Everyone, who is good at math, help the little ones solve two math problems with a lot of words! Tha

Option 2 is the most profitable.

Plan 1: 4 tons of milk tablets can be made in 4 days, 5 tons of fresh milk, and the total profit is 2000 4 + 500 5 = 10500 yuan.

Scheme 2: There are x tons of milk processed into milk tablets, and Y tons of milk processed into yogurt, and the binary equation is listed.

x+y=9x+1/3y=4

Solution: x=, y=

The profit is: 2000 yuan.

Therefore, option 2 is the most profitable.

It's too troublesome to type, but it's not difficult to solve it if you think about it yourself. \(o^)/~

Question 1: Plan 1: It can be made into four tons of milk tablets, and the remaining five tons of fresh milk can be sold.

The profit is 4 2000 + 5 500 = 10500. Scheme 2: It can be made into six tons of yogurt, two tons of milk tablets, and one ton of fresh milk.

The profit is: 6 1200 + 2 2000 + 500 = 11700.

Are you still in elementary school? Learn to read the problem patiently by yourself, and I'll help you do the first problem.

According to the first plan, make as many milk tablets as possible**, then 4 tons of milk tablets can be made in 4 days, and the remaining 5 tons can be sold as fresh milk.

You can make a profit 4 * 2000 + 5 * 500 = 10500, according to the second plan, make milk flakes x tons and make yogurt 9-x tons.

Then x+(9-x) 3=4 finds x=

It is possible to make a profit. Overall, the second option is better, but there are better options, and you can think about it.

1. Suppose there are x pages.

x/10+x/10+6)/x=1/4

So x=120

2. Suppose the first team has a car 5x, then the second team has 3x

5x-14)/(3x+14)=1/2

So x=6 for the first team and 30 for the first team and 18 for the second team

1.Xiaoyu read a book, read one-tenth of the book in the morning, and read 6 more pages in the afternoon than in the morning, at this time the number of pages read and the number of pages not read were 1:3. How many pages are in the book?

There are x pages in the book, morning and afternoon.

x = 120 pages.

2.If 14 vehicles are transferred from the first team to the second team, the ratio of the number of vehicles in the first team to the second team is 1:2, how many vehicles are there in each of the two teams?

If a pair of original cars are 5x, then the second team has 3x

5x-14）:（3x+14）=1:2

7x = 42x = 6, a team of 5x = 30 cars.

Second team 3x = 18 vehicles.

1.Let the book have x pages, and the equations are:

x/10+x/10+6):[x-(x/10+x/10+6)]=1:3

Solution: x=120

So the book has 120 pages.

2.Set up a team with x cars, and a second team with a car y, and the equation system gets:

x:y=5:3,(x-14):(y+14)=1:2 solution: x=30, y=18

So it turned out that the first team had 30 vehicles, and the second team had 18 vehicles.

Solution (1) If the book has x pages, then:

x/10+x/10+6)：[x-(x/10+x/10+6)]=1：3

Solution: x=120

So the book has 120 pages.

2) If the first team has x cars and the second team has y cars, then:

x：y=5：3

x-14)：（y+14)=1：2

The simultaneous solution is x=30, y=18

So the first team has 30 vehicles, and the second team has 18 vehicles.

1. I read 1 10 in the morning, and I read 6 more pages in the afternoon than in the morning, that is, I read 2 10 more than 6 pages in a day, and then I read all 1 (1+3)=1 4

So this book totals: 6 (1 4-2 1 10)=120 (pages)2, the total number of cars in the two teams is unchanged, before the adjustment, the first team accounted for 5 (5+3)=5 8, after the transfer of 14 vehicles, the first team accounted for 1 (1+2)=1 3, therefore, the total number of vehicles is 14 (5 8-1 3)=48 (vehicles).

So the original first team: 48 5 (3+5)=30 (vehicles), the second team: 48-30=18 (vehicles).

1.The book has x pages.

then x 10 + x 10 + 6 = x 4

x/20=6

x=120The book has 120 pages.

2.There were two teams with 5x 3x cars each.

Then 2(5x-14)=3x+14

7x = 42x = 6, so the two teams originally had 30 18 cars each.

1.Set x pages.

1:3 gives x=120

So the book has 120 pages.

The number of pages in the first question is a then a 10+a 10+6=a 4 and a = 120

In the second question, if the original number of cars in a team is 5A, then the second team is 3A

3a+14=2(5a-14)

The solution gets a=6 so it was.

Teams 1 and 2 each have vehicles.

1x-1 = plus or minus 40 = plus or minus 2 times plus or minus 10

x = 1+2 times with 10 or 1-2 times with 10

24x+1 = plus or minus 48 = plus or minus 4 times plus or minus 3

4x = -1+4 times with 3 or -1-4 times with 3

x=-1 4+3 or -1 4-3

(1) x-1 = plus or minus 2 root number 10

x = 1 + (plus or minus 2 root number 10).

2) 4x+1 = plus or minus 4 root number 3

4x=(plus or minus 4, root number 3)-1

x = (plus or minus root number 3) - (1 4).

1 Xiaoyue jumps 20 more per minute than Xiaofeng, and 40 more in that time, which is 2 minutes, so Feng skips rope 100 2 50 per minute

2 set the original plan to construct T days, now it is T-2, the actual work efficiency is 20% higher than the original plan, get 1800 (T-2) = 1800 T multiplied, get T = 12, so 1800 12 = 150

(1) Xiaoyue jumps 20 more per minute than Xiaofeng, and 40 more in that time, which is 2 minutes, so Xiaofeng jumps rope 100 2 50 per minute.

2）1800/x-1800/

x=150

1、（1）be=ec

ABE Circumference - The circumference of the ace.

AB+AE+BE)-(AC+AE+EC)AB-AC3 cm. 2)) AD BC, i.e. AD is high.

s△abe=1/2be×ad

s△ace=1/2ec×ad

be=ecs△abe=s△ace

i.e. the area of ABE is equal to that of ACE.

2、∵be=cf

be+ef=cf+ef

i.e. bf = ec

ab=dc, af=de

abf DCE (edge, edge, edge).

3. Can't draw a picture.

There are no figures.

It's better to have a picture, so it's easy to answer.