NH3 and O2 react, NH3 H2O

Choose AdThe reaction that occurs is: 4NH3 + 5O2 = 4NO + 6H2O (catalyst, heating), 4NO+3O2+2H2O = 4HNO3 (1) When the remaining gas is oxygen, the reaction can be written as:

4NH3 + 8O2 = 4NHO3 + 4H2O, so ammonia and oxygen 90 milliliters are mixed at 1:2 to complete the reaction, and the oxygen participating in the reaction is 60 milliliters, and the total oxygen is 70 milliliters. (2) When the remaining gas is NO, let the ammonia volume be x oxygen volume is, 3 (x 10) = 4 (y The oxygen volume can be obtained is milliliters.

wangtaozhuce2011-8-6 17:36

The above friend's solution idea is right, but when considering that the remaining gas is no, he ignores a problem. It can be considered that in this reaction 4NH3 + 5O2 = 4NO+6H2O (catalyst, heating), the amount of O2 is insufficient, and exactly 10 ml of NO is generated, because the O2 has been consumed. The second reaction does not occur.

Excess NH3 is absorbed by water. Under this condition, the volume of O2 is calculated to be . There is also the friend above who solved the equation incorrectly, and the result is.

The result of the first step solution is 70ml is correct. Therefore, the answer to this question is B.

The high concentration of NH3 was NH3+H2O=NH·H2O, and the low concentration of NH3 was NH3+H2O=NH4(OH).

According to the chemical equation and reaction characteristics, the substances that can react with NH2OH (hydroxylamine) and also react with NaHSO3 (sodium bisulfite) are aldehyde compounds.

Aldehydes have a structure containing a carbonyl group (C=O), so they can undergo addition counter-blocking with NH2OH or NaHSO3. In the Fengheng group, when it reacts with NH2OH, hydroxylamine forms corresponding oxygen heterocyclic compounds through nucleophilic addition reaction. When it reacts with NaHSO3, a silver electrophilic addition reaction occurs to generate the corresponding sulfinate product.

It is important to note that not all aldehyde compounds are capable of reacting with both reagents at the same time. The specific situation of the reaction also needs to be comprehensively considered according to the structural characteristics and reaction conditions of aldehyde compounds.

2NH4HCO3+2NAOH (small amount) (NH4)2CO3+NA2CO3 2H2O

NH4HCO3 + NAOH (large amount) is a large amount of NAOH and the above chemical equation continues to react.

Ammonia is formed NH4HCO3+2NAOH (mass) NA2CO3 H2O+NH3:H2O

The reaction equation is:

1. When NAOH is small.

2nH HCO +2NaOH (small amount) = (NH) CO +NA CO +2HO

2. When naoh in large quantities.

NH HCO +2NAOH (mass) = NA CO +H O + NH : H O

3. Under heating conditions.

nh₄hco₃+2naoh==δnh₃↑+na₂co₃+2h₂o<>

Cu2+ +==Cu(OH)2 is dissolved +2NH4+

In excess, Cu(OH)2 dissolves and dissolves the extermination limb excavation.

cu2+ +==cu(nh3)4]2+ +4h2o

NH3 produces N2 when burned in pure oxygen (not easily flammable in air), equation.

For: 4NH3 + 3O2 = ignition = 2N2 + 6H2O but this reaction has little practical significance.

Industrial nitric acid is made by using NH3 and O2 (or air) under the action of 450 500 and a catalyst to generate NO, the equation is:

4NH3 + 5O2 = Catalyst = 4NO + 6H2O

As far as I can tell, it shouldn't react.