There is a rope with a heavy object hanging in the middle, and the downward force is known to be 98N

Force analysis diagram, f, f, g three forces balance, f, f of the resultant force, and g of equal magnitude, opposite direction, <>

The component of f and f in the horizontal direction is exactly canceled, and the component of f and f in the vertical direction is equal to the magnitude of g and the direction is opposite, f sin5°+f sin5°=g, f = f ,2f sin5°=g, 2f sin5°=98n, f =98n (2sin5°).

Answer: The pulling force of the rope is.

When it can be slid freely, it is equivalent to putting a small pulley on the rope and hanging heavy objects through the small pulley.

In this case, for the analysis of the small pulley, the force that is applied vertically down (the magnitude is equal to the gravitational force of the object) is subjected to the pulling force of the rope on both sides (the tensile force on both sides is equal), and the resultant force is 0.

Note: Since the ropes on both sides belong to the same rope, the tension force is equal.

When the knot is knotted, the rope on both sides is no longer the "same" rope, so the rope tension on both sides has no necessary relationship, but the net force is 0 with gravity.

49 Ox. Basically, you can do it at 49 N because his torque can be reduced by half. So it's 98n 2 and that's fine.

It is equivalent to putting a small pulley on the light rope, and hanging the weight through the small pulley, as long as it is stationary or moving at a uniform speed, the resultant force of the tensile force at both ends of the rope is equal to the weight of all the objects hanging on the rope, and regardless of the angle between the two sections of rope, or whether to tie the dead knot.

Overall method analysis: light ropes, pulleys, and heavy objects are analyzed as an object.

The pulling force of the rope at both ends is 49N

For a lightweight rope, equal. Because rope, like spring, is an object that can produce elastic deformation, the elastic force generated is determined by the deformation.

Because the rope is stretched and deformed, it produces an elastic force that shrinks inward, which is the same as that of a spring.

If you hang objects of different masses on both sides, I understand that you mean the rope is on a fixed pulley, then the two objects will not be balanced, and the object with the higher mass will fall and the object with the lower mass will rise.

At this point, the elastic force t of the rope should satisfy: (t-mg) m = (mg-t) m

That is, the acceleration of both objects is the same.

t=2mmg/(m+m)

If it is a rope hanging from an object, then the pulling force of the rope on the object and the pulling force of the object on the rope are acting and reaction.

The pulling force of the rope on the object is also the tension of the rope.

It's the same with springs.

A rope, the force at both ends, how much tension at both ends? Answer: A rope is stressed at both ends, and the tension at both ends is equal.

A weight is balanced by force, the vertical direction of the resultant force is 0, the tensile force is equal to the gravitational force, the horizontal direction of the tensile force is 0, one of the horizontal tensile force is f*sina a is half of the angle.

Reason: Because gravity does not change, the resultant force and gravity of the tension force of the two ropes are a pair of balanced forces, the magnitude is equal, and the action is opposite, so the resultant force remains unchanged and is equal to gravity. (I don't know how to draw my own pictures and look at it).

Each end of the rope is subjected to a tensile force of 3N, and the net force on the rope is zero.

Sometimes a word is used, tension, which refers to the mutual traction force that exists inside the rope and perpendicular to the contact surface of the two adjacent parts when it is subjected to tensile force, which is also 3n.

This question. It's quite troublesome to answer, so let's use the counter-evidence method to prove it. Hypothesis one:

Take two tensile force gauges instead of ropes, let the left side be the wall, the right side is pulled by hand, the left tensile force gauge shows that the tensile force is 3N, and the right tensile force gauge shows that it is also 3N, then the total tensile force received by the two tensile gauges is 6N, and the tensile force received by the rope is 6N; Hypothesis 2: Take four more tensile force gauges instead of the rope, the four tensile force gauges show that the force is 3N, and the total force of the four tensile force gauges can be obtained is 12N, so the force on the rope is 12N, which is contradicted by the result of hypothesis 1, so the calculation method used in the two assumptions is not valid. Suppose one is to materialize the wall-to-rope tension into a left-hand tensile force, and the hand-to-rope tensile force is replaced with a right-hand tensile force, and hypothetical two is equivalent to cutting and tying a knot in the middle of the rope, so why is this algorithm not valid?

Because you regard the rope as two parts, the wall end and the arm end are respectively forced, so the rope force is the combined force of the two forces, it seems that this calculation method is correct, but the biggest mistake is that you divide the rope in this way. In fact, it can be divided into countless parts, replaced by countless tensile force meters, the force of each tensile force meter is 3N, the total force of the rope is infinite, only the rope as a tensile force meter can correctly express the tension of the rope, otherwise how to calculate can not really calculate the size of the force on the rope.

1. The tension of the wall to the rope is 3N

2. The pulling force of "force" on the rope is 3N.

So: the rope is subjected to a tensile force of 6n.

This is called the interaction force (Newton's third law). Pay attention to distinguishing balance forces. If the exerting party of the interacting force cancels the applied force, the stressed party cancels the applied force. Present and disappear at the same time. The applied force and the applied force are not on the same body. The magnitude of the force is equal and the direction is opposite.

1. It's still 100N.

n。Analysis: Forces all occur in pairs, i.e., action and reaction. The action force is 100N, and the reaction force is 100N. It can be assumed that one end of the rope is fixed, and you pull the rope with 100N, and the rope tension is 100N.

The force on both sides is not the same, the force of 110N is greater than 90N, the rope will move, 90N is the interaction force, and 20N produces acceleration. But the rope has to bear 90 n of balance force and 20 n of acceleration force.

1. The rope is subjected to a balanced force, and the resultant force is zero due to the balance of the two forces, that is, the tension is zero. 2. Since the forces at both ends are not equal, they are not subject to the equilibrium force, so this belongs to the synthesis of two forces, because the direction is opposite, so the resultant force needs to be subtracted by two forces, that is, 20!

1: Because the rope is subjected to the balancing force, the force on the rope is 0n

2：:110-90=20n

Answer: <>

FOB because of FOA

FOB, so when lifting heavy objects and overweight, the AO rope is broken first (2) when FOA

n, the heaviest object to be hoisted

Place gravity along the foa

The direction of the FOB is decomposed, as shown in the figure on the right, there should be a component of gravity along the direction of the FOA, g1

Equivalent to FOA

Because of +90°, in a vector right triangle, g1

g cos = g sin , 37°, 53° so: g = f

oasin53°

n Answer: (1) When the gravity of the lifting heavy object gradually increases, the AO section rope is broken first (2) The heaviest weight that the device can lift is n

As shown in the figure, the gravity of the three hook codes is 1N, and they are connected and suspended by three ropes, so the tensile force received by rope A is (3)N, the tensile force received by rope B is (2)N, and the tensile force received by rope C is (1)N.

When analyzing the first rope, look at the three hooks as a whole.

When analyzing the second rope, look at the two hooks as a whole.

Then, the solution can be solved using the knowledge of the balance of two forces.

The rope at the top is 3n, the middle is 2n, and the bottom is 1n

The first empty 3, the second empty 2, the third empty 1

1. The net force of zero is not equal to stationary, I don't know the specific environment of your problem, for example, you tighten the rope with both hands at the same time, and then you translate with both arms, it is stressed by 0, but it is moving. Or there is an initial velocity.

2. The tension is in these two equal sizes, imagine that you remove a force, when the rope is relaxed, it is considered that there is no tension, and now it is stretched on both sides, tight, and the size of the tension is the balance force.

Tension is the internal force of the rope.

Resultant external force as the name suggests is an external force.

The external force is not zero, but the resultant external force is zero, which is the effect of the force.

If you are stationary, you will not be forced?? Are you still now? Is the ground supportive for you? Does the Earth have a gravitational pull on you? You pull your own hair, don't you hurt and don't feel strong!