The school s football field is 105 meters long and 68 meters wide, how many square meters is the siz

A: The football field has an area of 346 square meters.

100 50 = 5000 (square meters).

A: The area is 5000 square meters

25,000 square meters. According to the title, it can be known that the area of the football field is 100 * 50 = 5000 square meters, and the area of the school is 5 times that of the football field, so that the area of the school is 5000 * 5 = 25000 square meters.

Because the area of the football field is 100 50 = 5000 square meters, the school is 5 times the size of the football cherry branch field, which is 5 5000 = 25000 square meters.

100 50 = 5000 (square meter hail Xun);

100+50) 2,150 2,300 (m);

Answer: The surface of the source is 5,000 square meters, and the circumference is 300 meters

110 75 = 8250 (square meters).

A: Its area is 8250 square meters

A football field is 110 meters long and 75 meters wide, and its area is 8,250 square meters.

It is known from the title that it is 110 meters long and 75 meters wide, because the football field is rectangular, so you can use the formula for calculating the area of the rectangle: length and width area So the area of the pitch is: 110 75 8250 (m).

Knowledge Expansion: Common Geometric Formulas in Primary School Mathematics.

Circumference of the rectangle = (length + width) 2 Formula: c=(a+b) 2 Circumference of the square = side length 4 Formula: c=4a

Area of the rectangle = length and width formula: no excitation friend s = ab

Area of the square = length of the side of the side of the locust Formula for the length of the side: s = a The area of the triangle = the height of the base 2 Formula: s=ah 2 The area of the parallelogram = the height of the base Formula: =ah

Area of the trapezoid=(upper bottom + lower bottom) Height 2 Formula: s=(a b)h 2 Diameter = radius 2 Formula d=2r Radius = diameter 2 Formula: r = d 2 Circumference of a circle = pi Diameter = Pi Radius 2 Formula:

c= d =2 rThe area of the circle = pi Radius Radius Formula: s= r <>

105 68 = 7140 (square meters).

The area of the football field is 7140 square meters.

Rectangle area = length x width = 105x68 = 7140 square meters.

80 50 = 4000 square meters.

2 (80+50) = 260 meters.

The area of this football field is 4,000 square meters, and the circumference is 260 meters.

Area: Length by width 80 50 4000 square meters.

Circumference (80+60) 2 260 m.

The football field is rectangular, then the floor area should be length times width, 80*50=4000 square meters. The circumference should be (length + width) 2, (80 + 50) * 2 = 260 meters.

Length * width = area, so 110m * 90m = 9900m 2, that is, 110 meters by 90 meters is equal to 9900 square meters.

The area of the rectangle == length times width. That is, 110 90==9900 What do you mean by 1k? 1000㎡？

That's one of the most noisy things about this course. If it means 1 (km) (i.e. one square kilometer), that is 11 times the size of the stadium.