A math problem is a reproduction, etc

Hour. 2.Assuming that the total cost is y, and is allocated to plant A x tons, then B is divided to (700-x) tons.

y=x/55*550+(700-x)/45*49510x+(700-x)11

7700-x

Y 7370 is required first, so x 330

Therefore, at least 330 tons of garbage should be allocated to plant A.

3.Forget about the itinerary!

Solution: (1) Factories A and B process the city's garbage at the same time.

700 (55+45)=700 100=7 (hours)2) Set: It takes X hours for A to process the city's garbage.

B: It takes Y hours to dispose of the city's garbage.

550*x+495*y=7370...1)55*x+45*y=700...2)

y = 370 45 (approx) = 8

x=330/55=6

3)55*x+45*y=s

hours) B is more expensive than A, try to use B.

700 55 = 12 (hours)...40 (tons).

40 tons to B, B can't finish it at one time, so give it to A.

13 * 550 = 7150 (yuan) did not exceed 7370 This is the least flower.

3.B to process 100 tons, and now A starts processing, and B does the same. How long does it take for A to process 50 tons more than B?

100+50) (55-50) = 30 (hours).

B is more expensive than A, try to use B.

700 55 = 12 (hours)...40 (tons).

The key is how to establish the equation, that is, the equation (the time taken by A and B to make parts is equal) solution: let the work efficiency of A be x pieces of hours is already y and then set the same number of parts as a

Then Workload Efficiency = Time.

1/4 a）/x=(a-45)/y

(1+20%)=2 3 a-(a-45) to solve the equation, the total workload is 1 4 a * 2 3 + 1 4 a + 2 3 a

A and B. Hope it helps!

After A completes 1 3 and then completes the remaining 3 4, then A has completed a total of 3 4 * (1-1 3) + 1 3 = 5 6 B has completed a total of 1-3 8 = 5 8

A: B = 5 6: 5 8

A = 3 4 B.

When A completes 1 3 of the total, B completes (1 3) * (3 4) = 1 4, that is, 54 (1 4) = 216 (pcs).