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Anonymous users2024-02-13Question 3: First of all, with the number of students in the whole school 548-365=183 people, even if there is a birthday every day, there will be 183 people who have the same birthday as others, if 183 people have the same birthday, that is, there are 184 people who have the same birthday. Then 63-31 = 22 people, and similarly, 23 people have the same birthday in May.
183-22=161, there are still 161 people who did not find their birthday, and similarly, 162 people have a birthday on the same day other than May. 23 + 162 = 185 people, these 185 people are all people with the same birthday. It is assumed that the current year is not a leap year.
Question 5: Permutations and combinations, at least 6 cards. There is only one in the middle 5. Because 1+9=10;2+8=10；3+7=10;4+6=10.
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Anonymous users2024-02-12Question 3, to be honest, this question sounds ambiguous, 63 31>2, then there are at least 3 people with the same birthday in May, 548-63 = 485,485 (365-31)<2, then at least 2 people have the same birthday in the whole year, take the greater value, so it is (3).
But this question can also be understood as as long as there are many people with the same date and birthday, that is, 63 2>2 (all May may have the same birthday) 63 people, (548-63) -365-31) = 151 (excluding at least 151 2 = 302 people with the same birthday in May), 63 + 302 = 365, but given that there may be 366 days in a year (leap year), it can only be inferred to the first meaning, otherwise there will be 2 answers.
So the final answer is 3
Question 5, the last sentence "in order to ensure that the sum of two numbers is 10" is a bit chewy or ambiguous, and I personally think that (1) card will be selected! Note that the word "must have" is not "arbitrary", and only 5 cannot appear "must have".
Now I don't know what I want to do, this kind of question is not an algorithm problem, it is completely a test of logical thinking.
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Anonymous users2024-02-11May has 31 days.
63 were born in May, i.e. at least 3 people had the same birthday. 63 = 31 * 2 + 1 The number of births in other months is 548-63 = 485
There are 365 days in a year, with the exception of May, which is a total of 334 days.
485 = 334 * 1 + 151, at least 2 people in other months have the same birthday.
So the answer should be 3
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