How much does the voltage drop per kilometer of 22OV AC?

How much the voltage drops per kilometer. In physics, u=irThis is the basic Ohm's Law formula. To determine the size of the step-down, it is necessary to have the current i flowing through the wire, and the impedance of the line is related to the material and cross-sectional area of the line.

Therefore, the distance and voltage alone cannot be determined, and the line is stepped.

If the line resistance is 2 ohms and the line current is 10 amps, then the step-down is 20 V. If the current is 0, the step-down is also 0

220 volts of alternating current, the voltage drop per kilometer is limited, the coarser the voltage drop is smaller, the finer the trap, the larger the pressure, and the smaller the deputy length is affected by you, the greater the pressure, the greater the burden, and the smaller the pressure.

The technical term is called "voltage drop", and the voltage drop is related to the cross-sectional area, resistance value, length, power and power factor of the load side of the cable. It is not that there is an exact fixed value, for example, with 10 square millimeters of copper wire, 1000 watts of load, power factor as an example, there will be a voltage drop of about 21 volts per kilometer, because the power factor of alternating current is lower, the actual voltage drop will be more. It is recommended that you complete the previously mentioned parameters before you can provide accurate information.

For 220 volt electricity, its voltage drop per kilometer has a lot to do with the load it carries and the wire diameter of the line.

For this kind of electricity knowledge, I suggest you ask the staff of the power company, or ask your friends and relatives around you. Because we are not professional, it is not accurate to say it.

Answer: This is related to the current, voltage drop = current * resistance.

Pull 2,000 meters away from the wire, 2 wires, a total length of 4,000 meters.

Resistance of the wire = resistivity x length of copper wire cross-sectional area = x 4000 = 28 (ohms), the voltage drop is proportional to the current or power of the load, that is: voltage drop = current x resistance = power x resistance voltage, if the load is 1000 watts, the voltage drop is 1000 x 28 220 = 127 (volts), the electrical appliance has not worked normally.

If the voltage drops to 200V, some electrical appliances (such as light bulbs) can still work, but allow it to be abnormal, the maximum power that can be driven is 220x20 28 = 157 (W).

The conclusion was that the unusable wire was directly introduced into the 220V power supply from 2 km away.

The formula for calculating the DC resistance of the wire: DC resistance per kilometer = resistivity 1000 cross-sectional area (square millimeters), the data is OK.

When the temperature is 20, the resistivity of copper is Euro * square millimeters; The resistivity of aluminum is Euro* square millimeter meters; Therefore, the power supply is 2000 meters away from the load, and 2 core copper wires need to be used, and the actual wires are 4000 meters, DC resistance = 4 * ohms.

1. What is the voltage drop after the 220 volt voltage of the square copper core wire is pulled 2000 meters, the answer is a variable, that is, the larger the load, the greater the current, and the voltage drop = current * resistance. As calculated above, the voltage drop varies with the load for resistive fixed;

2. How much power can it drive? That's a good question. To answer it, we must first refer to the national electricity code on the allowable voltage fluctuation range of low-voltage lines is 220 10%, that is to say, the voltage drop is allowed to 22V, and the reasonable working voltage range of electrical equipment is (198 242V).

Wire line current = 22V ohm = ; Load power = current * voltage =

The conclusion of the calculation is that after 2000 meters of double-strand wires, the electrical appliances that can only be driven normally can be driven.

The calculation is a simplified DC equivalent calculation. The actual calculation of alternating current is more complicated.

Regardless of this calculation, it is not feasible for a 220V power supply to supply a load 2,000 meters away, especially when using squared wires.

According to the requirements of GBT 3956, the maximum resistance of the copper conductor should not exceed Euro kilometers, the distance between single-phase 2 wires is 4 kilometers, the maximum resistance is 30 ohms, if the current through 1A, the voltage drop on the conductor is 30V, and the voltage is only 190V, so the power of electrical appliances should be controlled below 1000W, and it is best to control it below 700W.

Ask if a 2,000-meter cable (5x16) has a load of 20 kilowatts. What is the terminal voltage?

This doesn't usually happen, does it? Either the voltage was stepped down through the transformer, or there was a problem with the device itself that you were detecting the voltage.

This situation is very complicated, what you described is too general to answer, it may be that the mains voltage is too low, it may be that the circuit is broken, or it may be that the wire diameter is too thin, and the power of the electrical appliance is too low to pull the voltage.

220 volts AC becomes 120 volts, which is step-down by the transformer.

Transformer 2, you can also use switching power supply 3, in most cases in the play bar AC becomes DC.

If 220V AC becomes 120V, it may be caused by the unstable voltage here.

The voltage of the alternating current fluctuates at 120 and will change from a stable state to a stable state, so it is fine as long as it can be operated.

220 volts AC becomes 120 volts, check if your wiring is broken? It's possible that the 120 volts you measured was an induction electricity.

If 225 AC becomes 125, it means that there must be a problem with the inquiry, and everyone has a problem with the line after returning.

220V, the AC voltage becomes 125, this may be because there are some problems with this voltage, so this should still be paid attention to.

This is a professional question, please can't answer the question Do you have a familiar electrician master? I asked them about another physics teacher, and I thought I could explain this problem with scientific reasoning. Ask them for advice.

I was handed over by the second degree Liu Bei mystery, how can I go back to the second degree? Then in this specific case, we also have to look at the situation when people use it.

There are several possible reasons for the increase in terminal voltage:

1.The transformer tap is adjusted to the highest gear, and the high voltage on the primary side is increased.

2.The loop load is mostly capacitive load, which is in a high power factor operation state, and even reaches the phase entry state.

3.There is a problem with the line parameter selection, it is on the edge of resonance, so the voltage rises.

The function of the 220-volt power transformer is to reduce the 220-volt AC voltage through the transformer to the voltage required by the electrical appliance. The production of power transformer can calculate its power, the number of turns per volt, the number of turns of the primary coil, and the number of turns of the secondary coil according to the required voltage, and calculate the required enameled wire diameter of the primary coil and the required wire diameter of the secondary coil according to the power size. The secondary winding of the power transformer can be wound with multiple independent voltages according to different required voltages.

The following figure shows the power transformer for AC radio, with 200 volts AC high voltage and volt filament voltage

The secondary output of the power transformer is still 50Hz alternating current, if you need to supply power to the audio, you must pass the rectification, filtering, before it can be used. As shown in the figure below, the power supply circuit for the 12-volt DC power supply of the car audio:

Flat can be, the wire mainly depends on the current and power, not just the voltage. You can find the relationship between wire diameter and current, and the relationship between power and power, but there is no relationship between voltage and voltage.

Hope...

Look at the power of the load, the power of the wire has to be thick, the power can be smaller, you asked something, the voltage is high, the hail is low and the wire diameter is not Guandou Town, really help you look forward to the source of the pin

The voltage of 220 volts refers to the effective value. The upper limit is 220 times the root number of the virtual branch two, the difference is about volt, and the lower limit is 220 divided by the root number two, which is about volt.

Just choose a full-bridge module directly, the input terminal is connected to 220V AC, and the output terminal directly outputs 220V DC through rectification, and select the appropriate full-bridge module according to your load power and input and output voltage!

1. The bridge rectifier uses four diodes and is docked in pairs. The positive part of the input sine wave is that the two tubes are turned on to obtain a positive output; When the negative half of the sine wave is input, the other two tubes are turned on, and since the two tubes are reversed, the output still gives the positive half of the sine wave. Bridge rectifiers use the input sine wave twice as efficiently as half-wave rectification.

Bridge rectification is the first step in the conversion of alternating current to direct current.

2. Bridge rectifiers, also known as rectifier bridge stacks.

3. The bridge rectifier is made of multiple rectifier diodes as bridge connections, and is encapsulated with insulating plastic externally, and the high-power bridge rectifier is encapsulated with a metal shell outside the insulation layer to enhance heat dissipation. There are many varieties of bridge rectifiers, excellent performance, high rectification efficiency, good stability, the maximum rectification current is from 50A, and the maximum reverse peak voltage is from 50V to 1000V.