The surface of a cuboid is painted red, divided into 18 small squares, and there are a few that are

Hello! It depends on what kind of cuboid, if the ratio of the length to width of the cuboid is 1:18, then after being divided into small squares, there is no side painted red, if the ratio of length, width and thickness of the cuboid is 1:

2:9, then no piece is painted red on one side, if the ratio of the length to width of the cuboid is 3:6:

1, there is still no one side painted red, there is only one possibility: the ratio of length, width and thickness of the cuboid is 3:3:

2. After dividing into 18 small squares, only two small squares are painted red on one side!

If it helps you, hope.

2 pieces on 1 side. 8 blocks on 2 sides.

8 blocks on 3 sides. The three sides are the eight pieces with 8 vertices.

There is one 2-sided between every two adjacent 3 sides.

One side is the core of the middle.

The bottom ones are divided into 9 pieces like a "well", and you don't seem to be able to explain how these 18 small squares are divided. Then the answer is.

Shadow is given. (I don't say the specific division, but there may be 14.) , if it is a different division. The answer could be 0. After all, the conditions you have listed are not rigorous enough, so there are many possible answers.

If it is divided on.

How can there be a red side, how to say that the least surface also has 3 sides, the cuboid has a total of 6 sides, you have 9 pieces above, 9 pieces below, and the red side still has at least 3 sides.

Go downstairs, 9 pieces above, 9 pieces below, very good to divide, such as a piece of tofu, a knife from the middle, and then cut 9 knives to 18 pieces.

How do you divide the 9 pieces above and the 9 pieces below??

Separate like the word "tic-tac-tac"?? Or divide it into 9 portions directly along a certain side.

The conditions should be clearly explained.

Solution: Let this cube be cut into n small squares with edges long, then the colored surfaces of these small cubes are:

Coloring on three sides: 8 pcs.

Two-sided coloring: (n-2) 12

Color one side: (n-2) 6

No coloring: (n-2).

When n is 10, then.

Coloring on three sides: 8 pcs.

Two-sided coloring: (10 2) 12 = 96 pcs.

Coloring on one side: (10 2) 6 = 384 pcs.

No coloring: (10 2) = 512 pcs.

Only the wooden block on the edge has 2 colored sides, a total of 12 edges, the opposite two faces are the same length, at least 3, then there are a total of 8 cubes on the two opposite faces 2 sides colored, there are 8 left, and there are 2 sides of the side 4 sides on each side, so the side edge length is 4.

So this box can only be 3*3*4=36 blocks.

After painting the surface of a large cuboid block in red, and dividing it into several small cuboids of the same size, only two of which are painted red on the small cube are exactly 16 pieces, then at least this large rectangle should be divided into pieces.

24 small cuboids Test points: dismantling and assembling (cutting and stitching) of figures; the surface area of the cuboid and the cube; Logical reasoning Analysis: Since the cuboid with only two sides painted red can only be located in the middle of each edge, the cuboid is divided as shown in the following figure:

The number of cuboids divided sequentially is , then the number of blocks divided in Figure (4) is at least 24, and there are exactly 16 cuboids painted red on both sides

Answer: Solution: As can be seen from the above figure, only two small cubes painted with red are exactly 16 cuboids with the following types: the number of small cuboids is , all of which meet the conditions, but at least this large rectangle should be divided into 24 small cuboids;

Answer: At least this large rectangle should be divided into 24 small cuboids, so the answer is: 24

If the length of the cuboid is 3+2=5, the width is 1+2=3, and the height is 1+2=3, then the volume is 5 3 3 = 45

At first, I thought it was a cube and scared me to death. Obviously, the height is 1+2=3, the length is 3+2=5, the width is 1+3=3, and the result is 3*5*3=45

5 in length, 3 in height, 3 in width, multiplied to get 45 cubic meters.

The three-sided ones are definitely on the horns: 8.

The two sides are on the edge, and the length of each side minus two is all added up, and the length, width and height are 4 each

6-2) + (4-2) + (5-2)) * 4 = 36 on one side: ((6-2) * (5-2)) + 6-2) * (4-2)) + 5-2) * (4-2))) 2 = 52.

There are 8 painted red on three sides (which are the 8 fixed angles of the box);

16 are painted red on both sides (12 edges of the cuboid, of which the 4 long edges have 2 on each edge);

There are 10 red ones on one side (6 sides of the box, of which the larger one has 2 on each side);

There are 2 that are not painted red at all (the rest are not painted).

Three-sided: The colored ones are the corners of the box, and the cuboid has a total of 8 corners, so there are 8 small cubes painted red.

Two-sided: The perimeter of the cuboid - 8 cubes painted on three sides = 4*(5+6+7)-8=64

One side: the remaining cube = 2 * 5 * 6 + 2 * 6 * 7 + 2 * 5 * 7-64-8 = 142

One side: 2 3 4 + 4 5 + 5 3 = 94 pieces, two sides: 4 3 + 4 + 5 = 48 pieces, three sides: 8 pieces.

40 pcs. The small cube without red must be inside the cuboid.

The small cube with red on both sides must be on the edge of the cuboid.

When 8 cubes without red are arranged in a long strip, the size of the large cuboid is 3*3*10, and 4*8+8=40 on the edge is the most.