Can CPU P1 7 be changed to P2 4 and P2 8 or P 3 0 How to configure

The key to upgrading your CPU is to see if your motherboard supports it, and you can check what type of CPU your motherboard supports. Here's what I've helped you find online:

According to the naming convention of micro motherboards, the MS-6558 should be an OEM product with the SIS645 chipset.

There are several motherboards in this series, except for the SIS645 Pro with the SIS645 chipset, which uses a SDRAM DIMM slot and can support up to 3GB PC133 PC100 SDRAM memory, the others use the SIS 645DX (702 BGA) chipset.

Such as SIS645 Ultra, SIS645E, SIS645E Max...and so on all support DDR memory.

Among them, the SIS645DX (702 BGA) chipset supports 64-bit 533MHz P4 CPU, 32-bit AGP 4X 2X slot, supports 64-bit DDR333 DDR266 memory, and supports Bi-directional 16-bit data transmission line;

SIS645E Max supports three 184-pin DDR333 266 200 DIMM

Memory (six memory banks) up to 3GB.

The so-called DDR memory is Double Data Rage (double data rate) is an updated product of SDRAM, which allows data to be transmitted on the rising and falling edges of the clock pulse, where 400 refers to its operating frequency, in addition to the highest 400MHz, there used to be etc., so, DDR memory is not equal to DDR400 memory, DDR400 is backward compatible.

XP systems support more than 1G of memory!

If you want to form a dual channel, it is necessary to install two, and it should be noted that try to buy two memory modules of the same brand and model!

Is it a 478 interface or what? The SIS chipset is very low-end. The effect is not very obvious. It should be exchangeable.

All are 32-bit, but there is a 64-bit P4

Hehe, it's okay to write like this. To put it more bluntly, the value of this register (equivalent to the register) is copied to another register.

There is also such an instruction in the 51 MCU assembly statement. MOV P1, P2 So yes.

P1 P2 is just a name, and there is no such thing as being able to use it or not being able to use it.

It should be that your P1 controller is broken or the keyboard settings are wrong, just go to the controller settings of the options and set the good controller to P1 to play.

Keyboard,As long as there is no problem with the keyboard, it's OK to save it If the keyboard is broken,,Then you can only replace it Anyway, it's a bargain Ha。

Why can't you use the default p1 when you play alone, you make the problem clearer.

The keys in Live 8 are tuned in the options that go into the game, and the keyboard is 1p for any live game

Take 1L of concentrated salt Hu slipperic acid, the mass is 1000P1 gram, the solute mass is 1000P1W gram, the amount of the substance is 1000P1W mol, take 4L of water, the mass is 4000 grams, the mass of dilute hydrochloric acid is 4000 + 1000P1 grams, the volume is (4000 + 1000P1) P2 ml = (4 + 1P1) P2 L, therefore, the concentration of the grinding volume of the substance of dilute hydrochloric acid is (1000P1W mol L.).

In league mode, there is a player setting before entering the league before selecting a team. Turn P1 to gray and P2 to blue.

Change it in the outermost button setting, and it won't work to change it in P2.

There's a setting in the installation folder, so change it here!

It seems that the settings file also needs to be set.

I really don't know about this, I haven't played it.

The driver or software of the notebook is not fully installed. Take a look at what you bring with your computer. of the plate.

Solution: To prepare a solution with a density of 1 2 (1 + 2), a solution with a density of 1 is required to have a volume of v1', the volume of the solution with density 2 is v2', from the title, 1v1'+ρ2v2'=1/2×（ρ1+ρ2）×（v1'+v2'）

1v1'+ρ2v2'=(1/2)(ρ1v1'+ρ1v2'+ρ2v1'+ρ2v2')

2ρ1v1'+2ρ2v2'=ρ1v1'+ρ1v2'+ρ2v1'+ρ2v2'

1v1'+ρ2v2'=ρ1v2'+ρ2v1'

1v1'－ρ2v1'=ρ1v2'－ρ2v2'

v1'（ρ1-ρ2）=v2'（ρ1-ρ2）

v1'=v2'

Both solutions have the same mass and are both m kg, 1 2

The volume of the two solutions v1 v2.

Hence v1'=v2'=v2=m/ρ2

The maximum mass of a solution with a density of 1 2 (1 + 2) m = m1 + m2 = 1v1'+ρ2v2'=ρ1×(m/ρ2)+ρ2×(m/ρ2)=mρ1/ρ2+m

When two liquids of equal volume (v1=v2=v) are mixed, the result is =m v

This results in m1= 1v1

m2=ρ2v2

Then m total = m1 + m2 = ( 1 + 2)v

v total = 2v then total = m total v total = ......=( 1 + 2) 2 Dense liquid, small volume - all taken - m

The intake volume with low density is v=v2=m2

then the mass of the taker is m1= 1m 2

To make a solution of mixed = (1+ 2) requires a volume of a solution with a density of 1 v1 and a solution with a density of 2 with a volume of v2, there is.

1v1+ρ2v2=½（ρ1+ρ2）(v1+v2)ρ1v1+ρ2v2=(1/2)(ρ1v1+ρ1v2+ρ2v1+ρ2v2)

2 1v1+2 2v2= 1v1+ 1v2+ 2v1+ 2v2( 1- 2)v1=( 1- 2)v2, v1=v2

m=m1+m2=ρ1(m/ρ2)+ρ2(m/ρ2)=ρ1(m/ρ2)+m