Mathematically solve equations to find detailed processes, mathematically solve equations, find proc

Solution: First x-3》0 get x》3

Move 2x to the right of the equation and square the two sides.

x-3=4x^2-24x+36

4x^2-25x+39=0

x-3)(4x-13)=0

x=3 or x=13 4

Commutation method. 2x+√(x-3)=6

x-3)=6-2x

x-3)=2(3-x)

Order: a= (x-3).

Then: 3-x=-a

The original equation is: a=-2a

Solution: a=0 or a=-1 2

x-3)≥0

a=√(x-3)=0

x=3I hope mine is helpful to you, o( o!

2x+√(x-3)=6

x-3)=6-2x

x-3=(6-2x)²

Solve binary equations.

Pay attention to root addition. Method 2

2x+√(x-3)=6

2x-6+√(x-3)=0

2（x-3)+√x-3)=0

2(√（x-3))²x-3)=0

Let (x-3)=y

Solution: Move the term to get x-3=(6-2x), x-3 0, and then you can solve it yourself to get x=3 or x=13 4

Let the root number (x-3)=t t t be greater than or equal to 0

x-3=t^

x=t^+3

So 2t +6+t=6

2t(t+1)=0

t=0 or -1 (rounded).

So t=0x=3

The original equation becomes ln(,[5(1-x) 3], subtracting from the left and increasing from the right, with a unique solution.

Let f(x)=[5(1-x) 3] ,f(,f(,f(,f(,f(,f(,f(,f(,f(,,x

1) 2/(x+2)=3/(x-2)2(x-2)=3(x+2)

2x-4=3x+6

2x-3x=6+4

x=10x=-10

It is tested: x=-10 is the solution of the original fractional equation.

2) x/(x+1)+(x-1)/x=2x^2+(x+1)(x-1)=2x(x+1)x^2+x^2-1=2x^2+2x

x^2+x^2-2x^2-2x=1

2x=1x=-1/2

It is tested that x=-1 2 is the solution of the original fractional equation.

Solve the equation first. There seems to be a problem with this problem, and in the end it is simplified to: 1=0, which has nothing to do with m, and the formula does not hold.

Don't write the multiplication sign and x together, your x is too much like the multiplication sign, if you understand correctly, it's a cubic equation, you haven't learned to solve the formula, what should be investigated is factorization.