How many boys are in a class with 1 3 more than the class size, and 10 more girls than boys?

Binary linear equations are solvable. Let the number of boys x and girls y, from the known conditions, x-(x+y) 3=5

y-x=10

y=10+xsubstitutionx=25y=35 class=25+35=60 people.

There are x boys, x + 10 girls, and the whole class x + x + 10 = 2x + 10 people.

According to the title: x=1 3(2x+10)+5

x = 252x + 10 = 60 people.

There were 60 people in the class.

Hope, thank you.

Solution: Let the boy x people, call the girl x ten 10 people, and list it as an equation according to the title.

x one (2 x ten 10) 3 = 5

then x = 25 people, girls = 25 + 10 = 35 people, and the class size is 25 + 35 = 60 people.

The class size is equal to the boys and girls.

Set the class size to x

x=1/3x+5+1/3x+5+10

x=2/3x+20

1/3x=20

x=60 So there are 60 students in the class, 25 boys and 35 girls.

There are x boys and y girls in the class.

x=（x+y）/3+5

y=x+10

3x=x+x+10+15

x=25 (person).

y=35 (person).

There are 25 + 35 = 60 students in the class.

Let the number of boys be a and the number of girls be b

then (a b) one-third a 5

b a=10.

Set: The boys and girls in this class are x and y respectively.

x=5/9（x+y）-4

9x+36=5x+5y

4x-5y+36=0……（1）

y=40%（x+y）+6

5y=2x+2y+30

2x-3y+30=0……（2）

1)-(2) 2.

y=24x=21

y-x=24-21=3

There are 3 fewer boys than girls.

There were three fewer boys than girls, forty-five in total, twenty-one for boys and twenty-four for girls.

The number of boys in a class is 4 fewer than the total class size of 5 9, and the number of girls.

Let's assume the class size is x

5/9x-4+

x-5/4/9x-2/5x=2

45 on both sides at the same time, got.

20x-18x=90

2x=90x=45 (person).

So there are 5 9 45-4 = 21 boys.

There are girls who have them. 24-21 = 3 people.

There are 3 fewer men than girls.

Hope it helps.

Male 5 9x-4(1).

Female 40%x+6(2).

Male + Female x5 9x-4+40%x+6=x

x-5/9x-40%x=2

x（1-5/

x（9/9-5/

x=2＊9/

x=451)-(2)Substitute x 45

3 There are 3 fewer boys than girls in this class.

There were 21 boys and 24 girls, and there were three fewer boys than girls.

There are people in this class.

5/9x-4+40%x+6＝x

5/9×+2/5x+2＝×

25x+18x+90＝45x

x 45 boys 45 5 9-4 21 people.

There are 24 girls.

24-21 = 3 people.

There are 3 fewer boys than girls.

Personally, I think that there are 3 fewer boys than girls, so you can solve the problem in this way.

If the class size is y, there are:

5y/9-4+y×40%+6=y

Multiply the two sides of the above equation by 9 to get:

5y+then: y=45 (person).

Number of boys = 5 45 9-4 = 21 (people).

Number of girls = 45 x 40% + 6 = 24 (people).

As a result, the number of boys is 3 fewer than the number of girls.

If there are 3 more boys than half of the girls in a class, there are 6 more boys than girls, i.e. girls +6 = 2 times the boys.

There are 17 more girls than boys, and the number of girls is a and the number of boys is b

a - 17 =ba + 6 = 2b, subtract the above two equations to obtain:

b = 23a = 40This class has a total of 40 + 23 = 63 people.

Set up girls to have Shenghui Ji Biheng x people.

1/2x+3＝x-17

3+17 x-1 2x

20＝1/2x

A: There are 63 students in this class.

Solution: Boys account for 7 10 of the class, and girls account for 1-7 10 3 10 of Zheng Dan's classSo the class size is 14 (7 years 10-3 10) 14 2 5 35 people.

There are three more boys than 2 5 of the total, and one more girl than 1 2 of the total, and the total number of x people. Male grinding Shensheng is 2x Zhila 5+3. For girls, it's 1x 2+1.

x=2 x/5+3+1x/2+1。

x- 2x/5-1x/2=4。

x- 4x/10-5x/10=4。

1x/10=4。

x=40。There are 40 people in the class.

Set boys: x; Girl: Y

x=2 5(x+y)+3 is the source spike.

y=1 hail key Bu2(x+y)+1 i.e. 1 2y=1 Liangkai 2x+1 i.e. y=x+2

Substituting y into x: x=2 5(2x+2)+3 gives x=19 and y=21

Class size: x+y=40 students.

The answer is 20 people, and if the class size is x, two-fifths x plus three equals one-half x plus one, and you get 20.

Let the whole class be 2 5x13 for boys and 1 2x+1 for girls

2 Wisdom Shirt 5 +3+1 2 +1=

Anterior chamber 1-2 5-1 2) = 4

There were 18 girls in a class, accounting for two-fifths of the total number of students in the class. The class had [45

People, friends and boys account for one-fifth of the class Zheng San, boys have [27 people.

There are 18 girls in a class, accounting for 2 5 of the total number of students in the class, that is, 2 5 = 18 45

1. It can be seen that there are 45 people in the class; Male (45-18) = 27; The stove collapsed

Boys account for (5 5- 2 5) = 3 5.

The number of boys was 6 more than the class size of 5 liter state 7, and the number of girls was 4 less than the class size of 1 4 of the class size of the Fool Clan. How many people are in the class?

There are x people in the class.

5/7 x+6+1/4 x-4=x.

20/28 x+7/28 x+2 =x.

27/28 x+2=x.

x-27/28 x=2.

1/28 x=2.

x=56.A: There are 56 students in the class.

There are x people in the male laughter jujube and y people in the female girl.

According to the question, the system of equations can be listed x=5 7(x+y)+6y=1 4(x+y)-4

Solving the system of equations yields x=46 y=10

There were 56 students in the class.

I hope I can help you.