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Anonymous users2024-02-13People's Education Publishing House**, here is every page of the teacher's book**, very clear. However, it is a bit difficult to find the answers to the exercises after class, because the textbook analysis and the answers to the exercises are not separated.
When you open the web page above, the following directory will appear:
Chapter 1 Sets and Function Concepts.
1. Overall design.
2. Textbook analysis.
1 1 Collection.
1 2 Functions and their representations.
1 3 Basic properties of functions.
Practicum Assignment 3 Self-test questions.
4. Expand resources.
Chapter 2 Basic Elementary Functions ( ).
1. Overall design.
2. Textbook analysis.
2 1 Exponential function.
2 2 Logarithmic functions.
2 3 power functions.
3. Self-test questions.
4. Expand resources.
Chapter 3 Application of Functions.
1. Overall design.
2. Textbook analysis.
3 1 Functions and Equations.
3 2 Functional Models and Their Applications.
3. Self-test questions.
4. Expand resources.
You click on each chapter under it"2. Textbook analysis. ", and then gradually turn the page to the solution to the problem after each lesson, and then print out the diagram of the page with the solution. It's a bit of a hassle, but there's really no other way.
Due to the limited time today, I can't help you paste every page with the answer for the time being, if possible, I can paste it for you another day. I'm sure you won't fool yourself with the answers, though. All in all, I wish you good luck in your studies!
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Anonymous users2024-02-12Is your book a human-taught version?
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Anonymous users2024-02-11Square both sides first, then multiply DC at the same time, and vice versa.
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Anonymous users2024-02-10Answer: (1).
1+sina/1-sina
1+sina)/[(1-sina)(1+sina)]=(1+sina)/cosa
2）1-sina/1+sina
1-sina)/[(1-sina)(1+sina)]=(1-sina)/cosa
Root number 1 + sina 1-sina - root number 1-sina 1 + sina = |(1+sina)/cosa|-|1-sina)/cosa|=(1+sina)/|cosa|-(1-sina)/|cosa|=2sina/|cosa|
a is the second quadrant angle, cosa<0
Original = 2sina (-cosa) = -2tana
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Anonymous users2024-02-09The root number on the left is multiplied by the same (1+sina), and the right (1-sina) can be opened and classified for discussion.
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Anonymous users2024-02-08a=a/√a √b = b/√b
Rule. a b-b b+b a-a big guess a(a-b) b+(b-a) command bridge a
a-b)/(1/√b-1/√a)
If a>b, then 1 b-1 a>0, so the original formula "0 if a proves the simplified type.
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Anonymous users2024-02-07Hehe, inequality was the homeroom teacher's favorite at that time, and you can do this step.
Now, you move the root number ab to the right.
Move the root number A + the root auspicious dust number B to the left.
That becomes a matter of proof.
A+B-Root number AB is greater than or equal to the root number AB
Isn't this the root number AB where A+B is greater than or equal to 2 times the infiltration?
Does the doll understand??
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