One or two simplified questions in the first year of junior high school! Urgent!!!!!!!

(3-4y) (3+4y)+(3+4y) quadratic.

3－4y)(4y+3)-(3+4y)^2；

3+4y)(3-4y-2)

3+4y)(1-4y)

4-13y+4y-16y^2

4-9y-16y^2

2x+y) quadratic - (2x-y) (x+y)-2(x-2y) (x+2y), where x=one-half and y=-2

4x^2+y^2+4xy-2x^2-2xy+xy+y^2-2(x^2-4y^2)

4x^2+y^2+4xy-2x^2-2xy+xy+y^2-2x^2+8y^2

4x^2-2x^2-2x^2+y^2+y^2+8y^2+4xy-2xy+xy

10y^2+3xy

1) Simplification of the result 18+24y

2) Simplification of the result xy+8 (the square of y).

The number of carry-on values turned out to be 31

1]（3+4y）（3-4y+3+4y）=6(3+4y)

2] After simplification, y(10y+3x) brings in data to get 37

Question 1: (3-4y)(3+4y)+(3+4y) squared.

3+4y)[(3-4y)+(3+4y)](3+4y)*6

18+24y

Question 2: (2x+y) squared - (2x-y)(x+y)-2(x-2y)(x+2y).

4x square + y2 + 4xy - 2x square - 2xy + xy + y square - 2x square + 8y square.

3xy+10ysquared.

Bring in x=1 2 y=-2, get.

Original = 3*(1 2)*(2)+10*(-2) squared.

What is the process is casual, the process is the most important, if you don't understand how to get out, you won't be able to do it in the future, learning attitude is the most important!

x+z) Chafan y+(x+y) z+(y+z) x+x x+y defeat hail y+z z=0 (take 3 apart).

x+y+z) hail letter y+(x+y+z) z+(x+y+z) x=0 to eliminate x+y+z (because it is not equal to 0, both sides can be removed at the same time) 1 x+1 y+1 z=0

Multiply the left and right by xyz at the same time

Get xy+yz+xz=0

Simplify first and then evaluate: m(m3) (m3)(m3), where m4 simplifies (evaluates) the value, where.

Simplify first, then evaluate, known a = 1, b = find the value of the polynomial first simplify, then evaluate: , where , simplify first, then evaluate: , where x= 2, y= .

Simplify, then evaluate: , where.

Simplification and evaluation. 2xy2+[7x 3(2x 1) 2xy2] y, where .

When , find the value of the algebraic equation .

Simplify, then evaluate: 2x2+( x2+3xy+2y2) (x2 xy+2y2), where x= , y=3

Simplification Evaluation: where.

Simplification and then evaluation: 4 (2 5 ) 2(3 where = 1, b= simplify: 2x2+(-x2+3xy+2y2)-2( xy+y2), where x= ,y=3

1)x²y²+ xy²

2)-9x²y+6x²y²-10xy³

3)-6a²b²+6a²b³

But then again, you should do it yourself.

Question 1 I don't know, is question 2 equal to 1?

2. The cut-and-patch method is exactly half, and the area is 1

1. Obviously, the angles of point O are all 60 degrees, AC, EF are parallel, and the area on the left can be solved by setting three unknowns ob, of, and od to list the area (using the sine and cosine theorem).

2) Connect the file Zen to AC and take the point Q to connect QN and QM, so you can shoot stupid to get qmf= f, and attack the jujube qnm= den and qmn= qnm, so as to get den f.

Original formula = 1 tung orange (-x) (1 x) = permeability -x) x (-x) (numerator and denominator are multiplied by (-x) x).

x）^（x-1）

That is, the result is the x-1 power of -x in parentheses around the hail cluster.