Ask the girls to answer the question and answer the urgent !!

It depends.

There are many girls who have menstrual cramps.

Some will be severe.

Painkillers don't always work, and a friend of mine once had a pain that almost went into shock.

You can't go out at this time!

That's right. Girls may leak when they are active, so it's troublesome

Hehe, anonymous question, I'm also curious.

Hehe, if it happens to be a period, I won't go out.

I'll stay at home for a few days.

Because I have menstrual cramps, it's not convenient to go out and play.

The girl I know is the same as you say. It's usually pretty good. It's just those days. will refuse.

Of course I went, I came to that, so naturally I had to play with my temper, buy some gadgets, and make up for my meals, and eat well.

Go, don't affect it at all, if the girl uses this reason to reject you, then it must be that the girl doesn't want to go.

I'm also a man, and I'll see how girls are

Girls usually have emotional instability when they menstruate, but it depends on her mood to ask her out to play!

Why don't you go? What's wrong with that? I don't think coming here will affect my normal life at all.

The physical education class also has to be a physical education class. Girls aren't that vulnerable. Just don't be overly intense.

Girls in general don't mind. When you meet a little girl, you may be concerned.。。。 So you have to think clearly.

This looks at people, some girls are in good health, menstruation has little effect, and menstruation is still alive and kicking. But some girls have the so-called women's disease, and they are in pain to death when they menstruate, and they are in a bad mood, and there are many such girls.

I'm a man, I want it too, it's still okay to watch movies on the street, just swim and play.

84 24 = (84 6) (24 6), 84 24 = (840 6) (240 6), the divisor and the divisor are the same when the multiples are enlarged to indicate that the knowledge quotient is unchanged.

Note that 34 + 26 = 60

So tan60°=tan(34°+26°), i.e. 3=(tan34°+tan26°) 1-tan34°tan26°).

i.e. tan34°+tan26° = 3 (1-tan34°tan26°) thus tan34°+tan26°+ 3tan34°tan26°= 3

First, let's analyze the structure of this sentence:

made is a verb predicate.

His parent is the object.

Very angry is an object complement (the role of modifying the object).

So, what is missing from this sentence?

Subject! That is, "the same mistakes again" should be the subject of this sentence.

In this way, choosing d is exactly the subject of the subject, and if you choose any of the abc terms, then the part in the double quotation marks I typed above will become a single sentence, and cannot become the subject of the whole sentence.

Because this is a simple sentence, not a clause, the subject must not be a complete sentence.

But if the sentence has that (one of the symbols of the clause) between again and made, then you should choose b instead of d.

I don't know if you understand it, if you haven't learned the clause, then you should have more difficulty understanding, the clause should be taught from the third year of junior high school, and it is the key content of high school.

a∩a=a a∩ø=ø a∩b=b∩a b∩a=a∩b

a∪a=a a∪ø=a a∪b=b∪a b∪a=a∪b

Have you learned to assemble?

Intersection: The intersection of two sets A and B is a set that contains all the elements that belong to both A and B, and nothing else. Writing at the intersection of A and B"a ∩b"。

Formally: x belongs to a b if and only if x belongs to a and x belongs to b. For example:

The intersection of the set and is . The number 9 does not belong to the intersection of the set of prime numbers and the set of odd numbers {1, 3, 5, 7, 9, 11}. If the intersection of two sets A and B is empty, they do not intersect because they have no common element.

More generally, intersection operations can be performed on multiple sets at the same time. For example, the intersection of sets a, b, c, and d is a b c d a (b (c d)). The intersection operation satisfies the associative law, i.e., a (b c) (a b) c.

The most abstract concept is the intersection of sets of arbitrary non-empty sets. If m is a non-empty set, and its elements are themselves sets, then x belongs to the intersection of m, and if and only if for any element a of m, x belongs to a.

2a b +2b c +2c a -a 4-b 4-c 4=-(-2a b -2b c -2c a +a 4+b 4+c 4)=-[(a -b) 2c (a +b )+c 4] There is a problem with the question, if yes:

2a²b²+2b²c²+2c²a²-a^4-b^4-c^4=-(2a²b²-2b²c²-2c²a²+a^4+b^4+c^4)=-[(a²+b²)²2c²(a²+b²)+c^4]=-（a²+b²-c²)²