A breeding group raises a total of 78 chickens and rabbits, with a total of 200 feet.

Known: A breeding group raises a total of 78 chickens and rabbits, with a total of 200 feetA rabbit has two more legs than a chicken

Analysis: Suppose that all the chickens in the breeding group are raised, then,78 chickens have a total of 78*2=156 legs。The 78 chickens and rabbits in the question have a total of 200 legs, which is 44 legs more than the 78 chickens.

That is to sayThese 44 legs are more than chickens in rabbits, ieThere are 44 rabbits 2 = 22 pcsThere are 78-22=56 chickens

Formula:(Total number of feet - number of chicken's feet Total number of feet) (Number of rabbit feet - number of chicken's feet) = number of rabbits

Total number of birds - number of rabbits = number of chickens

Calculation: 22 rabbits, a total of 22 * 4 = 88 feet, 56 chickens a total of 56 * 2 = 112 feet, adding up to 88 + 112 = 200, in line with the conditions of the question.

A: The group has a total of 22 rabbits and 56 chickens.

What is a chicken and rabbit cage?

Chickens and rabbits in the same cage is one of the famous typical interesting questions in ancient China, recorded in the "Sun Tzu Sutra".

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The ancient Chinese Sutra of Sun Tzu consists of three volumes, written around the 5th century AD. The book is easy to understand and has many interesting arithmetic problems, such as the "chickens and rabbits in the same cage" problem:

Today there are pheasants and rabbits in the same cage, there are thirty-five heads on the top, and there are ninety-four feet under it.

There are 35 pheasant rabbits in the question, and if the two front feet of the rabbit are tied with a rope and regarded as one leg, and the two hind feet are also tied with a rope and regarded as one leg, then the rabbit becomes a chicken with two legs, that is, the rabbit is first regarded as a chicken with two legs. The total number of feet of chickens and rabbits is 35 2 = 70 (only), which is 94-70 = 24 (only) less than the 94 mentioned in the question.

Untying the rope on a rabbit's feet will increase the total number of feet by 2, that is, 70 + 2 = 72 (only), and then loosening the rope on a rabbit's foot, the total number of legs will increase by 2, 2, 2, 2, 2 ......and continue until it increases by 24, so the number of rabbits: 24 2 = 12 (only), so that the chickens have 35-12 = 23 (only).

Let's summarize the solution idea of this problem: if you assume that they are all chickens, then according to the total number of chickens and rabbits, you can calculate how many feet there are under the assumption, compare the number of feet obtained in this way with the number of feet given in the question, see how much the difference is, every 2 feet indicates that there is 1 rabbit, divide the number of feet by 2, you can calculate how many rabbits there are.

To sum up, the basic relationship for solving the chickens and rabbits in the same cage is: the number of rabbits = (the actual number of feet - the number of chickens and rabbits in each chicken) (the number of feet in each rabbit - the number of feet in each chicken). Similarly, it can be assumed that it is all rabbits.

56 chickens and 22 rabbits.

Solution: If there are x chickens, then there are 78-x rabbits.

2x+（78-x）×4=200

2x+312-4x=200

312-2x=200

2x=312-200

2x=112

x=112÷2

x = 56 rabbits have 78-56 = 22 rabbits.

Set up x chickens. 2x+4*(78-x)=200

2x+312-4x=200

2x=112

x = 56 chickens and 22 rabbits.

If you don't understand, you can ask, it helps, thank you!

The solution idea, assuming that all 78 are chickens, then the feet are 78*2=156, and the actual is 200 feet, so there must be a four-legged rabbit in it, 200-156=44, because the rabbit has two more legs than the chicken, so.

44 2 = 22, 22 rabbits, 78-22 = 56, 56 chickens.

The equation is relatively simple.

Let there be x rabbits, then chickens are (78-x) rabbit feet are 4x, chicken feet are 2 (78-x) The equation is: 4x+2(78-x)=200

4x+156-2x=200

4x-2x=200-156

2x=44x=22

Chickens: 78-22=56.

Do you understand?

Answer: There are 56 chickens and 22 rabbits. The specific calculation process is as follows: there are x chickens and y rabbits. There are x=y=78,x=4y=200 solutions for x=56,y=22

Summary. Assuming that all rabbits are present, then there are a total of feet: 4 78 = 312 (only) more than the actual number of feet:

312-200 = 112 (only) This is because the chickens are treated as rabbits: 4-2 = 2 (only) so the chickens are: 112 2 = 56 (only).

Rabbits have: 78-56=22 (only).

A breeding group raises a total of 78 chickens and rabbits, with a total of 200 feet.

Assuming that all are rabbits, then there are a total of feet: 4 78 = 312 (only) more than the actual number of feet: 312-200 = 112 (only) This is because the chicken is used as a beam to accompany the rabbit Each difference is only counted as a dregs high:

4-2 = 2 (only) so chickens have: 112 2 = 56 (only) rabbits have: 78-56 = 22 (only).

56 chickens and 22 rabbits.

Solution: If there are x chickens, then there are 78-x rabbits.

2x+（78-x）×4=200

2x+312-4x=200

312-2x=200

2x=312-200

2x=112

x=112÷2

x = 56 rabbits have 78-56 = 22 rabbits.

There are 56 chickens and 22 rabbits. The specific calculation process is as follows: there are x chickens and y rabbits. There are x=y=78,x=4y=200 solutions for x=56,y=22

78x4-200

112 (only).

56 (only) 78-56 = 22 (only).

A: There are 56 chickens and 22 rabbits.

Solution: If there are x chickens, then there are 78-x rabbits.

2x+（78-x）×4=200

2x+312-4x=200

312-2x=200

x = 56 chickens and 56 rabbits have 78-56 = 22 rabbits.

Solution: 4x78=312 [If they are all rabbits.]

312-200=112 [Extra.

4-2=2 [The number of feet that rabbits have more than chickens.]

112 2=56 [Number of chickens.]

78-56=22 [The number of rabbits.]

Solution: If there are x rabbits, then chickens are (78-x).

Rabbit's feet are 4x, chicken feet are 2 (78-x).

The column equation is: 4x+2(78-x)=200

x = 22 chickens: 78-22 = 56 chickens.

Are you an elementary school student?

Rabbit's feet are 4x, chicken feet are 2 (78-x).

The column equation is: 4x+2(78-x)=200

x = 22 chickens: 78-22 = 56 chickens.

Answer: There are 56 chickens and 22 rabbits. The specific calculation process is as follows: there are x chickens and y rabbits. There are x=y=78,x=4y=200 solutions for x=56,y=22

56 chickens and 22 rabbits.

Solution: If there are x chickens, then there are 78-x rabbits.

2x+（78-x）×4=200

2x+312-4x=200

312-2x=200

2x=312-200

2x=112

x=112÷2

x = 56 rabbits have 78-56 = 22 rabbits.

Answer: There are 56 chickens and 22 rabbits. The specific calculation process is as follows: there are x chickens and y rabbits. There are x=y=78,x=4y=200 solutions for x=56,y=22

If there are x rabbits, then chickens are (78-x).

Rabbit's feet are 4x, chicken feet are 2 (78-x).

The column equation is: 4x+2(78-x)=200

x = 22 chickens: 78-22 = 56 chickens.

Are you an elementary school student?

Fake all rabbits with two feet raised.

Number of rabbits. Chicken 100-22 = 78

48 4 equals 312 brackets 312-200 brackets divided by two equals 56, 78-56 equals 22, 56 chickens and 22 rabbits.

Let's say both the chicken and the rabbit have 4 legs.

Number of chickens: 312 200) 2=56, number of rabbits:

78 56 = 22.

If you raise x chickens, you will raise rabbits (78-x), which means 2x+4(78-x) 200

2x＋312-4x＝200

2x＝112

x 56 means 56 chickens and 22 rabbits.

Solution: Set the rabbit to have.

Chickens have (78-x) only.

4x+2(78-ⅹ)=2oo

4ⅹ+156-2x =2oo

2x =44

x = 22 chickens: 78-22 = 56 (chickens)).

Answer: Chickens have.

There are 56 rabbits and 22 rabbits.

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