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Answer: 1:2;1/2v0t0;4:1
Analysis: According to the momentum theorem, ft = mv, in the process of relative motion of a and b, their combined external forces are equal, and the ratio of the change in velocity is 2:1, so the ratio of mass is 1:
2;The minimum length of b is equal to the difference between the displacements of a and b in the process of relative motion, and the difference between the displacements of a and b is equal to the area of the triangle in the figure s=1 2v0t0; From the kinetic energy theorem, it can be seen that the work done by the resultant external force is equal to the amount of change in the kinetic energy of the object, and in this problem, the combined external force for a and b is equal to the frictional force, so the ratio of the work done by the frictional force is equal to the ratio of the change in the kinetic energy of the object, which is 4:1.
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1.Analysis: After the water is sprayed, it does a flat throwing motion.
Displacement decomposition: h= x=vot
t= vo= can be solved
Ejection volume per second v=vots = cubic meters.
2.After the parts fly out, they do a flat throwing motion.
Displacement decomposition: h= x=vot
t= vo= can be solved
So overspeeding.
4.Analysis: The horizontal motion of the object and the vertical motion of the object do not interfere with each other. The vertical direction is from the big silver to the falling body, and the water fights in the flat direction to accelerate the movement.
1) T time, vy=gt vx=at. where the horizontal direction is f=ma, a=f m.
So vy=gt,vx=ft m
2)x= ——
y=ratio:y=fx gm, the trajectory is a straight line.
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/(234/60)=
3. The T108 train stopped at Liaocheng Station at 9:28 and 9:36, so the instantaneous speed at 9:30 was 0
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It's high school, and it's a junior high school problem!
The key is to test your ability to know, understand, apply and convert time units of train timetables!
The known quantities required by this problem are all in the timetable, and the corresponding quantities are calculated by substituting the corresponding quantities into v=s t!
Specific as recommended, but there must be details of formulas and units!
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If you don't have a book, you don't know anything else, so let's do this one.
Let the mass of calcium carbonate required for the reaction be x, and the mass of calcium chloride shall be y
Find the carbon dioxide quality first:
The amount of substances of CO2 gas = =
The relative molecular mass of CO2 = 44
So the mass of CO2 gas = 44* = 22g
Chemical equation: CaCO3+2HC---CaCl2+CO2+H2O
x y 22
100/x=111/y=44/22
x=50g,y=
90% of calcium carbonate requirements are 50 90% =
The amount of calcium chloride substance is n=m m=
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Do you need an answer in the lab manual?
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According to the law of flat throwing motion,,, there is a formula to solve v0=, so the car is speeding.
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Analysis: When the block is thrown horizontally, the centripetal force is provided by gravity at the highest point on the belt, the critical velocity is calculated according to Newton's second law, and the minimum number of revolutions per second of the A wheel is found according to the relationship between the linear velocity and the rotational speed
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It should be the choice of C The tangent point of the object is the centripetal force provided by the gravity of the object at the tangent point that is about to leave the pulley, that is:
mg=mv2 r can be solved for the critical velocity for the answer c
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The centripetal force of the selected C object is mg, and the radius of circular motion is r
mg=rmv2
v = root number under gr
The force of the ox lifts the weight, according to the vector synthesis law, it should be 50n is the hypotenuse of the weight of 80n, the resultant force is the right-angled side, then the left and right ropes each contribute 50, gravity takes half of them, forming a triangle, at this time the hypotenuse is 50n, the gravity is 40n (half of 80), so that the rope is 1m long, and each side of the left and right hands is only calculated from the lowest point The height difference in the direction of gravity is the horizontal distance. So the distance between the hands. >>>More
Diagonally pushed up. Resultant force fcosa- (mg-fsina) frictional force f= (mg-fsina). >>>More
1. Placed on a horizontal tabletop weighing 100N, when subjected to a 22N horizontal force, it just starts to move - this sentence tells us that the maximum static friction force (that is, the minimum horizontal force that can make the object change from rest to motion) is 22N; >>>More
1.An object moves in a straight line at a uniform variable speed The magnitude of the velocity at a certain moment is 4m s and the velocity becomes 10m s after moving 12m, and the object is in this distance. >>>More
This problem can be done as follows: let the radius of the earth be r, the rotation of the earth is t, and the mass is m, then the period of the near-earth satellite is t n, so t 2 = 4 ( n) 2r 3 gm, let the radius of the geostationary satellite be r then t 2 = 4 2r 3 gm, the two are connected together, you can get, r = n 2r, then the height above the ground is (n 2-1) times the radius of the earth.