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There are a chicken and a rabbit in the cage.
a+b=180 …①
2a+4b=960…②
From a=180-b ....Bring in
2×(180-b)+4b=960
360-2b+4b=960
2b=960-360
b = 300 to calculate this is a miscalculation, a total of 180 chickens and rabbit heads, these 180 are rabbits, the calculation of feet (legs) is 180 4 = 720, obviously an unreasonable number.
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If the chickens are exempt from a total of 180 heads, if these 180 are all four legs, it is only 720 feet, and it will not reach 960 feet, so the number in the question is wrong.
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Let's say it's all rabbits:
180 4 = 720 (only).
All rabbits have 720 legs, but chickens and rabbits have a total of 960 legs, so there is a problem with the data of the question.
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Depending on the condition, there are at least 180*2=360 legs, and a maximum of 180*4=720 legs.
960 legs is out of the question.
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Chicken + Rabbit = 180
Chicken 2 + Rabbit 4=960
Solve the equation to obtain: The data in this question is incorrect.
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Your question is wrong, that is, there are 180 rabbits in this cage, and it does not have 960 legs, not to mention the common head of chickens and rabbits.
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It's not enough rabbit legs.
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Assuming that all chickens are there, then there are enough: 180*2=360
There is still a difference of 960-360=600
A rabbit has 2 more legs than a chicken, 600 2=300, and there is a problem with the data given by the question.
180 is considered a rabbit, there is enough 180 * 4 = 720 960, and the data is not appropriate.
Please refer to it. <>
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Solution, set rabbit x and chicken x + 40.
then 4 + 2 (x + 40) = 170
6x=90x=15
Chicken 15 + 40 = 55 (pcs).
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Let the rabbit be x, and the equation will be listed according to the problem.
4x+2*(x+40)=170
Solve the equation to get x 15
Chicken is 15 + 40 55
A: There are 55 chickens and 15 rabbits.
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If the chicken is x and the rabbit is -40, 2x+4(x-40)=17o, and x=55, then the chicken is 55 and the rabbit is 15.
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Number of rabbits: 170-40x2) (4+2)=15 (only).
Number of chickens: 15 + 40 = 55 (only).
Verification: 2x55 + 4x15 = 170
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92-29 2) (4-2), (92-58) 2, 34 2, 17 (only), Shirt.
29-17=12 (only); Mingplex cavity.
Answer: There are 12 Zheng Bi chickens and 17 rabbits in the cage
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Summary. Hello dear, there are 106 heads and 286 feet in the cage, 69 chickens, 37 rabbits. Question Analysis:
Assuming that 106 are all chickens, then there should be 106 2 = 212 feet, and 286-212 = 74 feet less. If a rabbit is seen as a chicken with two legs less, and there are several 2s in the number of fewer feet, it means that several rabbits are regarded as chickens. 74 2=37, which means that there are 37 rabbits, then chickens have:
106-37=69 (only). So the answer is: 37,69.
Hope it helps you <>
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Hello dear, there are 106 heads and 286 feet in the cage, 69 chickens, 37 rabbits. Question Analysis: Assuming that 106 are all chickens, Acorn should have 106 2 = 212 feet, and 286-212 = 74 feet less.
If a rabbit is seen as a chicken with two legs and a few 2s in the number of legs, the hood is clever to see several rabbits as chickens. 74 2 = 37, indicating that there are 37 rabbits, then chickens are: 106-37 = 69 (only).
So the answer is: 37,69. Hopefully, the key can help you <>
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I hope it will be helpful to you If you are satisfied with me, please give a thumbs up Your Pengzhou Noise Praise is the infinite power chain of my answer <>
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Summary. Column equations.
There are 200 chickens and rabbits with the head of the cage, a total of 580 feet, how many chickens and rabbits are in the cage?
Column equations. I'm sorry I don't understand, but can you elaborate on that?
If there are x chickens and rabbits, it is 200-x, and 2x+(200-x)x4=580 is counted as 110 chickens and 470 rabbits.
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Rabbits: 40-12 2) (4-2), 16 2, 8 (only);
Chickens have: 12-8 = 4 (only) scattered tombs;
Answer: There are 4 laughing books and 8 rabbits
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There are x chickens and y rabbits in the cage.
x+y=40 ①
2x+4y=100 ②
2: 2x+2y=80 ③
③:2y=20
y=10x=30
A: There are 30 chickens and 10 rabbits in the cage.
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Suppose there are x rabbits and y chickens, then.
x+y=40
4x+2y=100,y=40-x
4x+2(40-x)=100
Calculate x 10, y 30
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Solution: Set x rabbits and y chickens.
Then: x y 40
4x+2y=100
y=40-x
4x+2(40-x)=100
Calculate x 10, y 30
Hope it helps.
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You can use a column equation: let the number of rabbits be x and the number of chickens be y
Then: x+y=50;4x+2y=140 The equation can be calculated: 20 rabbits and 30 chickens.
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Suppose there are x chickens and y rabbits, 50 heads, x+y=50, one with 2 legs, one rabbit with 4 legs, 2x+4y=140 to solve the equation There are 20 rabbits and 30 chickens.
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Chickens and rabbits are in the same cage, with a total of 20 heads and 30 legs, which is impossible, and if they are both chickens, they should also have 40 legs, and it cannot be 30 legs. If there are 50 legs, chickens have (20 4-50) 2 = 15 and rabbits have 20-15 = 5.
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