When 2x square 3x 1 0, find the value of x 2 squared x x 5 2x 8?

Hello lz, : It is known that 2x2 + 3x + 1=0 can get 2x2 + 3x =-1 substituting the original formula to get the result of -5

The landlord asked the second question; Knowing the square of x - 2x = 2, find (x-1) (2x-1) - (x+1) squared +3

Untie; (x-1)(2x-1)-(x+1)'s square+3x2 -5x+3 known x's squared -2x=2; x = plus or minus root number 3 + 1

Substituting x2 -5x+3; 2+3 times root number 3 or 2-3 times root number 3

2x+1)(x-3)=0

In this way, the coefficient of factorization x 2 is obtained by multiplying the two digits on the left side of the posture, the constant is the multiplication of the two digits on the right, and the coefficient of x is the multiplication of the core number of the cross sail fork and then adding, that is, 2*(-3)+1*1=-5

Think of it this way.

2x 1x -3

In this way, (2x+1)(x-3)=0 is written in parallel

Summary. - 55x 4 + 120x 3 - 120x 2 + 60x - 1

Knowing that x squared + 2x-1 = 0, then the cubic of x is the value of 5x+4.

- 55x 4 + 120x 3 - 120x 2 + 60x - 1

I'm still a little confused, can you be more detailed?

The problem in the problem is to find the value of x to the third power - 55x4, which can be solved using the rules of polynomial multiplication. First, the cubic of x's source-55x4 is decomposed into (x-2) (x 2+10x+25), then x-2 and x 2+10x+25 are multiplied by x respectively to get x 3-2x 2+10x 2-20x+25x-50, and finally x 3-2x 2+10x 2-20x+25x-50 and -55x4 are added to get the value of x 3-57x4. Reason:

This is because of the rule of polynomial multiplication, which allows a polynomial to be broken down into multiple factors, then each factor is multiplied by another polynomial, and finally the products are added to get the final result. Solution: This problem can be solved using the rules of polynomial multiplication, where the polynomial is broken down into multiple factors, and then each factor is multiplied by another polynomial, and finally the product is added to get the final result.

Personal tip: When solving polynomial multiplication problems, keep in mind the rules of polynomial multiplication, decompose the polynomial into multiple factors, then multiply each factor by another polynomial, and finally add the product to get the final result.

x²+3x-1=0

x²+3x=1

x³+5x²+5x+18

x(x²+3x)＋2x²+5x+18

2x²+6x+18

2(x²+3x)+18

x^2+3x-1=0

x^2+3x=1

x^3+5x^2+5x+18

x^3+3x^2+2x^2+6x-x+18x(x^2+3x)+2(x^2+x)-x+18x+2-x+18

x^2+3x=1

x^2+3x^2=x

x^3+3x^2+2x^2+5x+18

x+2x^2+5x+18

2x^2+6x+18

2(x^2+3x)+18

Hope it can help you

x square + 3x - 1 = 0 multiplied by x on both sides

x to the power of 3 + 3x -x=0

x to the third power + 5x square + 5x to the third hand + 18

x-3x²+5x²+5x+18

2x²+6x+18

2（x²+3x-1）+2+18

6x cubic + 7x quadratic - 5x + 2011

6x -2x -2x + 9x -3x-3 + 20142x(3x -x-1)+3(3x -x-1)+2014 solution: multiply both sides of the equation x*2-3x-1=0 by 3x at the same time to obtain: 3x *3-9x*2-3x=0, and then add 2 to both sides of this equation at the same time to get :

3x *3-9x*2-3x+2=2

Solution: x 3+x 2-3x-5

x(x 2-x-1)+2x-2x-5 (because the condition x 2-x-1=0 is given in the question).

2(x^2-x-1)-3

Untie; x³+3x²=x+3

3x³+9x²-3x+1

3 (x +3x Feast Sale) -3x+1

3(x+3)-3x+1

3x+9-3x+1

From x +3x-1=0, we get: x +3x=1, from x +5x +5x+8x +3x +2x +5x+8

x（x²+3x）+2x²+5x+8

x+2x²+5x+8

2x²+6x+8

2（x²+3x）+8

x squared - 2x - 3 = 0

So 2(x -2x-3) = 0

So 2x -4x-6 = 0

Add 1 on both sides.

2x²-4x-5=1

So the value of 2x squared to 4x5 is 1

I'm glad to answer your questions and wish you progress in your studies! The Learning Guide team will answer the questions for you.

2x squared a 4xa 5

2 (x-2x-3) + 1

If 2x 2-5x-1 = -6

then 2x 2-5x+5 = 0

The equation is = 25-4 2 5 0

That is, x cannot be found, making 2x 2-5x-1 = -6 i.e. x does not exist.

So 2x 2-5x-1 ≠ 6

Adopt the overall substitution method to do the questions, and pay special attention to the addition and follow-up questions).

Solution: 8x squared - (x+2)(2-x)-2(x-5) squared = 8x +(x+2)(x-2)-2(x-5) = 8x +(x -4)-2(x -10x+25) = 8x +x -4-2x +20x-50

7x²+20x-54

By x=-3, i.e. 7x +20x-54

8x squared - (x+2)(2-x)-2(x-5) squared = 8x +x -4-2(x -10x+25) = 7x +20x-54

When x=-3.

Original = 63-60-54

According to 2x2+3x+1=0, x=-5 3 substitute the value of x into (x-2)2+x(x+5)+2x-8