What are the answers to the puzzle questions Do you know?

Question 1: The answers are 1 and 7.

Question 2: The answer is "turn around and chase after yourself, and ask another policeman to turn around and chase after you as well".

Only 1 and 7 (absolutely correct, copied from the book).

Analysis Because B first says that he knows, it means that B can determine a unique set of numbers through this product, and A later says that he knows, which means that A can also determine a unique set of numbers through the information provided by B and the sum of the two numbers.

Let's look at the product first If it is 1 and 4, the product is 4, which can be broken down into 1*4, 2*2, and is not the only group.

If it is 1 and 7, then the product of 7 is a prime number that can be decomposed into 1*7 and is the only group.

If it is 4 and 7, the product is 28, which can be broken down into, 4*7, 2*14, 1*28, not the only group.

If it is 1 and 17, the product of 17 is a prime number that can be decomposed into 1*17 and is the only group.

If it is 4 and 17, the product is 68, which can be broken down into 2*34 (not eligible), and 4*17, which is the only group.

If it is 7 and 14, the product is 98, which can be broken down into 49*2 (not eligible), and 7*14, which is the only group.

From this, 1 and 7, 1 and 17, 4 and 17, 7 and 14 are screened out

Looking at the sum of two numbers.

If it is 1 and 7, then the sum is 8, which can be decomposed into, 1+7, 2+6, 3+5, 4+4

1. If the decomposition is 2+6, the product is 12, and the only set of numbers cannot be determined to multiply.

2. If the decomposition is 3+5, the product is 15, and the only set of numbers cannot be determined to multiply.

3. If the decomposition is 4+4, the product is 16, and the only set of numbers cannot be determined to multiply.

4. If the decomposition is 1+7, the product is 7, which can determine the multiplication of a unique set of numbers.

Hence 1 and 7 hold.

If it is 1 and 17, then the sum is 18, which can be broken down into 1+17, 2+16, 3+15....9+9

Among them, if the decomposition is 1+17, the product is 17, which can determine the multiplication of a unique set of numbers.

If the decomposition is 5+13, the product is 65, which determines the multiplication of a unique set of numbers.

This allows at least two sets of solutions to be eligible.

Therefore 1 and 17 do not hold.

If it is 4 and 17, the sum is 21

where If it is decomposed to 2+19, the product is 38, which determines the multiplication of a unique set of numbers.

If the decomposition is 4+17, the product is 68, which determines the multiplication of a unique set of numbers.

This allows at least two sets of solutions to be eligible.

Therefore 4 and 17 do not hold.

If it is 7 and 14, the sum is 21

where If it is decomposed to 2+19, the product is 38, which determines the multiplication of a unique set of numbers.

If the decomposition is 4+17, the product is 68, which determines the multiplication of a unique set of numbers.

This allows at least two sets of solutions to be eligible.

Therefore 4 and 17 do not hold.

Overall, only 1 and 7 are eligible.

27+2, it doesn't mean anything, these two numbers can't be added together at all. The reason is very simple, what is 27, is the sum of 2 yuan of 25 yuan of the actual room fee of the trip and the waiter. It already contains 2, and adding 2 doesn't make sense.

Correct calculation: the actual room fee is 25 yuan, and the waiter hides 2 yuan, which is a total of 27 yuan; "The remaining 3 yuan was distributed to the three people, and each person received 1 yuan", 27 + 3 = 30, which is the money paid by the first three people. In this way, there is no contradiction

This topic is from "3 x 9 = 27 yuan + 2 yuan = 29 yuan hidden by the waiter" to guide you to drill the tip of the horns, if you think from this aspect, you will not get the answer to the stool person out of 10 yuan, and then return 1 yuan per person, that is, 9 yuan per person, 9 yuan x 3 = 27 yuan The boss said, 25 yuan is enough, so the extra 2 yuan is just right, this 2 yuan is "secretly hidden" by the waiter, so 25 + 2 = 27 + 3 = 30, no more, no less.

9 times 3 equals 2725+2 equals 27 That's not wrong at all!!

A complete set of puzzle questions and answers.

Khan First of all, I agree with the upstairs. Don't look at it now"And a dollar to go to**? "This sentence.

10-1=9 is no problem, 3x9=27 yuan is no problem. But do you see it clearly? They gave a total of 30 yuan.

But the discount is 5 yuan. The waiter was greedy for 2 yuan. 30-27 = 3 yuan.

The 3 yuan is the money that the three of them got after the waiter was greedy for money. In other words, there is no need to give 3 yuan now. $27 is the money now.

However, is there still 2 yuan from the waiter who did not give these three people 2 yuan in the 27 yuan? .Other words. If the waiter's 2 yuan is given, it will only cost 25 yuan.

Therefore, 27-2 = 25 yuan, which is exactly the 25 yuan to be given. 27 yuan = the money after the discount + the waiter's money. If you use 27 + 2 yuan.

Isn't it just a repeat of the waiter's 2 yuan again? Therefore, 27+2 yuan is wrong, there is not a single yuan left. Hey, hey, isn't it?

Waiter angle: 30 = 25 + 5 = 25 + 2 + 3

Traveler's angle: 30 = 10 + 10 + 10 = 3 * (9 + 1) 3 * 9 = 27 is not the same concept as 2, the 2 is 27 inside, hardpull to 29, it is double counting, ≠of course, 30!

This includes the concepts of double counting, intersection, and collection!

The 27 yuan spent by three people = 25 yuan in the hands of the boss + 2 yuan in the hands of the waiter, the formula in the question does not exist! is the wrong equation.

Now the money situation is 25 yuan in the boss's hand, 2 yuan in the waiter's hand, 1 yuan for each of the three people, and exactly 30 yuan together.

Not a single dollar at all. The three of them all got one yuan in the end, which was three yuan, plus the two yuan of the second child and the twenty-five yuan for the accommodation fee, a total of thirty yuan.