Math problems. To methods and formulas,. Don t have an answer

Xiaoli A2 and B2 total score: 32, then 2 (A + B) = 32, get A + B = 16, which means that if you vote one in each of the A and B districts, the total score is 16, and Xiao Min just votes one in each of the two districts, so Xiao Min's total score is 16

This problem does not require complex calculations, it only needs to be analyzed, and the results are out.

Solution: Let the distinguishing values of a and b be x and y., respectively

Then 3x+y=34, 2x+2y=32, the solution is x=9, y=7, so the total score of Xiaomin A1 and B1 is x+y=16 points.

Wishing you happiness and joy!

Set up area A, X, B, and Y.

3x+y=34① 2x+2y=32②

6x+2y=68 is obtained

Substituting yields 4x=36 x=9 y=7

Xiaomin=x+y=16

Solution: high A area x points, B area Y points, then.

3x+1y＝34

2x+2y＝32

Multiply by 2 minus to obtain.

4x 36, x 9, nesting formula to get y 7

So the total score of Xiaomin is 9 x 1 + 7 x 1 = 16

Set up an X score for Zone A and a Y score for Zone B.

2x+2y=32

x+y=16

So Xiao Min 16 points.

1.[square meters) (taken, for 1256 square meters).

square meters).

.(1) Vega's speed is 14 kilometers per second, which is equivalent to 7 13 of the Cowherd Star, how many kilometers does the Cowherd Star travel at a second?

14 7 13 26 (km/s).

2) Vega's speed is 14 kilometers per second, which is equivalent to 6 13 of the Cowherd's speed, how many kilometers does the Cowherd star travel?

14 6 13 91 3 (km/s).

1.Set the distance to x km.

x/6 + x/4=5

10x=120

Question] Two cars A and B respectively travel opposite each other from cities A and B at different speeds, meet on the way, the meeting point is 60 kilometers away from city A, after the two cars continue to arrive at the destination at the original speed, they both return immediately, and meet for the second time on the way, the meeting place is 40 kilometers away from city A, how many kilometers are the two cities apart?

Re: A and B met twice. The first time they met, A and B walked a whole course, of which A walked 60 kilometers;

When A and B go through two more whole journeys when they meet for the second time, then they walk three whole journeys from the beginning to the second encounter, and A and B go through three whole journeys, then it can be seen that A is gone:

60 3 180 (km).

180 40) 2 110 (km).

3.Set the rabbit to sleep for x minutes on the way.

2000 25-x) 320 + 400 = 2000 solution x = 75 minutes.

1. Let A and B be separated by x kilometers, then x 4 + x 6 = 5, and the solution is x = 12

1 to speed x, then the return speed is 2 3x

x is 3, then the distance between the two places is 3*4=12

2"On the way, the two cars were at the 50 km math class in place A"Ambiguous 3 takes 2000 25 = 80 points.

Rabbit sleep x then 320 (80-x) = 2000-400x = 75

Equation method:

7 (7+9+12)=1 4=7 28 9 (7+9+12)=9 28 12 (7+9+12)=12 28 28 210 (7+9+12) of 28 The sum of the two books is 210.

7 28 + 9 28) - (9 28 - 7 28) = 1 2 The total number of books 210 (1 2) = 420

The number of books of type A is 420 * (1 4) = 105

The number of copies of type B is 420 * (9 28) = 135

The number of books in the C category is 420 * (12 28) = 180 equations:

Solution: Because the book ratio of the three books of A, B and C is 7:9:12, the three kinds of books of A, B and C are 7x, 9x, and 12x respectively, and the difference between the sum of the two books of A and B is 210.

That is, (7x+9x)-(9x-7x)=210

solution, x=15

7x = 105 books of type A, 9x = 135 books of type B, 12x = 180 books of type C Answer: 105 books, 135 books, and 180 books of type C are respectively.