What are the conditions for two objects to collide and move in the same direction?

If this is to be satisfied, the object with the mass must collide with the object with the lower mass in order to ensure that the two continue to move in the same direction.

You can think of it this way: two objects have momentum p1 and p2 respectively, and the magnitude of momentum p1 > p2 is opposite. We can assume that two objects collide with each other (if they collide obliquely, there is always a part of the momentum that cannot be cancelled out), and the direction of the larger momentum p1 is positive, then the direction of p2 is the opposite direction, and the calculation is negative.

According to the law of conservation of momentum before and after the collision of these two objects, p1-p2 = p total, since p1 > p2, p total 》0. So the direction of the total momentum and the larger momentum of the last two objects are the same. If two objects collide completely inelastically (i.e., move at the same velocity), then their common velocity is always in the same direction as p, i.e., in the same direction as the larger momentum.

So the full formulation of your sentence is that two objects have a completely inelastic collision with the center, and finally the direction of the common velocity of the two objects is the same as the direction of motion of the object with high momentum. Also, there are mentions upstairs that "the law of conservation of energy" and "the movement of an object to the side with less force" are all wrong. In a completely inelastic collision, there is a loss of energy, and momentum is conserved but kinetic energy is absolutely not conserved.

In addition, according to Newton's third law, the force between two colliding objects is always reversed, and there is absolutely no such thing as "small force", and the impulse of their interaction is the same.

Momentum is conserved, energy is conserved.

Categories: Science & Engineering.

Problem description: Is it due to the relationship of force? If so, how can I control the impact effect of the object to my satisfaction? (e.g. I wish one stopped).

If not due to force, but by what? How to control it?

Please elaborate a little bit, I would like to hear an answer. Because I am afraid that there will be no satisfactory answer, I will give 10 points for the time being, and if there is any satisfactory, I will replenish it. Thank you!

Analysis: Let me explain that only the momentum balance is satisfied during the collision, and the energy balance is not necessarily satisfied, and there may be energy loss during the collision!

I'll address the questioner's questions one by one:

1。Two objects collide, and some move in opposite directions after collision.

This is a non-fully elastic collision where there is a certain loss of energy in the collision and the momentum is balanced before and after the collision.

2。Two objects collide, some in the same direction.

This is a completely inelastic collision in which the energy is lost the most and the momentum is balanced before and after the collision.

3。Two objects collide, and one of them is stationary.

This is an elastic collision, and if there is no excitation in the collision, the energy is lost, and the momentum before and after the collision is balanced.

The questioner only needs to know that the momentum is balanced to solve this problem.

But in order to delve deeper into the study of Lingxi, it is also necessary to understand the balance of energy.

The energy balance is not necessarily reflected in the object The energy of two objects may be partially lost to the surrounding environment due to an instantaneous collision.

In fact, the total energy of the two objects before the collision = the total energy of the two objects after the collision + the energy lost in the surrounding environment.

This is the balance of energy.

It is precisely because of the difference in the energy lost during the collision that causes two objects to collide, some of them move in opposite directions, some of them are in the same direction, and some of them are stationary.

Done, thanks.

There are too few conditions to judge, and it is related to the material, shape, mass, speed, movement mode, environmental conditions, etc. of the object. Take a simple billiard, for example, where the cue stick is hit horizontally.

In the case of the center of the white ball, the ball will move in the direction of the rod, and when the ball itself rubs against the table, the white ball will have a rotating motion. In general, the rotation is in line with or in the opposite direction of the ball (depending on whether the club strikes above or below the ball).In this way, you can hit the follower, set the ball, and withdraw the ball.

The curling ball is achieved by hitting the ball above or below the side. A ball struck by a white ball moves in the direction of the line between the point of impact and the center of the ball being struck. The influence of the ball's rotational motion on the white ball is generally negligible.

The direction of movement of the white ball after hitting the colored ball is greatly changed by the momentum of the white ball, and the position of the hit ball, the influence of rotation and the influence of the edge of the table, and the master is using these conditions to make the white ball stop in the ideal position.

According to this expression, the implication is that object A and object B are moving in opposite directions, and after object B collides, it is possible to burrow into object A or be stuck by object A, and move with object A at the same speed as object A in the direction of the original motion of A.

1. The premise of momentum conservation is that the resultant external force on the system is 0;

2. For two objects colliding on a smooth tabletop, a. there is no external force in the horizontal direction, and the momentum is conserved;

b. The resultant external force in the vertical direction is equal to zero, and the momentum is also conserved.

3. In the air, regardless of air resistance, two objects collide.

a. There is no external grinding force in the horizontal direction, and the momentum auspicious number is conserved;

b. The vertical side swims upward, and is affected by the gravitational pull of the earth, and the momentum is not conserved.

Pick B. The landlord should know that this topic examines the law of conservation of momentum, that is, m(a)*v(a1)+m(b)*v(b1)=m(a)*v(a2)+m(b)*v(b2), at this time, options a and b are in line with the equation, but according to the actual situation, after a collides with the skin from behind, a's speed can not be greater than b, at most the two move forward at the same speed when the same liquid grips, then exclude a, b should be selected.

Start first. The momentum theorem is staring.

The actual situation (e.g. a small ball collides with a wall, it must be the ball returning) determines the direction, and the direction is the direction of the object with the most momentum, and then combined.

Kinetic energy theorem. The law of conservation of energy.

The transformation of energy and the judgment of whether it is (complete) or not

Bullet Sakura Void Collision.

and other aspects of the joint solution. Spinal pulposus blindness.

The greater the momentum, the greater the impact force, and according to the law of conservation of energy, the object moves towards the side with less force.

The weight of the object is large and the inertia is large.

This kind of problem involves two conservations:

Conservation of energy. Momentum is conserved.

You must know about the conservation of energy, the conservation of momentum is not taught to check it.

Collisions are generally accompanied by a loss of energy (kinetic energy does not increase unless there is other energy conversion) and then the momentum is conserved, and if the latter block moves in the opposite direction after impact, the calculation will show that the kinetic energy of the system increases, which is not possible.

If the latter block has a higher velocity than the previous one (in the same direction, of course), do you think the later block is equipped with Phasers? (haha).

Actually, if you master two conservations, the collision problem will not be difficult. You can check the derivation and derivation of the formula, which generally belongs to the last three questions of the calculation question, and it is helpful to ponder it carefully by yourself.