Please help! Chemistry questions in junior high school

The first thing that comes to mind is to do it with conservation of charge.

The sum of positive and negative charges is zero.

The ratio of sodium to magnesium to magnesium is 5 to 1

Then the positive charge is 5x+2x=7x, and SO4 is negative bivalent, so bracket 7x twice as much as 14x and divide it by the negative bivalent of SO4, and we get the number of SO4 is 7x, so the ratio of the number of ions of Mg2+ to SO42- is 2x:7x=2:7

mm(gg) Ah, your question doesn't seem complete

The ratio of the number of Na+ to Mg+ ions is ???

If you add it, you can solve it.

Let me also talk about the process.

According to the law of charge conservation, the charge of Na+ and Mg2+ ions is equal to that of SO42-ions, and then let Na+ and Mg2+, and then I don't need to talk about it, it's a simple math problem.

I don't understand that the upstairs actually made the question without even the content of the question.

What does the ratio of Na+ to Mg+ ions mean?

...You didn't finish the question, what is the ratio of NA+ to MG2+?

Anyway, a no...

It is calculated based on the fact that the total number of molecular congratulatory messages is zero.

This question is better to do backwards, and the breakthrough is the turbidity of the clarified lime water at the far right.

First of all, the water with the clarified lime becomes turbid (CaCO3), which can only be CO2 or SO2, because F is a black solid, so G must be CO2, and F is C. Going up, and because of the high temperature with H to form purple-red solid B, it should be copper elemental (sorry that our textbook here describes copper is generally red, so I am not sure), then the reaction is carbon reduction copper oxide, and H is Cuo; Go back to F to the left, carbon reduces iron oxide, and the solid can only be Fe (the iron element is obviously a silvery-white solid. Well, at least the iron powder is a black solid), and then the hydrochloric acid is simply replaced, and the A can also react with Cuo, indicating that it is reducing hydrogen and reducing copper oxide.

Next, from B to the right, oxygen is burned into Cuo, dilute sulfuric acid to obtain CuSO4, and then add barium hydroxide, and you must sensitively think of the precipitation - barium sulfate and copper hydroxide. Finish.

The questions are quite simple, so don't go into details.

It's too messy to see, but i should be co, d is barium sulfate and iron hydroxide.

Please make the question clear.,I really can't understand it.··

d must be barium sulfate and copper hydroxide.

Positive solution: (1) A H2 I Caco3 d Baso4 Cu(OH)2

2) C+O2=(ignition)=CO2

3) The chemical equation of F e 3C+2Fe2O3=(High Temperature)=4Fe+3CO2

The chemical equation of Hc Cuo+H2SO4==CuSO4+H2OG I is CO2+Ca(OH)2==CaCO3 H2O

4) Point out one of the uses of B: making wires and cables.