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1 Two straight lines intersect and are equal diagonal.
2 Two straight lines are parallel, straight lines intersect, and the inner wrong angles are equal.
3 Two straight lines are parallel, straight lines intersect, and the isotopic angles are equal.
4. Two straight lines are parallel and intersect in straight lines, complementing each other with the wrong angles in the side.
5 Arbitrary triangle inner triangle and 180 degrees.
6 Sharp angles and 90 degrees inside a right triangle.
7 If two triangles have two equal inner angles, then they are similar.
8 If two triangles have two equal inner angles and one side equal, then the two triangles are equal.
9 If two triangles have equal inner angles and equal two sides, then the two triangles are equal.
10 If two right-angled triangles have equal sides, then the two triangles are equal.
11 The sum of the squares of the two right-angled sides of a right-angled triangle is equal to the third square.
12 The midpoint of a line segment bisects the line segment.
13 The perpendicular line of a line segment is bisected and perpendicular to the segment.
14 The midpoint of the circle is past the center of the circle and the distance to the circle is equal.
15 The opposite sides of the square are parallel, and the adjacent sides are perpendicular to each other, and the four corners are right angles, and the four sides are equal.
16 The rectangle is parallel to each other, the adjacent sides are perpendicular to each other, and the four corners are at right angles, and only the opposite sides are equal.
17 The sum of the four interior angles of a parallelogram is equal to 360
18 Parallelograms are complementary, with equal diagonals and equal opposite sides.
19 The upper and lower sides of any trapezoidal shape are parallel, and the left and right sides are hypotenuse, and the extension intersects.
20 The upper and lower sides of the right-angled trapezoid are parallel, and one hypotenuse is perpendicular to the upper and lower bottom edges.
21 The upper and lower sides of the isosceles trapezoidal shape are parallel, and the two hypotenuses are equal.
The questions and answers are all in there, make them up yourself.
I don't know if it meets your requirements, look at it, I did my best!
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Wouldn't it be okay to buy a test paper?
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Extend the BE to cf to G
Because of the right triangle abc, abc=90°, and because of equilateral abe, abe=60°, cbg=180°-90°-60°=30°
Because the equilateral triangle is bcf, so bcf=60°, so cgb=90° so be cf
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1.In the triangle ABC, An is the angular bisector of the angle BAC, Bn is perpendicular to AN, and M is the midpoint of BC, connecting MnKnowing ab=6, bc=10, mn=2, what is the perimeter of the triangle abc?
Answer: Solution: An is the bisector of the angle bac.
ban=∠can
bn vertical with an
bna=∠cna=90°
In ABN vs. ACN:
ban = can (verified).
an=an(common edge).
BNA = CNA (including which Kai has been verified).
abn≌△acn(asa)
ab=ab=6 (the corresponding sides of congruent triangles are called equal) bc=10
Circumference of ABC = 6 x 2 + 10 = 22
2.The three angular bisectors of the triangle ABC AD, BE, CF, intersect at a point O, OG perpendicular BC to G, and try to prove that the angle BOD = the angle COG
Answer: OG is perpendicular to BC.
cog=90°-∠ocg=90°-1/2∠acb=90°-1/2(180°-∠bac-
abc)=1/2∠bac+1/2∠abc;
bod= bao+ abo=1 2 bac+1 2 abc);
So: bod= cog.
This question mainly examines the knowledge of the properties of the inner and outer angles of the triangle. 】
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1) Set the vertical x and the horizontal y
4x+3y=340
x+2y=160
x=40;y=60
2)4x+3y=n
x+2y=160
290 Xie Zhou Shi n = 640-5y; 290<640-5y<306;Censen Limb y<70
When y=67; x=26;n=305。Chuntuan when y=68, x=24, n=300When y=69, x=
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E is constant, it should be a fixed value, because ADE does not change, DPE does not change.
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How can the three corners of this picture be equal, this look will know that it is wrong. Because it should be 2 times the angle e
Angle ACB Angle B
31 pcs. Drawing is more complicated, and it is straightforward to reason: >>>More
a) Calculation:
1)a-(a-3b+4c)+3(-c+2b) >>>More
Choices of 4,123 prove that the two triangles are equal. If you want to know the process in detail, please ask, thank you!
x=a+b+c
x-b-c )/a +(x-c-a )/b + x-a-b )/c[(x-b-c-a)+a]/a+[(x-c-a-b)+b]/b[(x-a-b-c )+c]/c >>>More
This problem is not easy for me to do, you can think about it again, I do it in two steps, even pb to make a small circle to m, even ap, qb >>>More