Physics Where does the electrical energy go, the physical electrical energy problem

The construction of the ammeter also uses the principle of electromagnetism. There is a small coil in the ammeter, and the current generates magnetism through the small coil in the ammeter, attracting the pointer of the ammeter, and people can intuitively see that there is a current passing through. That is to say, there are two places where the electrical energy disappears, one is the consumption of the wire itself, and the other is the mechanical energy consumed by the ammeter to convert the generated electric energy into a visible pointer.

If the electric energy in the circuit is simply increased, the display of the ammeter will not be delayed, because the ammeter can only indicate the three states of electricity or no electricity in the circuit and how much electricity there is, if you want to make the value of the ammeter slowly become 0, you must ensure that the current in the circuit slowly decreases to 0.

There is a current in the loop because the induced electromotive force is generated when cutting the magnetic inductance line, and there must be a stable electromotive force to have a stable current, when you have no electromotive force after cutting or there is no change in the magnetic inductance line, the current is naturally gone!

Electrical energy is mainly converted into heat for the wires.

No, if you cut the magnetic inductance line to generate an electric current to overcome the elastic force of the spring in the ammeter, it becomes the potential energy of the spring, and after you stop, the potential energy of the spring becomes the kinetic energy of the ammeter pointer, so the pointer returns quickly; If you increase the amount of electrical energy, it is just an increase in the amount of energy mentioned above, and it is estimated that it will not disappear after a while as you said.

The ratio of the generated electrical energy to the energy consumption of wires and meters is still too small, and the loop current cannot be maintained for a long time.

Induced electromotive force is generated when the magnetic inductance line is cut, and there is no change in electromotive force after the cut. The current is gone

The reason for the current is the directional movement of electrons, and if there is an electromotive force, the electrons will move from high to low, and without electromotive force, the electrons will move in a chaotic manner!

Electrical energy is first converted into electromagnetic energy, which is used to deflect the pointer, and after confronting the magnetic field on the magnet in the ammeter, it is converted into thermal energy.

1 total joule = 1 watt * 1 second.

1 kWh = 1000 watts * 1 hour.

1 kWh = 1 joule * 1000 * 3600

p is the power, which represents the speed at which work is done per unit of time.

Kilowatt-hours and joules are units of energy that characterize the magnitude of energy.

Power 1W means that 1 joule of electrical energy is consumed in 1 second.

Similar to the S=VT formula, watts correspond to velocity, joules and kilowatt-hours correspond to distances, and they are linked by time.

Kilowatt-hours and joules denote the units of energy. A watt is a unit that denotes power. Power is one watt In electricity, it means that the power of electrical energy in the first second is one watt, and the work done is 1 watt * 1 second one joule. You can't say a watt of electricity.

Is Nava w a unit of p?

Is the power of 1W mean that 1W of electricity is used in one second?

No, a power of 1W represents 1J (joules) of electrical energy per second.

1 kWh = 1 kWh is the unit of electrical work. The joule is also a unit of electrical work. 1kw·h＝ 。

The use of the two is different, the unit of joule is very small, it is inconvenient to use, and the unit that commonly uses "degree" to do electrical work in life is the "degree" that is usually said to use a few degrees of electricity.

watts) is a unit of power p. p is the rate of change of electrical work with respect to time (also known as work done per unit of time).

p=dw dt (w is the electrical work).

1 watt = 1 joule second.

It can be counted by the conservation of energy.

The electrical energy is all converted into mechanical energy = 5*10 7*80% The mechanical energy is equal to the distance that the object Kochi moves under the action of force, and the force in this question = 600n, so s*600=5*10 7*80%.

The solution is s=2 3*10 5m hope.

w is the gravitational potential energy of the lifting water, w=mgh=pvgh, q is the electrical energy required to store water, w q= q, and q

The gravitational potential energy of the water or w when the water is discharged The efficiency of the generator is q1 as the electrical energy produced q1=w*

The idea is very simple: self-study and look at the questions.

I don't think anyone will calculate such a big problem for you.

600r, description 600 rpm, power consumption. The turntable of the electric energy meter has rotated 120 times in ten minutes, and the electric energy consumed by the air base in ten minutes of Youchun q = 120 600 1 = the electric energy consumed by each bucket of grinding minutes q =

0 minutes to answer the ruler and turn 120 times.

720 laps in 60 minutes.

And 600 revolutions per hour is 1kw

It is now 720 laps per hour.

That's 720 600=

Therefore, the average energy consumption per minute is w=pt=1200w*60s=72000j

600r, which means that every time the chaos macro consumes one kilowatt-hour, the meter turns 600 times and turns 120 times, indicating that the power of the stool is 120 600 = degrees, so the power consumption per minute = one kilowatt-hour = 1000x3600j = the jujube posture consumes electricity in one minute =, o5 =