What should I do if I have high numbers or something!!!!!!

Mathematics: Theorems in textbooks, you can try to reason on your own. This will not only improve your proof ability, but also deepen your understanding of the formula.

There are also a lot of practice questions. Basically, after each class, you have to do the questions of the after-class exercises (excluding the teacher's homework).

Listening: You should grasp the main contradictions and problems in the lecture, think synchronously with the teacher's explanation as much as possible when listening to the lecture, and take notes if necessary

Reading: When reading, you should carefully scrutinize, understand and understand every concept, theorem and law, and study together with similar reference books for example problems, learn from others' strengths, increase knowledge, and develop thinking

**: To learn to think, after the problem is solved, then explore some new methods, learn to think about the problem from different angles, and even change the conditions or conclusions to find new problems

Homework: Review first and then homework, think first and then start writing, do a class of questions to understand a large piece, homework should be serious, writing should be standardized, only in this way down-to-earth, step by step, in order to learn mathematics well

In short, in the process of learning mathematics, we should realize the importance of mathematics, give full play to our subjective initiative, pay attention to small details, develop good mathematics learning habits, and then cultivate the ability to think, analyze and solve problems, and finally learn mathematics well

In short, it is a process of accumulation, the more you know, the better you learn, so memorize more and choose your own method.

Good luck with your studies!

Ask more teachers, read more books! Go to the library more often, the learning environment there is great!

The key is to understand, to be fine... Do more questions...

,g(x)=2 x,discontinuous at x=0,negate c,d piecewise function f(x)= -x, when x<=0; x+1 when x>0;

g(x)= 1+x, when x<=0; -x, when x>0;

is interrupted at x=0, but f(x)+g(x) and f(x)*g(x) are continuous at x=0.

2.cy = x (1 3) one-third of x is not derivable at x = 0, but the tangent exists, which coincides with the y-axis;

Of course, it may not exist, such as y=|x|At x=0 it is not derivative, and the tangent does not exist.

Method 1: Use the mixed product of the coplanar vector to be 0. Point a(3,1,-2) on a straight line point b(4,-3,0) The direction vector of a straight line n(5,2,1), any point c(x,y,z) on the plane can be known, vector:

ab, n, and ac are co-faceted quantities, so their mixed product is 0, from which a third-order determinant is obtained, and the plane equation can be obtained by simplifying this determinant. The solution process is omitted.

Method 2: Same as above, use the cross product of n and ab to find the normal vector of the plane, and then use the point formula of the plane to solve. The solution process is omitted.

Method 3: Use the planar cluster method to solve the problem.

There are an infinite number of planes that cross a straight line (x-4) 5=(y+3) 2=z 1, and we are asking for only one of them.

The expression for a planar cluster can be as follows: 2x-8-5y-15+k(2z-y-3)=0, where k is the coefficient to be found.

At this point, we just need to bring the point (3,1,-2) into the above equation and find the corresponding k value, where k = -11 4

So we bring k=-11 4 into the above equation and simplify it to get 8x-9y-22z+59=0

It should be noted that this planar cluster does not contain the plane 2z-y-3=0, but we don't say anything about it, because if we can't solve the corresponding k value in the above equation, then we can be sure that the plane 2z-y-3 is the plane we need! (Just think about why you say that).

For example, if the coordinates of the point (3,1,-2) become (2,-1,0), if we bring it in, we find that -14=0 will appear, which means that this point is not on our plane cluster, but because the plane cluster we give only misses the plane 2z-y-3=0, we also know that a straight line and its outer point must determine the displacement of a plane, at this time it is obvious: the plane must exist, and the other planes except 2z-y-3=0 are not satisfied, Then 2z-y-3=0 is of course the plane that satisfies the conditions, as for whether it is or not, the method is very simple, just bring the coordinates of the point into the calculation!

Proof: Take any x (0, +infinity).

f(x)=f(x^2)=f(x^4)=f(x^8)=……=f(x^(2^n))

1.When x (1, +infinite), x > x

So, lim(n->infinity) x (2 n) = x (+ infinity) = + infinity f(x) = f(x 2) = ......=f(x (2 n))=limf(x) (x->+infinity) =f(1).

2.When x (0,1), x infinity) x (2 n) = x (+ infinity) = 0f(x) = f(x 2) = ......=f(x^(2^n))=limf(x) (x->0） =f(1)

So, f(x) = f(1) is constant and x belongs to (0,+infinity).

It is divided into two parts, one part is 1 root number (...).The other part is (arcsinx) 3 root number (....)The first part is arcsinx, substitute the upper and lower limits to do it yourself, and the back part puts 1 root number (....)I got to the back of D and became (arcsinx) 3D (arcsinx), and I don't need to say it, I think it will be done.

It can be calculated by applying the properties of the integral of the parity function in the symmetry interval.

Is it about the limit? If it's about limits, o denotes the higher-order infinitesimal.

The method is shown in the figure below, please check carefully, I wish you a happy study and academic progress!