Why is the solution of the equation 3x a 0 for x greater than the solution of the equation a 2 3x 4

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Since the solution of equation 3x+a=0 is x=-a 3, and the solution of equation a-2 3 x-4=0 is x=3 2*(a-4), then, when -a 3-3 2*(a-4)=2, -1 3-3 2)*a=2-6

2/6+9/6)a=-4

11a/6=-4

a=24/11

So, when a = 24 11, the solution of the equation 3 x + a = 0 about x is 2 greater than the solution of the equation a-2 3 x - 4 = 0.

The solution of the equation 3x+a=0 is x=-a 3, a-2 and the solution of 3x-4=0 is x=3(a-4) 2, and from the meaning, it is known that -a 3-3(a-4) 2=2

2a-9a+36=12，∴a=24/11.

The solution of 3x+a=0 is x=(a) 3,a 2 The solution of 3x 4=0 is x=3(a-4) 2

a)/3＝3(a－4)/2＋2

a)/3－3a/2＝－12/2＋2

2a)/6－9a/6＝－6＋2

11a)/6＝－4

11a＝－24

a＝24/11

That is, when a = 24 11, the requirements are met.

Because the noisy bifan 2x-4=0 seeks to hail out x=2

And because Hui judges that it is 3x -a=0, we find x =a 3

From the problem x x, i.e. a 3 is greater than 2, so a is greater than 6

3x=-2a+1

x=(-2a+1)/3

x=a+3, big 4

The cluster slips to so-burn (-2a+1) 3=a+3+42a+1=3a+21

5a=-20

a=-4 so.

The first Zheng Xu: an x=(-2a+1) 3=3

The second x=a+3=-1

3x+a=0

3x=-ax=-a/3

3-2 (x+3) hood sum = 1

2(x+3)=3-1

x+3=1x=-2

a 3-(-2)=3 (the solution of equation 3x+a=0 is greater than the solution of 3-2 (the width of the object is stared at x+3)=1 and the solution is a large and clever macro 3).

a/3+2=3

a/3=-1

a=-3

x+2a-1=0;

x=1-2a;

a+3-x=0;

x=a+3;

So 1-2a-(a+3)=4;

1-2a-a-3=4;

3a=-6;

a=-2;So x1=1+4=5;

x2=a+3=-2+3=1;

I'm glad to answer for you, skyhunter002 to answer your questions, if you don't understand anything about this question, you can ask,

2x+5a=0

x=-5a/2

3 Comma 4x-6=0

3/4x=-6

x=-8 then there is a crack -5a 2-(-8)=3

5a Shanyuanso2=8-3=5a=2

3x + a = 0

3x = -a

x = -a/3

5x - a = 0

5x = a

x = a/5

So -a 3 - a 5 = 2

Multiply both sides by (-15) at the same time to get :

5a + 3a = -30

8a = -30

a = -15/4

So choose A

The solution of equation 3x+a=0 is x=-a3

The solution of equation 5x-a=0 is x=a 5

So -a 3-2=a 5

8a/15=-2

a=-15/4

The first equation is solved x=-a 3, the second is solved x=a 5, the first one is 2 larger than the second, so -a 3-a 5=2, and the solution is a=-15 4. Remember to take it as, thank you.

First, we use a to represent x, i.e., x=-a3 and x=a5, respectively

From the known -a 3-a 5=2 to find a=-15 4

So choose A

Since the solution of equation 2x+a=0 is 5 greater than the solution of equation 3x-a=0, let the second equation be: 3(x+5)-a=0=3x+15-a=0

Add 2x+a=0 to the above equation to get x=-3, so a=6