Hurry, hurry! A few Pythagorean theorem math problems! Kneel and beg for answers! 30

Answer: 1 because the angle a = 1 2 angle b = 1 3 angle c triangle abc inner angle sum = 180 degrees.

So the angle a = 30 degrees, the angle b = 60, and the angle c = 90

The side opposite the angle c = 90 degrees is the longest side = 10

Then the side of the angle a=30 degrees is the shortest.

In a right triangle, the side of the 30-degree pair is equal to half of the hypotenuse.

Then the shortest variable is equal to 5

A2 The Pythagorean theorem gives c = a + b

If a=then c=13. If a=12, c=37, then b=12a:c=7:25, as a is 7 parts, c is 25 parts, then b is 24 parts.

A3: The longest should be the hypotenuse of 12mm and 4mm and 3mm to form a right triangle.

It should be 13mm

A4: In an equilateral triangle, the three lines are 1, and the three angles are all 60 degrees.

Then the square of the high is equal to.

The square of the side a minus half of the square of a is equal to the area of a 3 times the root number of 2 times = the base times the height divided by 2 = the square of the root number of 4 times 3 times a.

A5 is to form a right triangle.

The length of the ladder is 10 cm, and the vertical distance is 8 cm

The distance between the bottom end of the ladder and the wall is 6 cm

If it slides down 2cm, then it is height = 8-2 = 6cm

Then the bottom of the ladder is 8cm away from the wall, and the original distance is 6cm, so slide down 2cm, and the bottom of the ladder also slides 2cm to the right

Solution: 1 Let a be x, because la = half lb = one-third lc, so b = 2x, c = 3x, and because the sum of the inner angles is 180 °, so 6x = 180, so the angle c is equal to 90 degrees, so the shortest side is 1 2 of the longest side so the shortest side is 5 cm

2: A +B = C, so C=13, if A=12, C=37, then B=45, if A:C=7:25, let A=7T, C=25T, then B=24T, so A:B=7:24

3: The longest is under the root number (12 +4 +3), so the longest is: 13cm4: its height is under the root number (a - (a 2) ) = (root number 3) a 2, so the area is: root number 3) a 2 * a 2

Let's look at it this way, first of all, the angle a = 1 2 angle b = 1 3 angle c triangle abc inner angle sum = 180 degrees.

So the angle a = 30 degrees, the angle b = 60, and the angle c = 90

The side opposite the angle c = 90 degrees is the longest side = 10

Then the side of the angle a=30 degrees is the shortest.

In a right triangle, the side of the 30-degree pair is equal to half of the hypotenuse.

Then the shortest variable is equal to 5

Then the second problem, the Pythagorean theorem gives c = a +b

If a=then c=13. If A=12, C=37, then B=12A: C=7:25 is seen as A, is 7 parts, C is 25 parts, then B is 24 parts, the third question is simple, the longest should be the hypotenuse of 12mm and 4mm, and the hypotenuse of 3mm to form a right triangle.

It should be 13mm

The fourth problem is that the three lines of an equilateral triangle are 1, and the three angles are all 60 degrees squared.

The square of the side a minus half of the square of a is equal to the area of a 3 times the root number of 2 times the area of a = the base multiplied by the height divided by 2 = the square of the root number of 4 times 3 times a Finally, look at the fifth question, pay attention to the formation of a right triangle.

The length of the ladder is 10 cm, and the vertical distance is 8 cm

The distance between the bottom end of the ladder and the wall is 6 cm

If it slides down 2cm, then it is height = 8-2 = 6cm

Then the bottom of the ladder is 8cm away from the wall, and the original distance is 6cm, so slide down 2cm, and the bottom of the ladder also slides 2cm to the right

3.The length and width are the right-angled sides of the triangle, find out that the diagonal of the bottom surface is 4 times the root number 10, and then take it and 3 as the right-angled sides.

The Pythagorean theorem is ......

4 The side length is a, then the height = (the square of a + the square of a 2) the open root number.

h = (root number 3) 2 times a

5, with 10 as the hypotenuse, 8 as the right-angled edge, the horizontal distance is 6 down one meter to 7

With the Pythagorean theorem.

Slide down two meters with a right-angled side of 6 and two meters to the right.

Solution: Let the intersection of two red rays at the top of the tree be c, the letter at the root of the tree is d, the lower left side is e, and the lower right side is f

ecd+∠dcf=90°;∠ecd+∠e=90°.

Then: e= dcf; cde= cdf=90°

So, edc cdf, cd fd=ed cd, cd 2=fd*ed=8*2, cd=4 (m).- The height of the tree.

Let it be x, according to the projective theorem.

x²=2*8=16

x = 4 (m).

The most straightforward way is to set the tree height to x, the hypotenuse of a is y, and the edge of b is z. A system of ternary quadratic equations is obtained.

y square — x square = 4

z square - x square = 64

y square + z square = 100

This system of equations is not difficult to solve... Solve x, i.e. the tree height is more than 4 meters.

1) In ABC, C=90°, Ac=BC, A=(45°), B=(45°).

2) In ABC, A= B+ C, then ABC is a (right-angled) triangle.

1) Because c=90°, ac=bc, and the sum of the inner angles of the three corners is 180°, the triangle is an isosceles right triangle, a=(45°)b=(45°).

2) In ABC, a= b+ c, then abc is (right angled) triangle a= b+ c,, a+ b+ c= a+ a. The sum of the internal angles of the three corners is 180°, i.e., a+ b+ c=180°. Roll out a=90°.

3) As shown in the figure, in ABC, c=90°, a=30°(1) when ab=7. then bc=( )2) when bc=5, ab=(10)In a right triangle, the side of the 30-degree angle is equal to half the side of the hypotenuse.

Solution: The three sides of a right triangle are a b64-16b+b 2+64=64+16b+b 264=32b b=2

The triangle is three-sided: 6, and the area is 6*8 2=24

Question 2: Just use the Pythagorean theorem twice:

The circumference is: 15 + 13 + 14 = 42 hehe.

Because ab=6, ac=8, so bc2=ab2+ac2

So bc2=100

bc=10（。。You're talking so fast, you haven't learned yet, that's all you can do)