4-2).

48 (only) loss cover pure early.

(Total number of feet - total number of heads Number of chicken's feet) (Number of rabbit's feet - Number of chicken's feet) = Number of rabbits. Rabbit.

14 chickens: 36-14 = 22 chickens

May it help you!

Consider that the rabbit with legs, the chicken with claws, and the accompaniment will be Wang.

Rabbit = 100 4 = 25 Luling Yuan.

Chickens = 99-25 = 72 pcs.

In elementary schools, this kind of problem is often hypothetized.

Suppose 49 are all wild chickens, with a total of legs:

49 2 = 98 articles.

Less: 100-98 = 2 pure enlightenment.

Each rabbit has 4-2 = 2 more legs than a pheasant.

Rabbit pomace orange: 2 2 = 1.

Pheasants: 49-1=48 pheasants.

Set x rabbits.

4x+2（49-x）=100

x=149-1=48

1 rabbit and 48 pheasants.

Assuming that they are all pheasants, then 49 pheasants have 98 legs. The missing two are the legs of the rabbit, which means that there is 1 rabbit. So 1 rabbit, 48 pheasants.

Come, listen to all my animals lift one foot! There are 51 legs left! Come on, go on, all the animals are lifting one leg, and there are two legs left!

Whose? Rabbit's! Come, go on, the remaining two legs stand that rabbit puts the legs down!

100-4) 2=48 So 48 chickens! A rabbit!

The pheasant rabbit walks on 49,100 legs. Q: How many pheasants are there? How many rabbits are there?

Set x chickens and y rabbits.

So x y 49

2x＋4y＝100

There are 49 chickens and rabbits with a total of 100 legs.

There are rabbits (100-49x2) 2=1.

There are 49-1 = 48 chickens.

If it's all chickens, there are 49x2=98 feet, 2 feet less, 1 rabbit has 2 more legs than chickens, so there are 2 2=1 rabbits).

Suppose chickens have x rabbits.

then: x+y=49;2x+4y=100

Yields: x=48;y=1

So there are 48 chickens and one rabbit.

Chickens x rabbits.

x+y=49

2x+4y=100

x=48 y=1

48 chickens and 1 rabbit.