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Anonymous users2024-02-13Oh, it's a competition question, the question has a pattern, each number in the question is a 10-digit number, and the last one can be seen as a 0864219753 (starting with 0). The first five digits of each number are different combinations of 8,6,4,2,0, and the last five digits are different combinations of 7,5,3,1,9, and they all happen to be one after another in order, for example, the first 5 digits of the first number are 86420 (starting with 8), and the first 5 digits of the second number are 64208 (starting with 6, 6 is after 8, so that 8 is at the end), and the title is just five numbers. (The proposer specially made 5 numbers, otherwise it could not be a competition question).
Since they are different combinations of numbers, their sums must be the same because they are in order. We know that the first 5 digits 8, 6, 4, 2, and 0 are all 20 no matter how they are combined (the sum of each of the first 5 digits is 20). The last 5 digits 7, 5, 3, 1, and 9 are all 25 no matter how they are combined.
Well, now the answer is almost out. Find the average, divide each by 5, then the average of the first 5 digits is 4, and the last 5 digits are 5, so the answer is 4444455555. (There are 5 4s and 5 5s).
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Anonymous users2024-02-12Five numbers, each with ten digits, and the last one is seen as starting with 0.
Look at the first place, 86420Sum 20
secondary, 64208Sum 20
third place, 42086Sum 20
Then the top five is 44444.
The last five digits are the same, 13579 and 25, with an average of 5
That's five 5sOverall, it's 4444455555
Uh, I said this, you look at Sa
I didn't use a calculator or anything like that, I just looked at it and got the answer.
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Anonymous users2024-02-11First of all, average the two numbers starting with 8, and add the numbers that start with 2 to average, add and average the numbers that start with 6 and 4, and finally average them.
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Anonymous users2024-02-10There is no easy way, simple is easy to make mistakes, and stupid methods are absolutely not wrong.
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Anonymous users2024-02-09Let the maximum number be a, and the rest of the numbers are b, c, d Obviously, the rubber row a+(b+c+d) 3=135 , and there are three other equations The four equations are added to get (a+b+c+d)*2=414 (a+b+c+d) 3=69 to get the acorn, a=99 ....Liang Ruran.
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