Seek the first round of review materials for science and mathematics

This You can order a copy of Wang Houxiong's "Complete Interpretation of the College Entrance Examination" This is a skill, if you solve the problem, you can subscribe to Tianli's "Test Question Research", I just graduated from high school, these two books are very suitable for students like you, I hope it will help you, hehe.

Big brother: To tell you the truth, I can understand your feelings, that's how I came here.

You have to fumble and explore the math yourself, how can you say it now.

Personally, I think it's better to go to the bookstore and find some books to do. You can look at one or two example questions, the main thing is to do more and endure some hardship.

Let's summarize after accumulating a large number of topics.

In other words, it's not the third year of high school, and some topics are not suitable for you. Some of the testimonials may be rubbish.

Again. You won't have much time for summer vacation.

Do more to focus on weaknesses.

Function? Triangle? Sequence?

**Weakest to do**.

Don't rush, take your time. When I got to the back, I worked hard to do a set of questions, looked at the steps of the solution, and carefully reflected on my own ** detour in solving the problem.

I don't want you to share it, so I'll talk about it.

En test question research" can.

The king doesn't want anything, it's a little difficult, and it's a lot, and it's a headache to watch.

Personally, I don't recommend Wang Houxiong, I have watched it for three years, except for finding answers to after-school questions, there is no other benefit. I have used the first document of the college entrance examination and think it is okay.

Mathematics is a study of many examples, and the methods and techniques for solving each problem are introduced and detailed, and generally speaking, they can be understood, and they may not be good.

Study more of Nantong's joint examination papers and find them on the college entrance examination website.

1, the original formula = x Minghu in6x = 4in12-in6

2, the original formula y =-1 x .y =-2 Song Huai Bo x Ye Xiang.

(1) There are no solid roots, or there are two overlapping solid roots. It can be seen that delta < = 0, so 1-4m < = 0, i.e., m>=1 4

2) If the parabola (mx 2+x+1) opens downward, then the value range cannot reach positive infinity, so m>=0, and the lower bound of the value range is 0, so there is a real root, and the condition with a real root is delta>=0, we can know m<=1 4, and the comprehensive knowledge is 0<=m<=1 4

The domain condition is defined as: mx 2+x+1>=0;

1) When m=0:

x+1>=0

x>-1;It does not meet the conditions of the problem x r and therefore does not hold: (2) when m<0;

f=mx 2+x+1 must have a part below the y-axis, so x cannot be completely taken r(3) when m>0;

As long as f=mx 2+x+1 is above the y-axis, i.e., the discriminant formula (b 2-4ac) < = 0

1-4m<=0

i.e. m>=1 4

Therefore m>=1 4

The value range is required to be [0, infinite), that is, the value range converted to f=mx 2+x+1 must include [0, infinity) can be more or less.

1) When m=0:

f=x+1 on x r the range includes [0, infinity).

Therefore, (2) when m<0.

f=mx 2+x+1 must have a maximum, i.e., the range cannot include [0,infinity) (3) when m>0.

As long as the quadratic function and the x-axis intersect, that is, the discriminant formula (b 2-4ac) >=01-4m>=0

m<=1/4

Combine m>0

Therefore, 0 is summed up, 0=

（1）g(x)=√(mx^2+x+1)

g(x) is defined in the domain r, so {m>0

1-4m≤0

>{m>0

m 1 4 so, m 1 4