The charging process of physical capacitors is a problem, and what is the process of charging and di

The power supply is to carry the charge through the electric field force (the positive one moves to the negative pole, and the negative one moves to the positive pole), so that the potential difference between the two ends of the power supply is formed, which causes the electrons (wires) in the conductor to move directionally under the action of the electrostatic force to form a current, and the ability of the power supply to carry the charge, that is, the electromotive force, is numerically equal to the power supply voltage, which is why the voltage at both ends of the capacitor is equal to the two ends of the power supply, because the power supply has such a large ability, it will not exceed, and if it is insufficient, it will be made up, and the resistance of the wire is considered to be zero. The resistance is not shared, and the internal resistance is not considered. Therefore, the two ends of the capacitor are equipotential with the two ends of the power supply, and the voltage is equal ( In fact, when we measure the voltage at both ends of the capacitor, isn't it equivalent to using a voltmeter to re-measure the power supply voltage, and the measured value should be approximately equal to the power supply voltage. In fact, the voltage at both ends of the capacitor should be slightly less than the power supply voltage, which should be the presence of internal resistance!

Because there is a potential difference between the two plates after the connection is turned on, that is, the electromagnetic environment there has changed.

Then since the environment has changed, the free charge will move according to the change in the environment.

The movement of the free charge will produce a change to resist the original electric field.

Therefore, when the resistance electric field of the charge is balanced with the originally applied electric field, the electric field force received by the charge is balanced, and the charge is not in motion, but balanced.

Without voltage difference, there would be no current.

Charging stops.

If it is not equal, it will continue to charge, and only when the potential at both ends is equal, the electrons will not move anymore.

The first thing you have to understand is that you can't absorb electricity in a vacuum.

There is a source to charge it, and the capacitor can be charged.

When the two boards of the capacitor are connected to the positive and negative stages of the power supply, the power supply will charge the capacitor until the potential is equal to the power supply.

The microscopic process can be seen as the transfer of electrons from the positive plate to the negative plate through the power supply.

Charging and discharging are the basic functions of capacitors.

Charging The process of making a capacitor charged (storing charge and energy) is called charging. At this time, the two plates of the capacitor are always positively charged on one plate and the other plate on the other plate with the same amount of negative charge. If one plate of the capacitor is connected to the positive pole of the power supply (such as a battery pack), and the other plate is connected to the negative pole of the power supply, the two plates will each carry the same amount of dissimilar charge.

After charging, there is an electric field between the two plates of the capacitor, and the electrical energy obtained from the power supply is stored in the capacitor during the charging process.

Discharge The process of causing a charged capacitor to lose its charge (release charge and energy) is called discharge. For example, if you connect the two poles of a capacitor with a wire, the charges on the two poles will neutralize each other, and the capacitor will release charge and energy. After discharge, the electric field between the two plates of the capacitor disappears, and the electrical energy is converted into other forms of energy.

In general electronic circuits, capacitors are commonly used to achieve bypass, coupling, filtering, oscillation, phase shift, and waveform transformation, which are the evolution of their charging and discharging functions.

Charging and discharging are the basic functions of capacitors.

The process of charging to electrify the capacitor is called charging. At this time, the two poles of the capacitor are always one plate with a positive charge, and the other plate with the same amount of negative electricity. If one plate of the capacitor is connected to the positive pole of the power supply, and the other plate is connected to the negative pole of the power supply, the two plates will each carry the same amount of dissimilar charge.

After charging, there is an electric field between the two plates of the capacitor, and the electrical energy obtained from the power supply is stored in the capacitor collision during the charging process.

The process by which a discharged capacitor loses its charge is known as discharge.

1.The question about electricity can be compared to a row of seats. When the seat is full, it can be seen that both the person and the seat are not moving.

When one person at the front is absent, there is an empty seat. At this point, the person in the second seat moves to the first seat, and the second seat becomes the second empty seat. In the same way, the people behind them all move to the empty seats in front of them in turn.

As a result, all the seats were moved to the front, but in fact, the empty seats were moved to the last position in the opposite direction of the person movement. The electric current is also moving with a negative charge (electron), but when it loses an electron, it has a positive charge, so it can also be seen as a positive charge moving. However, the direction of movement of the positive charge and the negative charge is opposite, so that the direction of the current is uncertain, and in order to determine the direction of the current uniformly, it is specified that the direction of the positive charge is the direction of the current.

When an uncharged capacitor is connected to a power supply, the positive and negative charges flow from the positive and negative poles of the power supply to the capacitor plates under the action of voltage. We call the two plates of a capacitor that stores positive and negative charges a positive plate and a negative plate, respectively.

2.When an uncharged capacitor is connected to a power supply, the positive and negative charges flow from the positive and negative poles of the power supply to the capacitor plates under the action of voltage. This is the moment when the power supply is turned on, the maximum current is the moment, as the charge accumulated by the two plates of the capacitor increases, the potential of the two plates is gradually close to the positive and negative potential of the power supply, and the current flowing to the capacitor becomes smaller, when the potential of the two plates is equal to the positive and negative potential of the power supply, the current flowing to the capacitor is gone.

So there's what you said about charging, and the circuit just has an instantaneous current.

3.When the potential of the two plates of the capacitor is equal to the positive and negative potentials of the power supply, the number of positive and negative charges accumulated on the positive and negative plates of the capacitor is equal, so the two electrode plates carry the same amount of dissimilar charges after charging.

The voltage gradually rises during the charging process, so I won't talk about the formulaic, but let's talk about the image.

What is the increase in charge here? It's the charge moving, isn't the charge moving the current?

Current vs. capacitance, voltage is the accumulation of charge, that is, voltage is the integral of current, so what is the current?

If you were that capacitor, what would you do?

Does it look at how tight the urging is, here is how much is the voltage difference (four tones)?

The question of how much voltage difference is, when in non-ideal conditions (the power supply has internal resistance, the charging path has resistance, and the charging current cannot be infinite), it becomes a question of how much current there is. How big the current is, that is, how fast it is charged.

However, this repeated to the previous question mark forms a recursive problem, that is, the charging current determines the capacitance voltage, and the voltage determines the current. But in this seemingly paradoxical relationship, in fact, time is gone. Therefore, when a circuit parameter is determined, its voltage and current relationship is also determined.

In this way, voltage and current can be understood in relation to the power of the natural base of the capacitor voltage function, which is "itself is its own derivative".

To put it simply, since charging is said to be a "process", it is not charged in an instant. The first sentence in the question, "During the charging process of the capacitor, the capacitor remains connected to the power supply, and the voltage between the boards does not change" here does not mean that the voltage does not change between the boards, but that the power supply voltage does not change. If the power supply has no internal resistance and the current can be infinite, then it can be charged in an instant, let alone talk about the "process", but there is no such situation.

But it's important to emphasize here that when we talk about the process of starting charging to a fully charged steady state, the capacitor cannot be used as an open circuit, because it is charged, and there is a current flowing through it. The function of this current flowing through the tangled with a natural base, the characteristic of the capacitor itself, the capacitance, and the external factor of the current limiting resistance, together determine the change in voltage (i.e., the relationship with respect to time).

Hope it helps.

First of all, you didn't say the voltage of the charged capacity, the charging voltage and current will have a certain impact on the capacitor, the light is broken, the heavy is **! (The above is not recommended for testing, and the consequences of ** in the test have nothing to do with me!) ）

There is an electric current in the circuit, which is the charging current.

During the charging process of the capacitor, there is an electric current passing through the circuit, and the voltage at both ends of the capacitor is zero at the beginning of charging. With the increase of time, the charge of the capacitor continues to increase, and the voltage at both ends of the capacitor also increases, which is the principle that the voltage at both ends of the capacitor cannot be abruptly changed, so that the current in the circuit continues to decrease, and when the current tends to zero, the capacitor is fully charged.

Charging current in the circuit i = (supply voltage - voltage across the capacitor) resistance in the circuit.

From the above equation, it can be seen that the current is maximum at the beginning of capacitor charging, and the charging current decreases as the voltage at both ends of the capacitor increases with the increase of charging time.

Capacitor charging time constant = rc, capacitor charging and discharging time is basically over when 3 5 time constants.

During the charging of the capacitor, the charging current is gradual, and the energy is converted into a strong omen.

Correct Answer: Decrease; Electricity; Knowing the dry electric field.

Hello, the reason why the pro-capacitor is charged after discharging in the circuit: this is related to the characteristics of the voltage at both ends of the capacitor can not be abruptly proportional, when the voltage at both ends of the capacitor is added, it is impossible to abruptly compare, so it still maintains the original value, with the passage of time, the voltage at both ends of the capacitor is gradually increasing, which is the process of charging. When the load is connected to the load at both ends of the capacitor, the voltage does not change suddenly, and the voltage at both ends of the capacitor gradually decreases over time, which is the discharge process.

To charge a high-voltage and large-capacity electrolytic capacitor, it is necessary to limit the current first and then rectify, otherwise it will cause a strong current impact on the rectifier bridge and easily damage the rectifier bridge.

Between the AC circuit and the rectifier bridge, it is necessary to connect at least a few ohms of current limiting resistor, the power is about 10W, and then connect the rectifier bridge, so that the rectifier bridge with 15-25A and withstand voltage of 400-600V can meet the needs.

Assuming that the current limiting resistor is not connected in series, the capacitor is equivalent to a short circuit at the moment of charging, and the 220V alternating current is directly added to the rectifier bridge, and the powerful current instantaneous peak can reach thousands of amperes, and the rectifier bridge is burned immediately.

If the current limiting resistor of a few ohms is connected in series, such as 5 ohms, the instantaneous peak maximum current is only 220 5=44A, and the instantaneous peak current that the 15A rectifier bridge can withstand can reach 15*10=150A, which is a safe value; If a 25A rectifier bridge is used, the instantaneous peak current that can withstand can reach 25*10=250A, which is safer.

The current-limiting resistor only acts instantaneously, and when the capacitor is fully charged, the resistor has almost no power dissipation, which is equivalent to a length of wire.

Hope it helps.