Ask a Chemistry Master About Electrolysis, Chemistry What is an Electrolytic Reaction? Detailed!

The key is to figure out the nature of electrolysis!!

Electrolysis is the strongest redox reaction pathway.

Since it is a redox reaction, there must be the movement of electrons, and what does the movement of electrons depend on? By ions dissolved in water.

Therefore, true distilled water (without impurities) cannot conduct electricity, and electrons cannot move in it, so it cannot be electrolyzed.

1. In the second science book, water molecules (H2O) are electrolyzed into oxygen atoms (O) and hydrogen atoms (2H) (in this text, it is said that water molecules are composed of hydrogen atoms and water atoms, and there is no other substance, that is, distilled water can be electrolyzed).

This sentence is that you have misunderstood, he said that the water molecule is composed of hydrogen atoms and oxygen atoms, which is completely correct, but the electrolyzed water molecule is pure, it does not mean that the electrolyzed water is pure. Pure water molecules are electrolyzed, which does not mean that pure water (distilled water) is electrolyzed.

It is because there are magazines mixed in the water, so that the water can conduct electricity, and the electrons can move in it, so that H+ can gain electrons, and Oh- can lose electrons

1.Because water is a molecular crystal, in the normal state is a molecule as a unit, conduction requires ions, only ionic crystals conduct electricity, high school chemistry books say that matter is divided into four crystals, molecules, ions, metals, atoms, this is the property.

2.Electrolysis is electrolysis, which uses electrical energy to disassemble molecules, not the general process of disassembling ions.

Therefore, there must be metals or ions to conduct electricity, but the water of molecular crystals has no ions and only molecules, so it cannot conduct electricity.

Water is a weak electrolyte and can be said to be non-conductive.

When electrolyzing water, sodium sulfate is added to the water.

Distilled water can weakly ionize H+ and OH-, so water is a weak electrolyte, but the concentration is very low, the conductive effect is weak, and the dissolution rate is slow.

Water is a weak electrolyte and does not conduct electricity.

Electrolysis is due to the addition of electrolytes.

1.Distilled water (H2O) without impurities H is cationic O is anion, which meets the conditions that the teacher said, why can't it conduct electricity.

H+ and OH- are ionized in distilled water, and the concentration is 10-7mol L at room temperature, so water is a weak electrolyte, and it cannot conduct electricity due to the extremely weak degree of ionization.

2.If distilled water does not conduct electricity, how can it be electrolyzed?

Background 1: What is the original sentence? Electrolysis is different from ionization, which occurs automatically and generates anion and cation; Electrolysis, on the other hand, is the generation of new substances by gaining and losing electrons under the action of an external power source.

The conductivity is very low, and there is no by default.

Electrolytic sodium sulfate is electrolyzed water.

When the gas produced by the cathode is H2, there is amol, then the water participating in the reaction has amol, that is, 18a grams.

This part of the water and w g sodium sulfate decahydrate just form a saturated solution, because the temperature is constant.

The relative molecular mass of sodium sulfate decahydrate is 322, where the relative molecular mass of sodium sulfate is 142, then the mass fraction of sodium sulfate is 71 161

So the mass of the solute is 71w 161

The mass of the solution is 18A+W

The mass fraction is 71W, 161 divided by 18A+W, multiplied by 100%, and then simplified, and then B, choose B

The reaction that occurs at the cathode is 2h 2e h2

Because there is amol gas, the amol water is electrolyzed, that is, 18ag because the final solution must still be saturated, so the substance that is separated from this solution constitutes a saturated proportion.

The sodium sulfate in sodium sulfate decahydrate has 142w (180+142)g, and the answer b can be found

The original solution is saturated, and the remaining solution is saturated, so the part that is separated from the solution is also equivalent to a saturated solution, and the concentration is the same, so this question is based on the part that is separated from the solution to find the concentration of the remaining solution: "A molar gas escapes on the cathode" is hydrogen, that is, the electrolysis of a mol of water [a 2mol of oxygen will be precipitated on the anode at the same time]; "WG sodium sulfate decahydrate" contains sodium sulfate (142 322) w grams, aqueous (180 322) w grams, therefore, the part that is detached from the solution is solute sodium sulfate (142 322) w grams, solvent water (180 322) w + 18a grams, so that the mass fraction of the solute of the remaining solution is: molecule (142 322) w g, denominator w + 18a g multiplied by 100%.

Simplified to B.

The electrode reaction is not a chemical reaction equation in the true sense, but only indicates the gain and loss of electrons and the change of matter at one pole in the galvanic cell or electrolytic cell.

The point solution reaction is a general reaction equation that summarizes the sum of the reactions of the two electrodes of the electrolytic cell and can reflect the change of the substance.

For example: electrolysis of water, electrode reaction: anode.

2h2o-4e=4h+o2

Cathode. 2h+2e=h2

Whereas, the electrolysis reaction of electrolyzed water is 2H2O = (energized) = 2H2 + O2

The oxidation-reduction reaction that occurs on the electrode is applied to the aqueous solution of the electrolyte. For example: 2H20 + 2CuS04 = Power on = 2H2S04 + 2Cu + 02

In an electrolyzer, direct current passes through the electrode and electrolyte, and an electrochemical reaction occurs at the interface where the two come into contact to prepare the desired product.

Electrolysis is the process of passing an electric current through an electrolyte solution or molten substance, (also known as electrolyte), causing redox reactions on the cathode and anode, and the electrochemical battery can undergo electrolysis when an external voltage is applied.

The process by which an electric current passes through a substance and causes a chemical change. Chemical change is the process by which a substance loses or gains electrons (oxidation or reduction). The electrolysis process is carried out in an electrolytic cell.

The electrolytic cell consists of two electrodes, one and two electrodes, submerged in a solution containing positive and negative ions, respectively. The current flows into the negative electrode (cathode), and the positively charged positive ions in the solution migrate to the cathode and combine with the electrons to become neutral elements or molecules; The negatively charged negative ions migrate to the other electrode (anode), donating electrons, becoming neutral elements or molecules.

1）①2h +

2e - h 2

The gas is released, and the solution turns red.

2cl -2e -

Cl 2 put the moistened potassium iodide lake Wangqin Qi powder test paper near the Y electrode, and the test paper turned sleepy blue.

2) Pure copper head type; cu 2+

2e - cu blister copper; cu - 2e -

cu 2+

frankxj1980 seems to be quite right, but I didn't look closely, and the text gave me a headache, so let's talk about it according to my own understanding.

Summary of your question:

Does electrolytic copper sulphate electrolyze water at the same time? What is the process? Who was involved in the reaction?

What you need to know: When electrolyzing, ions gain and lose electrons in a priority order (which can be understood as liveliness).

Electrolytic copper sulphate: 2CuSO4 + 2H2O = 2Cu + 2H2SO4 + O2

Anode: 2H2O - 4E- =O2 +4H+

Cathode stuffiness: Cu2+ +2E- =Cu

Here, H+ and OH- in H2O are combined, so H2O and Cu2+ are involved in the reaction

So there is water involved, but it is not the electrolysis of water, which produces hydrogen and oxygen (as we all know).

So why isn't hydrogen being generated?

Because the electrons are Cu2+!

Why is the electron Cu2+?

Because of the discharge order! (below).

Anode: Ag and previous metals: S2->SO32->I->BR->Cl-> (OH-in water)> OH-> oxygenate (SO42-)>F-

Cathode: Ag+>Fe3+>Cu2+>H+>Fe2+>Zn2+> (H+ in water)>Al3+>Mg2+>Na+

This metal is related to the parallel order of the ante, and my teacher asked me to memorize it when I was in high school.

Looking at the anode first, SO42- is behind OH- in water, so the OH- of the mammoth fiber in the water loses electrons.

2oh- -4e- =o2 + 2 h+ (actually like this).

The cathode, Cu2+ in front of H+ in water so get electrons first.

cu2+ +2e- =cu

When electrolyzing copper sulfate solution, because copper sulfate is a strong electrolyte and the ionization of solvent water is considered, there are actually four components in the system: copper ions, hydrogen ions, sulfate ions, and hydroxide ions. The law followed during electrolysis is that the anions lose electrons at the cathode and are oxidized, and the cations gain electrons at the cathode and are reduced. However, there is a certain sequence of different ions discharging on the electrode, because the oxygen coarseness of copper ions is stronger than that of hydrogen ions, so at the cathode, copper ions are first reduced by electric stalkers to precipitate metal copper.

The reducibility of hydroxide ions is stronger than that of sulfate ions, so at the anode, hydroxide ions lose electrons first and are oxidized to produce oxygen. In this way, copper ions and hydroxide ions are always discharged at the electrode first, and then it is the turn of hydrogen and sulfate ions to be discharged during electrolysis. Therefore, in the actual electrolysis process, the copper ions and hydroxide ions are continuously reduced, and at the same time, the solvent water is continuously ionized, the acidity of the solution is enhanced, and finally it is completely converted into sulfuric acid, and the copper ions and hydroxide ions are completely discharged and consumed, and the electrolysis process of sulfuric acid is started at this time.