A few math equations to help solve

5x-3=3-x

5x+x=3+3

6x=6x=1

4y-7=6y-9

4y-6y=7-9

2y=-2y=1

5(x-1)=3(x+1)

5x-5=3x+3

5x-3x=5+3

2x=8x=4

2x-1) 3}-=1, multiplication on both sides of the equal sign 124(2x-1)-3(3x-4)=12

8x-4-9x+12=12

x=4x=-4

3(2x+1)+1=-4(5-3x), multiply minus one on both sides of the equal sign:

6x+3-1=20-12x

18x=18

x=1(5x+4) 6}=+1, multiplication of 12:

2(5x+4)=3(x-3)+12

10x+8=3x-9+12

7x=-5x=-(5/7)

65 100 (x-1) + 37 100 (x+1) = (Is this a mistake in the symbol).

65x-65+37x+37=10

102x=38

x=(19/51)

65/100(x-1)=37/100(x+1)+65x-65=37x+37+10

28x=112

x=42 5(3y+2)=1 10-3 2(y-1), multiplication 10 on both sides of the equal sign

4(3y+2)=1-15(y-1)

12y-8=1-15y+15

3y=24y=8

t-3) 2}+=1+, multiplied by 12:

3(t-3)+2(6-t)=12+3(1+2t)3t-9+12-2t=123+6t

5t=-120

t=-25 symbol is clear.

It's so simple to figure it out yourself.

Question 1.

x=-2 Question 2.

2y-1 4=1-3-y 8 multiply both sides by 8 to get 16y-2=8-24-y

Get 17y=-14

y=-14/17

Question 3. 85%（2x-3)-55%(5-3x)=60%(5-3x)85%（2x-3)=60%(5-3x)+55%(5-3x)85%（2x-3)=115%(5-3x)

85%/115%=(5-3x)/(2x-3)17/23=(5-3x)/(2x-3)

17(2x-3)=23(5-3x)

34x-51=115-69x

103x=166

x=166/103

Open, move item, x=25 13 2y-1 4=1-3-y 8 shift, 17y 8=-7 2, y=-28 17 85%(2x-3)-55%(5-3x)=60%(5-3x) open,move item,,x=166 31

1. Set the time to go to work in x minutes.

Then there is 12:10 + 2x+:10 (for 10 minutes) + 8 (for 8 hours at work) = 9:00

x=20min

So the time to leave the house is: 2:30, that is, the clock stopped for 2 hours and 20 minutes.

It's very confusing, in fact, the clock starts walking from 12:10 to 9:00 in the evening, during which Uncle Li goes to work and walks, and he arrives 10 minutes early, just subtract these)

2. There are x people who set 2 questions correctly.

7+5*6+2x+3x+4(52-7-6-2x)=181x=452-6-7-2x=31

3. No. 4. Set the cost of each type of candy to be X yuan.

Total number of kilograms: x

Total price: 3 x unit price = total price Total number of kilograms = 11 (yuan kilograms) The formula is not good to list, so it is written in words.

1. Encounter problems.

Let us meet after x hours, 65x+72x=274

137x=274

x=22, the unit price of the ballpoint pen is x yuan, then the unit price of the fountain pen is 4x yuan 4x+5x=

9x=x=pens4x=4*

3. Set up team B to repair x meters every day, and team A to repair 2x meters per day, x + 2x) * 8 = 4230

3x=x= (Team B).

4.Set A to save x yuan and B to save y yuan.

x+y=1000

x-240=3(y+80)

Solving the system of equations yields x=870

y=130 or let A save x yuan, B save (1000-x) yuan.

x-240=3(1000-x+80)

x-240=3000-3x+240

x=8701000-x=1000-870=130 (B).

1.Does the question mean that the two cars depart from Nanjing and Shanghai respectively? If yes, the equation is as follows:

65+72）*x=274

The solution is x=22Let the ** of the ballpoint pen be x yuan, then the ** of the fountain pen is 4x5x+4x=

9x=x= 4x= of the fountain pen

3.Set up team B to repair x meters every day, which can be seen from the title.

x+2x)*8=4230

3x=x=4.Set A to save x yuan and B to save y yuan.

x-240=y+80

x+y=1000

The solution is x=660

y=340

1.(65+72)x=274, x=2km2Ballpoint pen** x 4x+5x=yuan x= fountain pen 4x= yuan3(x+2x)8=4230 x= meter dollars.

1. Set the time to go to work in x minutes.

Then there is 12:10 + 2x+:10 (for 10 minutes) + 8 (for 8 hours at work) = 9:00

x=20min

So the time to leave the house is: 2:30, that is, the clock stopped for 2 hours and 20 minutes (it's very confusing, in fact, the clock starts walking from 12:10 to 9:00 in the evening, during which Uncle Li goes to work and walks, and it is 10 minutes in advance, just subtract these).

2. There are x people who set 2 questions correctly.

7+5*6+2x+3x+4(52-7-6-2x)=181x=452-6-7-2x=31

3. No. 4. Set the cost of each type of candy to be X yuan.

Total number of kilograms: x

Total price: 3 x unit price = total price Total number of kilograms = 11 (yuan kilograms).

The formula is not good for columns, so the text is written.

Hour 20 minutes.

Human, a+c=22, c+e=36, d+e=39 a+e+2c=22+36=58

a+e=58-2c a+e is an even number: a+e=28 58-2c=28 c=15

The first question is that it takes 8 hours to go to work, and there are 8 hours and 50 minutes from 12:10 to 9 o'clock, so it takes 25 minutes to get from home to the factory, so he watches the clock at 2:35 and the clock stops at 12:10, and there are 2 hours and 25 minutes in between.

The second question, 2x+y=52-7-6, 2x+3x+4y=181-7-5*6, x=4, y=31, there are 31 people.

The third question, no, it is very mysterious from childhood to adulthood.

Question 4,,,k=...

3 - Set the number of people who do pairs of 2 and 3 lanes x

1*7+5*6+2x+3x+4(52-6-7-2x)=181

x=452-7-6-4-4=31

Let the baby elephant be x years old and the elephant be y years old, then there is y+(y-x)=31, x-(y-x)=1, and the solution is: x=11, y=21

If the first pile has x, the second pile has Y, and the third pile has Z, then the first pile has x-y, the second pile has 2y, and the third pile has Z; After the second change, the first pile has x-y seeds, the second pile has 2y-z seeds, and the third pile has 2z seeds. After the third change, the first pile had 2(x-y) seeds, the second pile had 2y-z seeds, and the third pile had 2z-(x-y) seeds. So there is 2(x-y)=2y-z=2z-(x-y), and x+y+z=46, there is no integer solution, and there are 46 in total, how can "the number of marbles in the three piles be exactly the same"? "The third time I counted the marbles from the first pile and merged them into the first pile"?

If the father is x years old, the mother is (x-3) years old, the sister is y years old, and the younger brother (y-2) years old is yes.

x+(x-3)+y+(y-2)=73, and because the four people are 16 years old in four years, and 73-58=15, so the younger brother was not born four years ago, and the younger brother should have been born three years ago, so y-2=3, y=5, so x=34, so the father is 34 years old, the mother is 31 years old, the sister is 5 years old, and the younger brother is 3 years old.

The elephant is x years old, and the baby elephant is y years old.

x+(x-y)=31

y-(x-y)=1

Solution: x=y=

The first pile has marbles x, the second pile has marbles y, the third pile has marbles (46-x-y) three times after the first pile remains: 2 (x-y) = 2x-2y the second pile remains: y + y - (46-x-y) = 3y + x-46 The third pile remains:

2(46-x-y)-(x-y)=92-3x-y, the number of marbles is equal, and x, y, and 46-x-y 73 are 15 more than 58, indicating that the younger brother was not born four years ago, and the mother was x years old, the father was x+3 years old, and the sister was y years old four years ago.

x+(x+3)+y=58

x+4+(x+3)+4+y+4+3=73

x, x+3, y can be solved

The answer is very simple.

These questions. I knew how to do it when I was in elementary school, but now I don't think I can do it much.