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Odd numbers must be silky, and even numbers are not easy to say, and they are all possible.
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Are you talking about the number of chromosomes in humans or fruit flies or something?
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Just see if there are homologous chromosomes.
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There is no dominance in the middle birth, and the disease of the birth of a girl is often obvious.
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It is assumed that both teams are on autosomes.
p: rrtt * rrtt
F1: RRT (red eye is not possible, so TT is on the X handicap) correct:
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According to the description of the stem, it can be seen that the genotype of the individual with white eye color may be RR, the individual with purple eye color R t, and the red individual R tt, and the parents are homozygous and the offspring have purple eyes, so the white eye parents should contain the T gene.
So the red eye (RRT) and the white eye (RRT) next determine what chromosome to on:
Because the difference between purple and red eyes is the T gene, the R gene should be the same combination on the autosome, and the T gene should be different on the X chromosome, then the red-eyed female RR X T X T T T and the white-eyed male TT X T Y
The genotype of the offspring is rrx t x t and purple-eyed female; rrx t y is a red-eyed male.
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I'm using the hypothetical method.
First of all, the two pairs of genes must be one pair on the autosomal and the other on the X chromosome (if both are on the autosome, there will be no difference in traits between males and females).
So it's 2
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Selected core "high school biology" autosomal genetic knowledge points are summarized.
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<> in this diagram, A, B, and C all have 6 chromosomes.
There are 4 chromosomes in this picture.
There are 4 chromosomes in the first row, 8 in the first in the second row, and 4 in the second and third rows.
So when you check chromosomes, whether the chromosomes are type X or type I, there are several chromosomes with a few centromere.
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Regardless of whether the chromosomes are composed of sister chromatids, in a cell, the number of centromere points corresponds to the number of chromosomes, which is constant, and the number of centromere points can be counted to know the odd and even number of chromosomes. Not to be confused. Kiss!
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Count whether the number of centromeres is odd or even.
Separation in pairs, one cell enters two chromosomes, and there is no difference from the normal way.
First, the dominant recessive nature of albinism and sickle anemia was determined, and according to the left half of Figure 1, it can be concluded that anemia is a recessive genetic disease, which is bb; Then look at Figure 2, because if it is normal, it can be cut, and if it is not normal, it can't, so B is normal, C is albino, and both are homozygous, only A is heterozygous (because A can cut out three pieces: DNA is a double helix structure, only one of A can be cut, B can be cut all of them, cut into two short and two long, C is not cut) Because albinism is a recessive genetic disease, it is AA, so it can be known that B is AA and C is AA >>>More
There are two solutions to this problem: First, push directly. According to the topic, the second generation of children has bb, bb, bb, where gray is bb, bb, the ratio is 1 3 and 2 3, and the free mating of the second generation is: >>>More
That little creature in high school is indeed very shallow. And the genetics involved can be said to be a bit of popular science introduction. If you are really interested, buy a book on genetics and read it, and you will find out if you really like it. >>>More
Solve the problems that high school biology students are prone to.