The elder brother is 25 years old, the younger brother is 5 years younger than the elder brother, an

The younger brother is 5 years younger than the older brother and will always be 5 years younger. So when the elder brother is 47 years old, the younger brother is 42 years old.

The elder brother is 25 years old this year, and the younger brother is five years younger than the elder brother, but when the elder brother is 47 years old, the younger brother should be 47-5 = 42 years old.

Hello! You say your brother is 25 years old. The younger brother is five years younger than the older brother. He was 20 years old. My brother is 47 years old. My brother should be 42 years old.

Hello, my brother is 5 years younger than my brother, my brother is 47 years old, my brother is 47 years old, minus 5 years old, equals 42 years old, I hope mine can help you and oh thank you!

The age difference between the elder brother and the younger brother will not change, and the difference will always be five years, so when the elder brother is 47 years old, the younger brother is 42 years old.

He is 25 years old this year, his younger brother is five years younger than his brother, and his brother, how old is his younger brother when he is 47 years old? The elder brother, when he was 47 years old, the younger brother was 42 years old, because he was five years younger than her, so he was always five years younger.

The younger brother is always 5 years younger than the older brother, the older brother is 47 years old, and the younger brother is 42 years old.

It doesn't matter how old you are, it's a matter of logical thinking.

The problem of the age difference between the older brother and the younger brother does not change with age, so it is 42

Male, when his elder brother was 47 years old, his younger brother was only five years younger than his older brother. Then his younger brother is 42 years old.

I think my brother is 25 years old this year, and then the younger brother is five years younger than the elder brother and the clam is four years old, the younger brother should be 27

The younger brother, who is 25-5 this year, is equal to 20 years old.

The younger brother is 14-6 = 8 years old, 14 + 8 = 22 years old, 44-22 = 22, 22 2 = 11 years, so the sum of their ages after 11 years is 44 years old, when the elder brother is 14 + 11 = 25 years old, and the younger brother is 8 + 11 = 19 years old, hopefully, thank you.

The elder brother is 14 years old, and the younger brother is six years older, then the younger brother is 14-6 = 8 years old, and this year's elder brother plus the younger brother's age is equal to 14 + 8 = 22 years old, (44-22) 2 = 11, then the younger brother's age: 11 + 8 = 19 years old, and the elder brother's age: 14 + 11 = 25 years old.

The elder brother is 14 years old this year, 6 years older than the younger brother, then the younger brother is 8 years old, assuming that after x years, the sum of the ages of the elder brother and the younger brother is 44 years old, and the elder brother is 14 + x years old at that time, and the younger brother is 8 x years old, then.

14+x）+（8+x） =44

22+2x =44

2x = 22

x = 11

In another 11 years, the sum of the elder brother and younger brother was 44, when the elder brother was 25 years old and the younger brother was 19 years old.

is six years older than his younger brother, and his younger brother is 8 years old this year, and the total number of the two is 22 years old, so 44 years old is a difference of 22, that is, eleven years later, that is, 25 and 19 years old.

In the near future, it is still possible to contact everyone specifically to have the actual situation, or to look at the choice of mobile phone. yes, it's still a good chat.

Summary. Dear, the sum of the ages of the elder brother and the younger brother is 55 years old, and in 10 years, the elder brother is 5 years older than the younger brother, and the elder brother is now 25 years old. We can solve this problem with algebraic equations.

If the elder brother is x years old, then the younger brother is 55 - x years old. According to the conditions in the problem, after 10 years, the elder brother is 5 years older than the younger brother, and the equation can be listed: (x + 10) -55 - x + 10) = 5 to simplify the equation to get :

x + 10 - 55 + x - 10 = 5 Combine similar terms to get: 2x - 45 = 5 Shift terms to get: 2x = 5 + 452x = 50 to solve the equation to get:

x = 50 2x = 25, so my brother is now 25 years old.

The sum of the ages of the elder brother and the younger brother is 55 years old, and in 10 years, the elder brother is 5 years older than the younger brother, and how old is the elder brother now.

Accompanied by relatives and friends, the sum of the ages of my brother and my brother is 55 years old, and 10 years later, my brother is 5 years older than my brother, and my brother is now 25 years old. We can solve this problem with algebraic equations. If the elder brother is x years old, then the younger brother is 55 - x years old.

According to the conditions in the problem, after 10 years, the elder brother is 5 years older than the younger brother, you can list the equation: (x + 10) -55 - x + 10) = 5 Simplification of the equation to get the edge: x + 10 - 55 + x - 10 = 5 Combine similar terms to get :

2x - 45 = 5 Shift gets: 2x = 5 + 452x = 50 Solve the equation to get: x = 50 2x = 25 So my brother is now 25 years old.

Dear, I just miscalculated 10 years later, my brother is 5 years older than my brother, my brother is growing up, and my brother is also growing up, so the difference between my brother and my younger brother is 5 years, and their age sum is 55, and the bridge is 55-5=50,50 and then divide by 2=25,25+5=30, so my brother is now 30 years old, and my brother is 25 years old.

I'm 5 years old. I'm 15 years old. My brother and brother are not liquid after 7 years, how old is my brother older than my brother? Related knowledge points: Analysis Additional questions 15-5=10 (years).

12 years old. 1. Let the elder brother's age be y, the younger brother's age be x, the elder brother is 3 years older than the younger brother is equal to y-x=3, and their age sum is 27 years old is equal to x+y=27.

2. The solution y-x=3, y=3+x, x+y=27 is replaced by x+3+x=27, and 2x=37-3 can be obtained, and finally x=12 is obtained, and the younger brother is 12 years old according to the sum and difference formula. Qingqin.

The elder brother is five years older than the younger brother, and this year their age is 13 years old. You can use 13-5 to equal eight 8 2 to four, that is, four dd, 4 years old, and my brother is nine years old. It can also be xd d is x c, then the elder brother is x plus 5c, and then add up the age of the younger brother and the elder brother to equal 13, so that x is equal to 4

If the younger brother is x years old this year, then the elder brother is x ten 5 years old this year, ten 5 ten x two 13, x two 4 years old, 4 ten 5 two 9 years old, so the elder brother is 9 years old this year, and the younger brother is four years old this year.

The elder brother is 9 years old and the younger brother is 4 years old. They are exactly 13 years old. The elder brother is also exactly 5 years older than this younger brother.

Younger brother's age (13-5) 2=8 2=4 (years).

Elder brother's age 4 + 5 = 9 (years).

Younger brother's age = (13-5) 2 = 4 years.

Elder brother's age = 4 + 5 = 9 years old.

The elder brother is 9 years old and the younger brother is 4 years old.

From this question, we can know that the elder brother is four times older than the younger brother. There is also an older brother and a younger brother who are 25 years old together. We can know that the age of the five younger brothers is 25 years old.

The age of the younger brother is 25 5 to 5, and the younger brother is five years old, so the elder brother is four times that of the younger brother. Then the elder brother is 4 5. My brother's age is 20 years old.

My brother is 20 years old, 25 5 = 20

5 4 = 20 So my brother is 20 years old this year.

25 (4 x1).

5 (years) 5x4 = 20 (years).

A: My brother is 20 years old.

The younger brother is four years younger than the elder brother, and five years ago the sum of the ages of the two brothers was 24 years old, so one is, one is eight years old, and the other is 14 years old.

Brother, the younger brother is four years younger than the elder brother, and the two brothers were 20 years old five years ago, and they are all brothers.

Brother 5 years ago: (24-4) 2=10 years old.

Older brother: 10 + 4 = 14 years old.

Now brother: 10 + 5 = 15 years old.

Brother: 14 + 5 = 19 years old.

Five years ago, my younger brother was 10 years old and my older brother was 14 years old. Five years later, the younger brother was 15 and the elder brother was 19.

My brother is 19 years old this year, my brother is 15 years old, and my brother was 14 years old five years ago. The younger brother is l0 years old.

The younger brother is 14 and a half years old, and the elder brother is 19 and a half years old.

My brother is 19 years old this year, and my younger brother is 15 years old.

Suppose that five years ago the younger brother was x years old, then the elder brother was x ten 4 years old, and the sum of the ages of the two was x ten ten 4 = 24, so that x = 10 years old, x ten 4 = 14 years old, then five years later today the younger brother is 10 ten 5 = 15 years old, and the elder brother is 14 + 5 = 19 years old.