The ratio of yield per unit area of the two crops is 1 1 5, and it is now 140 meters long and 80 met

You can divide it however you want, as long as you make sure that the two plots of land are the same size.

If crop A is planted x square meters, and crop B is planted by y square meters, then x+y = 200 100 (1).

1x：：4 （2）

The angular simultaneous equation is obtained by (2), 4x=, x=, substituted by (1), 17y=160000, y=9412 9400 (square meters), x 20000 9400=10600 (square meters).

10600 100 = 106 (m), the rectangle of planting a crop is: 106 m long and 100 m wide;

9400 100 = 94 (m), the rectangle of planting crop B is: 100 m long and 94 m wide.

If the length of the land planted by crop A is x, then the width of the land planted by crop B is (100 x), and the area of the two crops is 20x, respectively

20 (100 x) The yield ratio of two crops is 20x*1:20(100x)*, so 20x:20(100x) 3:4

x is approximately equal to 43

I just calculated that if it were rectangular, it would be basically impossible to implement it according to the method of "Jianchen", but he miscalculated.

Set A Imperial Shelter x m 2 B y m 2

x+y= 200*100

x/( =3/4

x/y = 9/8

The solution is x= 180000 17 y=160000 17 (this can be omitted).

1) If the width of the long cut remains the same, the ratio of the long cut is 9 8

i.e. 200*9 17 = 1800 17= 106 on one side 100 on the other side

B 200*8 17 = 1600 17 = 94 100 on one side

2) If the length of the wide cut remains the same, the ratio of the wide pants is 9 8

i.e. 100*9 17 = 900 17= 53 on one side 200 on one side

B 100*8 17 = 800 17 = 47 200 on the other side

Let A x m 2 B y m 2

x+y= 200*100

x/( = 3/4

x/y = 9/8

The solution is x= 180000 17 y=160000 17 (this can be omitted).

1) If the width of the long cut remains the same, the ratio of the long cut is 9 8

i.e. 200*9 17 = 1800 17= 106 on one side 100 on the other side

B 200*8 17 = 1600 17 = 94 100 on the other side

2) If the length of the wide cut remains unchanged, the width cut ratio is 9 8

i.e. 100*9 17 = 900 17= 53 on one side 200 on one side

B 100*8 17 = 800 17 = 47 200 on the other side

Solution: Let the area of A be x and the area of B be y

x+y=20×100

x:2y=3:4 [Note: These two formulas are in one curly bracket].

Result: 4x-6y=0

6: 6x+6y=120000

Get: 10x=120000

x=12000

Substitute x=12000 into :

12000+y=20000

y=8000

So the solution of this system of equations is:

x=12000

y=8000

Note: This finds the area].

12000 100 = 120 [Note: This uses the area width = length] Answer: The long side of the rectangular land is about 120m away from one end, make the perpendicular line of this side, and divide the land into two rectangles, the larger piece of land is planted with crop A, and the smaller piece of land is planted with crop B.

If crop A is planted x square meters, and crop B is planted by y square meters, then x+y = 200 100 (1).

1x：：4 （2）

The angular simultaneous equation is obtained by (2), 4x=, x=, substituted by (1), 17y=160000, y=9412 9400 (square meters), x 20000 9400=10600 (square meters).

10600 100 = 106 (m), the rectangle of planting a crop is: 106 m long and 100 m wide;

9400 100 = 94 (m), the rectangle of planting crop B is: 100 m long and 94 m wide.

x+y=200(1) Area A = 100x, area B = 100y, the ratio of the total yield of crops A and B = 100x * unit yield of A 100y unit yield of B = 100x 100y * (1:2) = 3:4q to obtain y=80, x = 120

Let ae be an edge of length 200.

Then x y 200

The ratio of the total yield of the two crops A and B is 3:4

100 1 x) :(100 2 y) 3:4 is equivalent to: 2x 3y

Solution: x 120

y＝80

Site area = 200 * 100 = 20,000 square meters.

Set the area of A x square meters, and the area of B is 20,000-x square meters.

x：：4x≈10588

A is 10,588 square meters, and B is 9,412 square meters.

Let ae be an edge of length 200.

Then x y 200

The ratio of the total yield of the two crops A and B is 3:4

100×1×x）：（100×：4

Equivalent to: 8x 9y

Solution: x

y is an integer: x=106, y=94

A is 10,588 square meters, and B is 9,412 square meters.

Let ae be an edge of length 200.

Then x y 200

The ratio of the total yield of the two crops A and B is 3:4

100×1×x）：（100×：4

Equivalent to: 8x 9y

Let ae be an edge of length 200.

Then x y 200

The ratio of the total yield of the two crops A and B is 3:4

100×1×x）：（100×：4

Equivalent to: 8x 9y

Solution: x y is an integer: x=106, y=94 Solution:

x y is an integer: x=106, y=94

Let the area of crop A be x and the area of crop B be y

x+y=100*200=20000

x*1)/(y*

x approx. = 106

Y = 94, i.e., 106 meters. Crop B gets 94 metres.

1 unit area is the output of the area in which the unit is one.

2 Total production = production per unit area x area.

Set the planting area of type A x square meters, the planting area of type B y square meters, x+y=200 100, ,1 x):(2 y)=3:4, and the solution is x=12000, y=8000, that is, 12000 square meters of planting of type A, and 8000 square meters of planting type B

Set up planting X square meters of crop A and Y square meters of planting B crops.

According to the title.

x+y=200×100

2x:y=3:4

Solve the system of equations.

x=8000 y=12000

Set A to plant x square meters, B to plant y square meters, x:2y=3:4, x+y=20000