What factors depend on the magnitude of the main magnetic flux when the transformer is running at no

Updated on technology 2024-06-29
10 answers
  1. Anonymous users2024-02-12

    The difference between the excitation magnetodynamic potential of the transformer at no load and the load is that the magnetokinetic potential becomes larger at no load, while the magnetokinetic potential decreases when the load is loaded.

    The main magnetic flux of the transformer depends on the number of excitation turns of the primary-side excitation windingFor a specific power frequency transformer, the main magnetic flux depends on the terminal voltage of the primary-side excitation winding, and has nothing to do with the load size, that is to say, the main magnetic flux at no load and full load is basically unchanged.

    The standard definition of magnetodynamic potential is the magnetic flux generated by the flow of electric current through a conductor.

    is used to measure the magnetic field or electromagnetic field.

    A quantity similar to an electromotive force in an electric field.

    or voltage. It is described as the force by which the coil can produce magnetic flux, so that scientists can use it to measure or predict the force by which the energized coil can actually excite the magnetic flux. In addition, permanent magnets will also have a magnetokinetic potential.

    Note: The no-load current exceeds the rated current.

    10%, the loss of the transformer will increase; When the no-load current exceeds 20% of the rated current, the transformer cannot be used, because its temperature rise will exceed the allowable value, and the working time will be slightly longer, which will lead to a burnout accident.

  2. Anonymous users2024-02-11

    When the transformer runs at no load, there is only excitation current, heat loss and hysteresis loss, which means that the magnetic flux is a basically fixed value. As the load increases and decreases, the magnetic flux of the primary coil on the input side increases and decreases, because the load will produce a magnetic flux in the secondary winding that is opposite to the direction of the magnetic flux of the primary coil, which will weaken the primary magnetic flux, and the primary side will increase the excitation current to increase the magnetic flux in order to maintain the magnetic flux balance, that is to say, the relationship between the primary and secondary magnetic flux will change with the load.

  3. Anonymous users2024-02-10

    When the transformer is operating, the magnitude of the main magnetic flux is only determined in principle by the voltage value applied to the excitation coil or the applied frequency.

  4. Anonymous users2024-02-09

    The magnitude of the main magnetic flux at no load and at full load is basically the same.

  5. Anonymous users2024-02-08

    The excitation current does not vary with the load. Only the load current varies. You can solve for the primary current from the transformer's current relation.

    Broadly speaking, the excitation current provides a working magnetic field for generators and other "electrical equipment that works using the principle of electromagnetic induction" is called excitation; The current generated when the operating magnetic field is supplied is called exciting current.

    In a narrow sense, the excitation current is the current flowing through the rotor of the synchronous motor (with this current, the rotor is equivalent to an electromagnet, with n pole and S pole), and during normal operation, this current is generated by the DC voltage applied to the rotor externally. This DC voltage is supplied by the DC motor, and most of it is supplied by the thyristor after rectification, and the thyristor rectifier system is usually called an excitation device.

    When the generator is running alone, the excitation regulator adjusts the terminal voltage of the generator by adjusting the excitation current of the generator, and when there are multiple generators running in parallel in the power system, the excitation regulator reasonably distributes the reactive power between the generator sets running in parallel by adjusting the excitation current, so as to improve the static and dynamic stability of the power system.

    Excitation Current Regulation Software:

    The software of the PIC microcomputer excitation regulator adopts the assembly language of PIC16F877 and C language mixed programming, which is friendly to the man-machine interface and simple to operate. In addition, the modular design idea is adopted, with the main program as the core, the sub-programs of each functional module are designed, so that a large number of functions can be realized in the sub-programs, and the software design structure is simplified.

    The subroutine module mainly includes the system initialization and power-on self-test module, PID adjustment module, operation mode tracking module, over-excitation and under-excitation control module, start-stop module, communication module, etc. Figure 4 shows the flow chart of the main program of the system.

    The system provides three different modes of operation, namely constant voltage regulation, constant excitation current regulation, and constant reactive power regulation. Different operation modes can be switched and set to a given value by keyboard, in addition, the system also sets up the operation mode tracking module, that is, the tracking of the output of the alternate operation mode to the output of the current operation mode, so as to realize no disturbance when the operation mode is switched.

    Because the excitation system has inertia and hysteresis control objects, and requires high control accuracy and fast response speed, an improved PID adjustment mode is adopted in this design, that is, the integral saturation benefit is eliminated and the overshoot is reduced by using the integral separation algorithm.

    At the same time, the variable gain method of increasing the proportional effect in the dynamic response and reducing the proportional effect in the steady-state process is used to eliminate the large deviation and speed up the transition process, so that the excitation regulator has more ideal adjustment characteristics.

    In order to improve the reliability of the entire system, in addition to the self-test at power-up, error detection, fault tolerance and software watchdog are carried out during each calculation cycle.

  6. Anonymous users2024-02-07

    This is true, the transformer secondary load increases, the voltage decreases, the excitation current decreases, the magnetic force decreases, and in a magnetic closed loop, the primary magnetic force will be supplemented to the secondary. The excitation current of the primary is increased.

  7. Anonymous users2024-02-06

    <>1. The main magnetic flux of the transformer is determined by the number of turns on the excitation side. The number of turns on the excitation side phase is equal to the turn potential, according to the law of electromagnetic induction.

    The main flux can be found. This is a theoretical analysis, applied to the actual product, can also be calculated in this way, but in the actual design and production of the transformer, in fact, the transformer capacity is selected first.

    2. Then determine the magnetic flux density.

    The two are multiplied to determine the flux. The magnetic flux at the time of initial excitation by the transformer.

    Determine (i.e., no-load excitation flux), when the load is added later, the magnetic field generated by the primary side and the magnetic field generated by the paying edge are basically equal in magnitude, and the direction is opposite, and the magnetic field generated by the primary edge and the magnetic field generated by the paying edge.

  8. Anonymous users2024-02-05

    Summary. What is the relationship between the phase of the electromotive force e1 and the main flux m when the transformer is running at no load? Kiss! Hello, happy to answer your <>

    The relationship between the phase of the electromotive force E1 and the main magnetic flux m m during no-load operation of the pro-transformer is as follows: first of all, the voltage, in fact, they are not equal, because there will be a voltage drop on the impedance on the winding, and the input voltage should be higher than the self-induced electromotive force, but because the impedance of the winding is very small, the voltage drop is negligible, so it is approximately regarded as the input voltage is equal to the self-induced electromotive force. I don't know if you're in high school or college, I'll talk about it as much as I can:

    I can only say that we know from the derivation of the formula: e1== is the frequency, n is the number of turns of the coil, m is the magnetic flux, and e1 is the self-inductive potential), and the input voltage is equal to the self-induced electromotive force, so the total magnetic flux of the coil and the input voltage should be proportional and basically unchanged. When the secondary side is unloaded, the secondary side can not produce a variable magnetic flux, and the magnetic flux of the winding is determined by the primary side, that is, the above formula is determined.

    When there is a load, the secondary side produces a changing current, thereby generating a changing self-inductance magnetic flux, and a mutual inductance is generated on the primary side, and the total magnetic flux is constantly changing at the beginning, but from the above, after a dynamic process, the winding magnetic flux will always change back to the magnetic flux at no load, that is, it is always controlled by the input voltage. I'm tired, I haven't read a book for a long time, I hope mine can help you <>

    Do you have any other questions?

    What is the relationship between the phase of the electromotive force e1 and the main flux m when the transformer is running at no load?

    What is the relationship between the phase of the electromotive force e1 and the main flux m when the transformer is running at no load? Kiss! Hello, happy to answer your <>

    The relationship between the phase of the electromotive force e1 and the main flux m m during no-load operation of the pro-transformer is as follows: first of all, the voltage, in fact they are not equal, because there will be a voltage drop on the impedance on the winding, and the input voltage shed circle should be higher than the self-induced electromotive force, but because the impedance of the winding is very small, the voltage drop is negligible, so it is approximately regarded as the input voltage is equal to the self-induced electromotive force. I don't know if you're in high school or college, I'll talk about it as much as I can:

    I can only say that we know from the derivation of the formula: e1== is the frequency, n is the number of turns of the coil, m is the magnetic flux, and e1 is the self-inductive potential), and the input voltage is equal to the self-induced electromotive force, so the total magnetic flux of the coil and the input voltage should be proportional and basically unchanged. When the secondary side is unloaded, the secondary side can not produce a variable magnetic flux, and the magnetic flux of the winding is determined by the primary side, that is, the above formula is determined.

    When there is a load, the secondary side produces a change of current, thereby generating a change of self-inductance magnetic flux, and a mutual inductance is generated on the primary side, and the total magnetic flux is constantly changing at the beginning, but by the aforementioned, Yuhe only after a dynamic process, the winding magnetic Qingpeitong will always change back to the magnetic flux at no-load, that is, it is always controlled by the input voltage. I'm tired, I haven't read a book for a long time, I hope mine can help you <>

    Do you have any other questions?

    What is the load operation of a transformer?

    The load operation of the pro-transformer refers to the working condition when the primary winding is connected to the power supply voltage and the secondary winding is leased to the load.

  9. Anonymous users2024-02-04

    When there is a load, the main magnet of the transformer is generated by ().

    a.Which song current is contained in the primary winding.

    b.Secondary winding current.

    c.The primary winding current and the secondary winding current are slowed down together.

    Correct Answer: The primary winding current is the same as the secondary winding current.

  10. Anonymous users2024-02-03

    Answer]: The frequency of the main magnetic flux of the transformer is consistent with the frequency of the power supply voltage, and its amplitude is also affected by the power supply voltage, u e; In addition to the core loss of the transformer envy pressure device and.

    In the case of the resistance and leakage flux of the primary and secondary windings, it can be seen from this equation that the amplitude of the main magnetic flux of the transformer is basically equal when the two operating conditions of no load and load are basically equal.

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