How many tons of a 10 ton object falls from a height of 10 meters to the ground

A 10-ton object falling from a height of 10 meters to the ground is still 10 tons.

At a height of h above the ground, mg is not taken into account when the influence of the Earth's rotation is not considered'=f=gmm/(r+h)²；And at the ground mg=gmm r. Strictly speaking, a 10-ton object will be a little heavier than a 10-ton object after falling to the ground from a height of 10 meters, because (r+h) >r. However, since the radius of the earth r is much larger than h, it can be approximated that (r+h) = r.

So it can be said that a 10-ton object falling from a height of 10 meters to the ground is still 10 tons.

The law of gravitation: any two particles are attracted to each other by a force in the direction of a concentric line. The magnitude of this gravitational force is directly proportional to the product of their masses and inversely proportional to the square of their distance, independent of the chemical composition of the two objects and the type of medium in between.

The discovery of the law of gravitation was one of the greatest achievements of natural science in the 17th century. It unifies the law of the motion of objects on the ground and the law of the motion of celestial bodies, and has a profound impact on the development of physics and astronomy in the future. It was the first to explain the law of a fundamental interaction (one of the four types of interactions in nature) and set a milestone in the history of human understanding of nature.

The law of gravitation reveals the laws of celestial motion and has a wide range of applications in astronomy and in space navigation calculations. It provides a set of calculation methods for practical astronomical observations, which can calculate the orbits of celestial bodies that travel over a long period of time with only a few observations, and the discoveries of Halley's Comet, Neptune, and Pluto in the history of science are all examples of significant achievements in the application of the law of gravitation. Using the gravitational formula, Kepler's third law, etc., can also calculate the mass of celestial bodies that cannot be directly measured, such as the sun and the earth.

Newton also explained the tidal phenomena caused by the gravitational pull of the moon and the sun. Based on the law of gravitation and other laws of mechanics, he also successfully explained the reasons for the flattening of the earth's poles and the complex motion of the earth's axis. Overthrows the gravitational pull of the gods that ancient humans believed.

Are you asking how much impact the ground will have? The instantaneous velocity of the ground v=(2*g*10) is the root number. At that time, the momentum generated = m * momentum is conserved), t is a time, and the elasticity of the ground at the landing point is related, the greater the elasticity t t, the smaller the impact force generated, assuming that the time t of the object from the beginning of the ground to the stop is, then f = m * v t = 10000 * (the root number of 2 ox, f = mg, so m = f g = 140000kg = 140 tons, so it is equivalent to the pressure generated by 140 tons of things piled on the ground.

It's still ten tons, and the quality won't change.

Ignoring the air resistance, first use the energy conservation active mgh (1 2) mv to find the final velocity v of the object, and then use the impulse theorem zhi has ft δmv, where t is the contact time between the object and the ground, it can be seen that the longer the time, the less force is subjected, which is also the reason why the elastic object can be buffered.

Energy is neither created nor disappeared out of thin air, it can only be transferred from one object to another, and the forms of energy can also be converted into each other.

As a result of the law of conservation of energy, the first type of permanently moving machine cannot exist (such a machine does not consume any energy, but can do a steady stream of external work). For equations of motion without translational symmetry of time, it may not be possible to define conservation of energy. Examples include curved space in general relativity or time crystals in condensed matter physics.

The object is balanced, the mass remains unchanged at 100kg when it lands, and the gravity is 1000N

How much does it weigh? Is it the speed of landing? Still is?

First of all, the gravitational force of an object does not change, and it is its impact force that makes the limb surface in the world.

Suppose air resistance is ignored.

You can get mgh=mv 2, so the final velocity is 2gh=40 meters to search for seconds, and then use the impulse theorem fδt = δmv, if the action time is seconds, the impact force is 40 75 .

The weight is still 100 catties, but the impulse generated Impulse = m * v (mass * end velocity).

With a free-fall bench, acceleration, ignoring air resistance, keeping the object in shape unchanged when falling, ignoring the change in the gravitational pull of the Earth and the Moon on the object, ignoring the centrifugal phenomenon of the object when the ground collapse front ball rotates.

When the object falls to the ground, it is equivalent to a force of more than 400 catties pressing on the surface.

About 44 seconds.

According to Newton's law, if an object falls at a high altitude without considering air resistance, then the object moves freely, regardless of the weight of the object.

According to the formula of time in free fall in the theory of Wuhu Yun, h=1, 2gt, 2. That is, t 2 = 2h g = 2 10000 seconds 2, both sides open at the same time, about 44 seconds.

Summary. The weight remains the same.

What is the weight of an object weighing 100 kilograms, falling from a height of 30 meters, to the ground? How is it calculated?

The weight remains the same. Or mg=100*10=1000, I hope it will help you, if you don't know anything, you can consult the teacher Oh By the way, move Lao Min or move your little hand to give the teacher a thumbs up, thank you

The gravitational force experienced by an object on Earth is constant. The gravitational force on a 12kg object should be g=mg=12*N.

If the resistance of the air is not taken into account, the root accompaniment and the relationship between the height of the free fall and the time are as:

h = 1/2 * gt²

Get: t = 2h g = 2 * 8000 = 80000 49 So: Lu Mark.

t = 80000 49) = 200 slippage 2 7 seconds).