To determine the mass fraction of a limestone sample

You typed the wrong question...So I can only tell you the idea.

The mass of the original sample is subtracted from the mass of the remaining solid after the reaction, which is the mass of the reacted calcium carbonate. After deriving, divide by the mass of the original sample to obtain the calcium carbonate mass fraction.

After calculating the mass of hydrochloric acid, because hydrochloric acid has water, it is calculated by dividing it by the mass of raw hydrochloric acid.

The mass of carbon dioxide produced is.

caco3+2hcl=cacl2+h2o+co2x y

100/x=73/y=44/

x=10g y=

1) The mass fraction of calcium carbonate in limestone is 10g

2) The quality of the solute contained in dilute hydrochloric acid.

This question can be 3g

This problem is one of the many types of data that can be solved.

This problem only uses 1g for calculation because every 5g of hydrochloric acid can dissolve 1 gram of solid, that is, 1 gram of calcium carbonate is reacted, and the mass fraction of the solute of dilute hydrochloric acid in this question does not need to find the solute in 20 grams of dilute hydrochloric acid solution to find the mass fraction of the solute.

The solute mass fraction of dilute hydrochloric acid is:

The calculation process with 3G is as follows:

Let the mass of HCl in 15 grams of dilute hydrochloric acid be Y

According to the title, it can be obtained: every 5 grams of dilute salt can react with 1 gram of calcium carbonate if it carries acid, 15 grams of dilute hydrochloric acid can just react with 3 grams of calcium carbonate, and the hydrochloric acid added for the fourth time does not dissolve the limestone, indicating that the last 1 gram is an impurity.

caco3+2hcl==cacl2+h2o+co23g y100:73=3g:y

Y = solute mass fraction of dilute hydrochloric acid is:

Let 15 grams of dilute hydrochloric acid contain HCl with a fibrillatory mass of X

CaCO3 + 2HCl = = CaCl2 + H2O + CO2 gas.

3g x100:73=3g:x

x = dilute hydrochloric acid, solute mass index index group signaling number is:

1) According to the mass of the remaining solid of the third and fourth times is 1g, it means that the 4g limestone sample contains 3g of calcium carbonate, so the limestone sample is in:

w(CaCO3)=(3g 4g)*100%=75%2) Let the mass fraction and combustion difference of the dilute hydrochloride Xiangduanzi solute be XcaCO3+2HCl=CaCl2+H2O+CO23g...20g*x

100/73=3g/(20g*x)x≈

Finding the mass of a substance is found in this type of problem with insufficient quantity.

The mass that generates the carbon dioxide leakage balance is.

caco3+2hcl==cacl2+h2o+co2↑x y z

100/x=73/y=111/z=44/

x=20gy=

z = mass fraction of calcium carbonate in limestone 20g. Noisy.

Mass fraction of solutes in dilute hydrochloric acid.

The mass fraction of the solute in the solution after the reaction.

1) The mass of carbon dioxide is XcaCO3+2HCl==CaCl2+H2O+CO2

x y z100/44=x/,x=20g

The mass of calcium carbonate in limestone is 20g.

1: Cao produced after calcination, which absorbs water easily and reacts easily with CO2 in the air.

2：co2=

3: CaCO3 = heating = Cao + CO2xx =

caco3=

caco3%=9/10=90%

CaCO3 = = High temperature) CO2 (gas symbol) + Caox

- Solution: x=9g

xcaco3%= 90%

It's a hassle to play the chemical equation).

Xiao Ming measured the mass fraction of calcium carbonate in a limestone sample in the laboratory (impurities do not react with acid), CaCO3+2HCl==CaCl2+H2O+CO2 100 44 x 100:x= x=5g

Add the same amount of hydrochloric acid each time, if the amount of calcium carbonate is sufficient, the amount of solids in each reaction should be equal, but the amount of the third time is significantly less than the amount of the second time, then the reaction is up to the third time, and there is no calcium carbonate left.

Therefore, after the fourth addition of hydrochloric acid, the mass of the solid remains unchanged.

2.Mass fraction of calcium carbonate in the sample = (

Each time the same amount of hydrochloric acid is added, if the amount of calcium carbonate is sufficient, the solid amount of each reaction should be equal, and when HCl is added for the second time, the solid mass of the reaction is 5g, and it can be inferred that the mass of the solid before the first addition of hydrochloric acid is 11+5=16g

And the mass of the remaining non-calcium carbonate solid after the reaction is complete.

The mass fraction of calcium carbonate in the sample = (

3caco3+2hcl==cacl2+co2+h2o100 44

x:x so we get x=

The mass of carbon dioxide produced in the reaction.

You wrote the title wrong, and there was only 1g left for the second time?

Are you sure you have 1 gram of solids left for the 2nd time?

CaCO3 + 2HCl = CaCl2 + H20 + CO2 CO2 is a gas, so the mass of the solution is the mass of CO2, according to which the mass m of CaCO3 can be calculated, which is the mass of impurities, and the total mass-impurity is the total mass of the solution.

1) 1g of calcium carbonate can be reacted with every 5g of dilute hydrochloric acid added to Kuqingwan, but the remaining solid mass of dilute hydrochloric acid added for the fourth time does not decrease, indicating that the calcium carbonate has been completely reacted, and the remaining solids are impurities; Rule.

The mass fraction of calcium carbonate in limestone samples = 4g?1g4g2) solution: Let the mass of the solute in the hydrochloric acid be x

caco32hcl=cacl2

h2o+co2

1g x1gxx=

Mass fraction of solutes in hydrochloric acid

Answer: (1) The mass fraction of calcium carbonate in this limestone sample is 75%;

2) The mass fraction of the solute in this hydrochloric acid is: