There are too many formulas, are they all complete?

Physics formulas are perfectly understandable and memorized, and in doing problems, go deep into these formulas and concepts into your brain, and don't memorize them.

The equations of chemistry are obtained by experiments, and the design experiment questions in the college entrance examination are also ** for them, so it is recommended that you do not blindly memorize the equations when you usually memorize chemistry, but remember its experimental steps.

Mathematical formulas are rarely memorized, are they? Of course, it's not worth taking this book, they are important teachers to explain the questions, pay attention to summing up experience, and don't fall into the tactics of the sea of questions.

The modern essay of the Chinese exam is almost the same The analysis method is the same The teacher's analysis and comment on this article is very important for you Classical Chinese How much to read The meaning of commonly used words must be understood Translation is not a problem.

Of course, it is important to arrange your time wisely in high school.

Finally, I wish you all the best in your studies and progress.

The new curriculum was changed immediately, and learning was not so easy.

In short, many formulas are a problem that every student has.

But your land will adjust.

The formulas are all connected.

So remember the main formula.

Some of the bits and pieces can be rolled out.

Remember some more commonly used ones.

It would be nice to push it out at the time of the exam if it is not commonly used.

As for the learning methods in those subjects, we can communicate.

I was also about to ask you if chemistry is difficult on the nine?

Number of copies per copy of the total.

Total Number of copies per copy.

Total number of copies per copy.

2 1 multiples multiples several multiples.

Multiples of 1 multiple.

Multiples Multiples 1 multiple.

3 Speed Time Distance.

Distance, speed, time.

Distance, time, speed.

4 Unit Price, Quantity, Total Price.

Total Price, Unit Price, Quantity.

Total price, quantity, unit price.

5 Work efficiency Working hours Total amount of work.

Total amount of work, work efficiency, working hours.

Total work, working hours, work efficiency.

6 Addition Addition and.

and one plus and the other plus.

7 subtracted subtracted difference.

Subtracted Difference Subtracted.

The difference subtracted by the subtracted number.

8 Factor Factor Product.

The product of one factor is another factor.

9 Dividends Divisor quotient.

The dividend quotient divisor elementary math graph calculation formula.

1 square.

c perimeter s area a side length.

Circumference Side length 4

c = 4a area = side length side length.

s=a a2 cube.

v: volume a: edge length.

Surface area = edge length Ridge length 6

S table = a a 6

Volume = edge length edge length edge length.

v=a×a×a

3 rectangles.

c perimeter s area a side length.

Circumference = (length + width) 2

c=2(a+b)

Area = length and width.

s=ab 4 cuboid.

v: volume s: area a: length b: width h: height 1) surface area (length and width + height + width and height) 2

s=2(ab+ah+bh)

2) Volume = length, width and height.

v=abh5 triangle.

S area A bottom H height.

Area = base height 2

s=ah÷2

Triangle height = area 2 bases.

Triangular base = area 2 high.

6 Parallelogram.

S area A bottom H height.

Area = base height.

s=ah 7 trapezoidal.

S area: A, upper bottom, b, lower bottom, H high.

Area = (top bottom + bottom bottom) height 2

s=(a+b)× h÷2

8 Circle s area c perimeter d = diameter r = radius 1) perimeter = diameter = 2 radius.

c=∏d=2∏r

2) Area = Radius Radius

9 Cylinders.

V: Volume h: High S; Base area r: bottom radius c: bottom perimeter 1) side area = bottom perimeter height.

2) Surface area = side area + bottom area 2

3) Volume = base area high.

4) Volume side area 2 radius.

10 cones.

V: Volume h: High S; Base area r: Bottom radius volume = base area height 3

The quotient divisor is the dividend.

In 10 seconds, the team walked 10 meters, and the correspondent walked a total of 25 meters in 10 seconds, deducting the 10 meters that the team walked forward, the communicator walked backwards and returned to the leader. That is, the communicator walks backward = 3 seconds to reach the end of the line, at which point the team has walked forward 3 * 1 = 3 meters, so the length of the line is 3 + = meters long.