8 9 16 20 22 27 What is the next number in the sequence, process

Updated on educate 2024-06-13
14 answers
  1. Anonymous users2024-02-11

    Personally, I think it's 26 because you look at it in two.

    If it is a series of numbers, then it should come according to a certain law, where (1) in 16-8 8, 22-16 6, then the difference between the next number minus 22 should be 4, so the next in (1) is 26, in the same way, in (2) 20-9 11, 27-20 7. So the difference between the next number and 27 should be 3, so the next one in (2) should be 30, and because (1) is ranked first, 26 is in front of 30, that is.

    This is a personal understanding and can be communicated!

  2. Anonymous users2024-02-10

    The formula for this series is -(1 15)*(n-2)(n-3)(n-4)(n-5)(n-6)+(3 8)*(n-1)(n-3)(n-4)(n-5)(n-6)-(4 3)*(n-1)(n-2)(n-4)(n-5)(n-6)+(5 3)*(n-1)(n-2)(n-3)(n-5)(n-6)-(11 12)*(n-1)(n-2)(n-3)(n-4)( n-6)+(9 40)*(n-1)(n-2)(n-3)(n-4)(n-5); Substituting n=7 is sufficient, 188

  3. Anonymous users2024-02-09

    Rules: 2 = 3-1, 8 = 3 squared - 1, 26 = 3 to the 3rd power - 1, 80 = 3 to the 4th power - 1.

    So the nth number is 3 to the nth power -1.

  4. Anonymous users2024-02-08

    It is known that the number of a column is 2,8,26,80 ......According to this law, the nth number is 3n 1, which is a typical number series problem, and you must study hard to be correct!

  5. Anonymous users2024-02-07

    The first silver or the regular cluster of this column of numbers.

    The first: 2=1 2

    Second: 6 = 2 3

    The third: 12 = 3 4

    Fourth: 20 = 4 5

    Fifth: 30 = 5 6

    Rule: The nth is n(n+1).

    Answer: The 20th is 20 (20+1)=420, and the 99th is 99 (99+1)Edge=9900

  6. Anonymous users2024-02-06

    Summary. Are you sure it's this set of data?

    There is a column of numbers 1, 8, 64, 216 ......What is the 20th number.

    Are you sure it's this set of data?

    Or there's something to come.

    I took a closer look at the data that seemed to be irregular.

    I'm so sorry that the answer I gave earlier was wrong. The correct answer is elimination: the law of this column is a n = 2, where a n is the n$ number.

    Because of this, the value of the 20th number is a =2 =2 =2 =2 =144,115,188,075,855,872.

    I would have thought of this rule.

    But 216 doesn't.

  7. Anonymous users2024-02-05

    The answer is Wild Chop 1 570=285*2;285=57*5;57=19*3.That is, 570 = 19 * 3 * 5 * 2 * 1The latter instructors are all 570 factor stupid spine pure.

  8. Anonymous users2024-02-04

    According to the law of the topic, we can get the following data.

    And so on, we can tell that it loops every 20 digits, and when the ten digits are odd and the single digit is 6, then the last number can be deduced as 96

    So there are 21 numbers in total.

  9. Anonymous users2024-02-03

    The number series can list a 4-element system of equations, (the process is more complicated, so it will not be written here).

    The solution is an=

    a5 = test: a1 = 21

    a2=1a3=8

    a4=27I hope it helps you, I wish you progress in your studies!

  10. Anonymous users2024-02-02

    There is no law to this, it is possible that 21 is not in the number sequence, that is the cubic number relationship, choose b

  11. Anonymous users2024-02-01

    Is 21 a question number, and the books behind are all cubes of natural numbers, that is, 1 cube is 1, 2 cubes is 8, 3 cubes is 27, and 4 cubes are 64 in the back, choose B

  12. Anonymous users2024-01-31

    b, the first term is not in the law of , is the change in the number of cubes.

  13. Anonymous users2024-01-30

    1=1 to the 3rd power.

    8 = 2 to the 3rd power.

    27 = 3 to the 3rd power.

    Therefore, fill in the parentheses 4 to the 3rd power.

    So choose B

  14. Anonymous users2024-01-29

    Think of 2 as 4 2, 8 as 16 volts 2, and 18 as 36 2 to get a new sequence.

    Have you found a pattern? If you don't find it, take another step.

    The table of the number series is the Chada style of this hall.

    Divide the square of n by 2

    So the 20th number.

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