What is the concentration of nitric acid of 33 and potassium hydroxide of 48 after neutralization?

This cannot be calculated, the mass of nitric acid and potassium hydroxide solutions must be known to be calculated.

Assuming that the same mass (both w) is mixed, Hno3+Koh=Kno3+H2O33%W x Y x=56*33%W 63= ,Y=101*33%W 63=

Obviously, there are two kinds of potassium hydroxide excess, post-neutralization solutes, among them:

Potassium hydroxide concentration = w (48%; Potassium nitrate concentration = .

Let the mass of nitric acid solution be x, the mass of potassium hydroxide solution be y, and the reaction product kno3 be z

Rule. The mass of the nitric acid solute is 33%x and the mass of the potassium hydroxide solute is 48%y, because after neutralization of the two, it is a 1:1 reaction assuming that the reaction happens to be complete.

Other words. hno3 + koh = kno3 + h2o33%x --48%y---z

Column proportional formula.

63：（33%x）= 56：（48%y）

Get. y =（11/18）x

63 ：(33%x) = 101 ：z

Get. z =（1111/21）x

Because: Total mass of solution after reaction:

m (nitric acid solution) + m (potassium hydroxide solution) = x + y = x + (11 18) x = (29 18) x

So. After neutralization, the concentrations are:

Solubility mass Solution mass * 100% = (1111 21) x * 100% =

Hope it helps.

What is their quality?

Hno3 + KOH ==== KNO3 + H2O, that is, after neutralization of nitric acid containing 63 grams of HNO3 and potassium hydroxide containing 57 grams of KOH, the reaction happens to be complete.

Since the nitric acid concentration is 33%, the other is 48%.

That is to say, 63 33% = 191g of nitric acid solution and 57 48% = potassium hydroxide solution are neutral. Satisfied

Theoretically, 100g of hydrogen and oxygen brigade can completely react with nitric acid, and the equation of the vertical reaction of the wheel is: 2koh + hno3 k2no3 + 2h2o.

The mass of the solution after the KOH + HNO3 = KNO3 + H2O reaction is 200 g and the mass of solute KNO3 is 200 * = g.

From the pH=7 after mixing, it can be seen that KOH and Hno3 happen to react completely.

Let the width of the stool participating in the reaction koh mass be x grams.

koh + hno3 = kno3 + h2ox

The mass of the koh is 56 x = 101

x = 28

So the mass fraction of the KOH solution is 28 jujube 100 = 28%.

It is understood that at 18 degrees Celsius, 100g of sodium hydroxide can completely react with 100g of nitric acid.

Inadequate? Do you want to ask?

33% nitric acid and 48% potassium hydroxide are neutralized, how much is the concentration after neutralization? ”

So. Parse. As follows: Set.

The mass of the nitric acid solution is x, the mass of the potassium hydroxide solution is y, the product of the reaction.

kno3. Z rule.

The mass of the nitric acid solute is 33%x, and the mass of the potassium hydroxide solute is 48%y. After neutralizing the two, it is assumed that it happens to be a complete reaction.

is a 1:1 reaction.

Other words. hno3

kohkno3h2o

33%x--48%y---z

Column proportional formula.

63：（33%x）=

56: (48%y) y

11/18）x

33%x)z. z（1111/21）x

Because: Total mass of solution after reaction:

m (sodium disturbance nitric acid solution) + m (potassium hydroxide solution) = xyx (11 18) x

29/18）x

So. After neutralization, the concentrations are:

Solubility Mass The quality of the solution.

1111/21）x

29/18）x

Hope it helps you.

What is their quality?

hno3koh

kno3h2o

That is, a solution of nitric acid containing 63 grams of HNO3 and potassium hydroxide containing 57 grams of KOH is neutralized, and it happens to be completely reactive.

Since the nitric acid concentration is 33%, another mountain slip is 48%, that is. 63 33% = 191g of nitric acid solution and 57 48% = potassium hydroxide solution after neutralization, just neutral. Satisfied

Inadequate? Do you want to ask?

What is the concentration of nitric acid of 33 and potassium hydroxide of 48 after neutralization? ”

So. The resolution is as follows:

Let the mass of nitric acid solution be x, the mass of potassium hydroxide solution be y, and the reaction product kno3 be z

Rule. The mass of the nitric acid solute is 33%x, and the mass of the potassium hydroxide solute is 48%y, because after neutralizing the two, it is a 1:1 reaction assuming that the reaction happens to be complete.

Other words. hno3 + koh = kno3 + h2o33%x --48%y---z

Column proportional formula.

63：（33%x）= 56：（48%y）

Get. y =（11/18）x

63 ：(33%x) =101 ：z

Get. z =（1111/21）x

Because: Total mass of solution after reaction:

m (nitric acid solution) + m (potassium hydroxide solution) = x + y = x + (11 18) x = (29 18) x

The light withered. After neutralizing Jingbi Cave, the concentration is:

Solubility mass Solution mass * 100% = (1111 21) x * 100% =

Hope it helps.

The concentration is generally calculated based on the mass fraction.

The concentration after complete neutralization is the total mass: m (nitric acid solution) + m (potassium hydroxide solution) The solute after neutralization is potassium nitrate.

The two are quietly divided: m (potassium nitrate) m (nitric acid solution) + m (potassium hydroxide solution), which is its concentration.

Nitric acid and potassium hydroxide do not have their respective concentrations and volumes, how to calculate?

kno3 ～ 1/2 k2o

101 1/2 * 9499% x

101/(1/2*94) = 99%/x

x = %kno3 content is 99%, which is converted to potassium oxide as %k2so4 k2o

85% y174/94 = 85% / y

y = %K2SO4 content is 99%, which is % converted to potassium oxide

The volume ratio is x:1, x*10 (-3)=10 (12-14), x=10, and the volume ratio of nitric acid to potassium hydroxide solution is 10:1

Set up the need for x tons to be neutralized.

Because the two are a 1:1 reaction.

That is, koh --hno356---6323 * 48% -x * 33% then 56 :(23 * 48%) = 63 : x * 33%) to get x = tons.

So it takes about tons of 33% nitric acid neutralization.

Hope it helps.

koh + hno3 = kno3+h2o56 63

23t*48% x*33%

56/63=(23t*48%)/(x*33%)x=

So 48% potassium hydroxide 23 tons and 33% nitrate tons neutralized.

Suppose 23 tons of potassium hydroxide and 33% x tons of nitric acid neutralize KOH + HNO3 = = = = KNO3 + H2O

56 6323*48%t 33%x56/63=23*48%t/33%xx=

Tons of hope can help you.

Let's put the formula to be calculated first, e.g. 2kH2PO4 --K2O

2k---k2so4

The factor of the element to be calculated before and after is the same, so it is not easy to make mistakes.

1 Potassium nitrate Kno3 molecular weight 101 Potassium oxide K2O molecular weight 94k2o---2kno3 Pure K2O content 94 2x101 = pure K content 39 101

In this way, the K content of the sample is 39 101 x 46% Nitrate nitrogen is the n in NO3-, and NO3- directly corresponds to N, and the N content is.

2 2kh2po4 --k2o

2x136 94

Pure K2O content = 94 2x136 =

3 Potassium 39 174 x 52% 54% = Right?

Pure K2SO4 K is 2, and the content of K is 2x39 174 sample 2x39 174 x 52% 54% =4 This counts.

In the first question, let the potassium nitrate mass y, (46%y*78 94+54%y*39 101) y=potassium content, (54%y*14 101) y=nitrogen content;

The second question, I don't understand, please be more detailed.

The third question is not correct, the mass fraction of pure potassium sulfate and potassium element is higher, and the mass fraction of potassium in potassium oxide is higher, if potassium sulfate is mixed with potassium oxide, the mass fraction of potassium element will not be lower than the original, but will only increase. The calculation is similar to the fourth question.

Question 4, Magnesium sulfate heptahydrate quality y, (magnesium content.

hno3+koh=kno3+h2o

The mass ratio of nitric acid to potassium hydroxide at the time of reaction is 63:56=9:8

Nitric acid and potassium hydroxide react in a ratio of 1:1, so the amount of nitric acid and potassium hydroxide are both 1mol

Write the equation first, and then calculate the amount of koh+hno3=kno3+h2o 1 to 1