Who will know how to solve this problem! This question will not be, solve!

The first time B says he doesn't know, the product is not a prime number or 4 (it can only be 1*4, and the reason is the same as 4), A says he doesn't know for the first time, and the sum is not (only 1+4 and 2+3, but the product of 1+4 is 4 has been excluded by B saying he doesn't know, so if it is 5, A must be able to guess it) or 6 (only 1+5 and 2+4, and 1+5 can already be excluded by B saying that he doesn't know, so if it is 6, A must be able to guess it).

At this time, B said that he knew, then there must be only two ways to split the product in B's hand, and one of them has been denied by A, so considering that the product is 6, it can be split into 1*6 and 2*3, and 2+3=5 has been negated, at this time B guessed that it was 1 and 6 (there are two ways to split and the product of two prime numbers, but there is no negated splitting).

A, on the other hand, must have known B's inference process according to the above reasoning, and therefore also knew it.

So it's 1 and 6

In addition, I want to say that sanshi030258 should be seen clearly, and the title includes 1, which means that your first step of reasoning will not be valid (if there is 1, there are also two divisions of the product of two prime numbers).

4, 13 (sum is 17, product is 52).

4,37 (sum is 41, product is 148).

4, 61 (sum is 65, product is 264).

8,89 (sum is 97, product is 712).

16,13 (sum is 29, product is 208).

16,37 (sum is 53, product is 592).

16,43 (sum is 59, product is 688).

16,73 (sum is 89, product is 1168).

16,97 (sum is 113, product is 1552).

This is an ancient mathematical problem, and the title is as follows: "One day, Guiguzi chose 2 numbers out of the 99 numbers from 2 to 100, and then told Pang Juan the sum of them and Sun Bin the product. Of course, Pang Juan didn't know what the product was, and Sun Bin didn't know how much the sum was.

On the second day, Pang Juan met Sun Bin, who was very arrogant, and said, "Although I don't know what these two numbers are, I'm sure you don't know either." Sun Bin immediately shot back

I didn't know, but now I know what those two numbers are. Pang Juan thought for a while and said, "Now I also know what these two numbers are."

1.Pang Juan said I don't know these two numbers, but I'm sure you don't know either, which means that two numbers cannot be prime at the same time, so the sum of the two numbers cannot be even, that is to say, the sum of the two trees must be odd, that is, these two numbers must be one odd and one even.

2.Sun Bin said that I didn't know these two numbers originally, but since you said so, then I now know that this shows that there is only one of the various decompositions of Sun Bin's product, which is one odd and one even, so this product must eventually be written as a prime number * (2 n) 3Pang Juan said: Oh, then I know too.

This shows that only one of the various decomposition cases of Pang Juan's sum is in the form of prime number +2 n, so like 11, because it can be decomposed into 3+8 or 4+7, it does not meet the requirements, and finally the result is as follows:

4, 13 (sum is 17, product is 52).

4,37 (sum is 41, product is 148).

4, 61 (sum is 65, product is 264).

8,89 (sum is 97, product is 712).

16,13 (sum is 29, product is 208).

16,37 (sum is 53, product is 592).

16,43 (sum is 59, product is 688).

16,73 (sum is 89, product is 1168).

16,97 (sum is 113, product is 1552).

But the sum maximum is 102, so the last combination does not appear.

This question has a very similar question, but I don't know the answer.

What's the question? What's the question? What's the question? What's the question? What's the question? What's the question? What's the question?

At the very least, you need to know what the topic is.

Which question? How do you write it?

Oh broken, oh you Mozi www people do the most in the real meat in the real.

1）cos∠cab=2cos²∠cad-1cos∠cab=3/5

then the spike rolls cos cad=2 5 5

ad=ac/cos∠cad=3/(2√5/5)=3√5/22）ap=x

c'd=cd=3/2

sδapd=1/2*ap*c'd=3x 4 defines the domain 03) when ap=ad=3 5 2, it is an isosceles triangle.

When guessing the liquid ap=pd, it is also an isosceles triangle.

ap²=c'd²+(ac'Beizi-AP).

ap²=9/4+(3-ap)²

Get ap=15 8

The area of the block is represented by , and the same is true for the rest of the blocks, and the white block between in the diagram is set to , then.

+=16 2=8 (large semicircle).

+=4 2=2 (small semicircle).

+=32 2-(16-4 )=4 Add the above three formulas.

+=14 =32-(16-4 )=16+4 Subtract these two equations to obtain the shaded area.

You should choose B for this question, you are doing the right thing, because the pressure is equal, D is excluded. And because the force area of A is larger, the pressure is smaller, and C is excluded. The derivation process of option B is as follows, and I hope to click to adopt.

The answer is A

Then the volume ratio of the two substances is 2 9:3 4

According to the pressure formula p=f s, when the pressure is equal, the ratio of the pressure of matter A to the pressure of matter B is equal to the inverse ratio of their base area, because it is a cube, the pressure ratio is 9 2:4 3=2:3

I chose C, thinking back to the past, this question was still from me.

The divisor + the dividend is equal to 599-15-12 and is equal to 572