The understanding of electric field problems, the process of finding detailed solutions to electric

Acceleration is related to the force. So the whole paragraph is actually describing the change in the force on the particles. The electric field force is inversely proportional to the square of the distance.

When the charge carried by the charged particle is opposite to the charge at both ends, the charge at both ends has an attraction effect on the charged particle, and the gravitational force is inversely proportional to the square of the distance between the charged particle and the endpoint charge. It means that when it begins to move towards one end, the attraction of the charge at this end will gradually increase due to the proximity, and the action with the other end will gradually weaken, so the final resultant force will gradually increase along the direction of motion, which is manifested as an increase in acceleration.

If the charge of the charged particle is the same as the charge at both ends, the charged particle is subjected to the repulsive force from both ends, so it cannot move along the line of the two charges, but can only move along the middle perpendicular line (because the starting point of the charged particle is at the midpoint), and the magnitude of the resultant force is the sum of the projection of the charge from the two ends on the repulsion on the middle perpendicular. It would be better to make a diagram for better understanding. The resultant force is not only related to the magnitude of the component force, the greater the component force, the greater the resultant force.

And it is related to the angle between the component force and the vertical line, the smaller the angle, the greater the resultant force. This is a pair of contradictions, and the two are the product of the relationship, so it will cause the result of the force first becoming larger and then smaller, which is manifested as the acceleration first becoming larger and then smaller. This process is easier to understand as a diagram method.

It is mainly said that the largest field strength on the axis of the same charge is not the center, but the maximum initial field strength at another point, that is, the acceleration generated by the electric field force is the largest. The midpoint is the smallest when the horizontal line (charge wire).

With the same number, the charge should be subjected to a force to the left or right, then it accelerates... Acceleration becomes larger.

In the case of a different sign, the charge is subjected to an upward or downward force, so an acceleration motion with a gradual increase in acceleration is performed along the vertical line of the two charges, and then an acceleration motion is performed with a gradual decrease in acceleration.

How do I feel that there is a problem with the textbook? Because it is impossible to determine the direction of the disturbance of the charge? Please take a look at the things in front of the textbook and see if there is anything missing...

Once the electric field force is determined, the force analysis is sufficient. The physical image is obvious. This is a simple question in high school physics, try it yourself.

According to Gauss's theorem, the field strength in the inner cylinder is e1=0

The distribution of the field strength between the two cylinders: e2 = 2 0r then the electric potential at the distance from the axis r in the inner cylinder:

u=∫r-->a e1dr+ ∫a-->b e2dr=0+(λ/2πε0)∫a-->b (1/r)dr=(λ/2πε0)ln(a/b)

Assuming that the uniformly distributed line charge density is r, the electric fields generated by the left and right diameter segments at point o will cancel each other out. Therefore, only the electric field generated by the arc segment at point o remains, and it is obvious that the electric field also cancels each other out in the horizontal direction, leaving only the electric field of the vertical segment.

According to the definition of the power plant, the electric field strength of point o (only in the vertical direction) is obtained: e = (rdl r 2sina) in the interval 0 to , and because da = dl r, the above integral is brought in, and the integral is obtained: e = (rda rsina) in the interval 0 to , so that the electric field strength of point o is e = 2r r , and the direction of the electric field is in the vertical direction.

Since the electric potential is the product of the electric field at that point and the relative distance, the electric potential at point o is e = er = 2r.

According to the symmetry, the electric field must be spherically symmetrically distributed, and the spherical coordinate system is established with the center of the sphere as the origin, and the spherical shell with the origin as the center of the sphere and the radius r as the Gaussian surface, and the Gaussian theorem is used to obtain the field strength of the spherical shell

r r, e · 4 r = q (r 0).

r r, e · 4 r = q 0

The helium nucleus has two units of positive charge that is twice that of a proton w=uq w is equal so the ratio of proton to particle voltage should be equal to 2:1

1 2mv = uq v equal v=(2uq) m proton mass is 1 helium nucleus mass 4 bring in and pour out voltage ratio of 1:2

Because the ball is positively charged, the field strength is to the right, so the electric field force f=qe, the square basis excitation to the right sail sock electric field force decomposes into a parallel inclined plane direction of the component force f1=f*cos perpendicular inclined plane The component of the front state direction f2=f*sin Because the gravity of the ball is decomposed into a parallel inclined plane.

The answer given upstairs is already very good, it's really amazing, the picture is well done, and I learned.

Let the angles between OA and AB and the electric field strength E of the thin wires be and , the tension forces in OA and AB are F1 and F2 respectively, and the electric field forces on A and B are 3F and F respectively. First, list the force equilibrium equations for the two balls

B: Horizontal f2*cos = f, vertical f2*sin =mg, compare the two formulas, tg = f mg

A: Horizontal F1*Cos +F2*Cos =3F, Vertical F1SIN =MG+F2*Sin, substituting the above two formulas into these two formulas, we get Tan =F mg so =, that is, the answer C is correct.

The electric field is a vector field that is directed in the direction of the force of the positive charge. The nature of the force of the electric field is described in terms of the strength of the electric field.

Electrostatic FieldAn electrostatic field is an electric field that is excited by a stationary charge. The electric field lines of an electrostatic field start at positive or infinity and end at infinity or negative charge. The work done by the electric field force moving the charge has the characteristic of being path-independent.

The energy properties of an electric field are described with a potential difference, or the distribution of the electric potential of an electric field is visualized with an equipotential surface.

A physical quantity that describes the characteristics of an electric field at a certain point, the symbol is e, and e is a vector. The electric field strength is referred to as the field strength, which is defined as the ratio of the electric field force f to the amount of charge q that is placed at a point in the electric field, and the direction of the field strength is the same as that of the positive charge. The definition of field strength is derived based on the characteristics of the electric field that acts on the charge.

It is suitable for both electrostatic fields excited by charges and vortex electric fields excited by changing magnetic fields. The unit of field strength is the cow or the voltmeter, and the two units have different names and sizes. The field strength is numerically equal to the electric field force exerted on the unit charge at that point, and the direction of the field strength is the same as that of the positive charge.

The characteristic of the electric field is that there is a force acting on the charge, the electric field force, the positive charge is forced in the same direction and direction, and the negative charge is forced in the opposite direction. An electric field is a substance that has energy, and the energy of the electric field is greater when the field is strong. The strength of the electric field is known to determine the force exerted by the electric field on the charge, and the electrical breakdown of the dielectric (insulator) is related to the small strength of the field.

The electric field strength of the point charge is determined by the point charge and has nothing to do with the tentative charge.

In order to vividly describe the distribution of field strength, some directional curves are artificially drawn in the electric field, and the tangent direction of a point on the curve indicates the direction of the field strength at that point. The density of the electric field line is directly proportional to the strength of the field. The electric field is a kind of substance, and the electric field lines are an auxiliary tool that we artificially draw to easily describe the distribution of the electric field, and they do not exist objectively.

In space where there is no charge, the electric field lines are not intersecting and not interrupted. The electric field lines of the electrostatic field also have the following characteristics: 1. The electric field lines are not closed, starting from the positive charge and ending with the negative charge; 2. The electric field line is perpendicular to the surface of the conductor; 3. The electric field lines are perpendicular to the equipotential surface.

Electric Field Force: I. Definition: The interaction between the charges takes place through the electric field.

As long as there is an electric charge, there is an electric field around the charge, and the basic property of the electric field is that it has a strong effect on the charge placed in it, and this force is called the electric field force. Two directions: the positive charge is in the tangent direction along the electric field line, and the negative charge is in the opposite direction along the tangent direction of the electric field line.

3. Calculation: The formula for calculating the electric field force is f=qe, where q is the charge charge of the point charge and e is the field strength. Or by w=fd, it can also be found according to the distance between the work done by the electric field force and the motion in the direction of the electric field force.

Another important formula in electromagnetism is w=qu (where u is the potential difference between two points), which is derived from this formula.

The electric field belongs to a kind of field, there is a field strength, and the electric field line indicates the direction of the electric field, strictly speaking, the tangent direction;

The earth can be seen as a large magnetic field, attracting all objects, related to distance;

If the electric field is formed by point charges, the effect is also like that of the earth, attracting or repelling all charges, and this electric field is weaker and weaker the farther away;

If it is a uniform electric field, the charge will not change regardless of the force;

However, it should be noted that the electric field line is artificially drawn, and it does not actually exist, but it only represents the electric field situation, and the denser the line hall and between, the stronger the field strength.

The embodiment of energy: Ming Sui such as a plate capacitor has an electrostatic field, to produce this electric field is required energy, for example, Huai Nao needs to separate the charge on the plate of the energy required.

Embodiment of mass: For example, photons do not have static mass, but have moving mass, and the electric field is a part of the electromagnetic field, and the photon is the electromagnetic field.

It is not reflected in the electrostatic field and needs to be moved.