Chemistry questions in the third year of high school

Analysis:1. Coexistence. Because these ions do not react, Cu2+ is a blue solution and is also a clear and clear solution.

2。Under standard conditions, the number of molecules in 1mol of CHCl3 is equal to 1 Na. Because CHCL3 is in a liquid state, exists in molecular form, and is not hydrolyzed, the number of molecules in 1mol of CHCL3 is equal to 1NA.

3。That's right. Because sodium carbonate is a strong electrolyte, it is all ionized in an aqueous solution, Na2CO3 = 2Na+ +CO32-

And sodium carbonate is a strong alkali and weak salt, hydrolysis, hydrolysis equation:

CO32- +H2O <=> HCO3- +OH- From which it can be seen that one CO32- generates two HCO3- +OH- anions.

hco3- +h2o <=> h2co3 + oh-

Therefore, the number of anions contained in the solution obtained by sodium carbonate dissolved in water is greater than.

1 No, because copper ions and sulfur ions will precipitate reactions! Sulfate can!

2 SPT condition chloroform is liquid yes!

3 co3+h2o=hco3+oh

Each molecule of carbonate is hydrolyzed to form one molecule of bicarbonate and hydroxide! So it's bigger than that.

My personal opinion.

Question 1: Copper ions have color, so they should not be clear. Magnesium and sulfur cannot coexist.

In the second question, CHCL3 should be liquid under the standard condition.

1. Do not coexist. Clear and transparent, can be colored! Otherwise, it will be called "colorless and transparent"! Copper ions and sulfide ions do not coexist to form copper sulfide precipitates.

2. Equal to 1NA. Chloroform, commonly known as chloroform, is a liquid under standard conditions. If the title says "L chcl3 under standard conditions", it is wrong and cannot be calculated in terms of gas. If 1mol is the right one.

3. Because the anions obtained by hydrolysis are in addition to HCO3- and OH- in water

1. No, because copper sulfate is a slightly soluble substance.

2. Because CHCL3 is easy to decompose into CCL4, and the molecular weight of CCL4 is larger than that of CHCL3.

3. There are often hydrogen ions and hydroxide ions in the solution, and the solution is alkaline after being dissolved in water, and if there are more hydroxide ions, the hydrolysis is carried out to the left, so the carbonate ions increase.

1. Because CHCL3 is a liquid under standard conditions, the intermolecular distance of liquid is much smaller than that of gas, and the density is much larger than that of gas, so the number of molecules is greater.

2. Because both the solution and the colloid are dispersion systems, the dispersion systems are electrically neutral, if there are cations, there must be anions with an equal charge (such as sodium chloride solution), or there are no charged particles (such as sucrose solution, so the anions and cations move to different poles respectively, 3. The colloid is a dispersion system, which is composed of dispersion and dispersant, and the dispersion system must be a mixture, so the colloid is a dispersion particle with a diameter between 1-100nm and dispersed into the dispersant. Particles with diameters between 1 and 100 nm may be pure, so the above statement is false.

4. It is wrong that pure iron is easier to rust than carbon steel, because carbon steel is easy to form iron-carbon primary cells for electrochemical corrosion, while pure iron cannot be electrochemically corroded, and the corrosion speed is very slow, and it will not rust for a few months.

Thank you for your acceptance!

Under standard conditions, it is liquid, so it is a large amount, definitely much more than that.

2.If the solute is ionized in solution, then the cations move towards the positive electrode and the anion towards the negative electrode.

3.The dispersed system with a diameter of 1 nm to 100 nm is called colloid. Colloids and particles are different concepts.

4.Pure iron is indeed not easy to rust. In the case of external electrolyte or water erosion, a galvanic cell is formed inside the carbon steel, with iron as the negative electrode and carbon as the positive electrode, which accelerates its corrosion rate; Pure iron, on the other hand, cannot be electrochemically corroded, and the corrosion rate is very slow, and it generally does not rust for several months.

1. Because in this state, CHCL3 is not gaseous;

2. It depends on what kind of charge you are talking about, if there is only one charge, then it will only move to one pole, and if it has two charges, it will move to both poles; However, if there is only one type of charged body, it is to move towards a certain pole.

3. Particles with a diameter between 1-100nm refer to dispersed particles, and such dispersions are colloids.

4. Carbon steel forms a galvanic battery.

1.Under standard conditions, chloroform is in liquid form.

2.In the solution state, it is possible to ionize to form anions and cations in order to be able to move to the poles when conducting3It may be a solid particle, colloids are for substances dissolved in water (or other liquids), which is a concept that belongs to the dispersion system.

4.Pure iron is not easy to rust, because iron rust is a redox reaction, is the process of electron gain and loss, but pure iron is not pure in other substances, it is not easy to form electron transfer, on the contrary, there is a certain proportion of carbon in carbon steel, in the presence of water and oxygen in the air, it can form a galvanic battery with iron, iron is the negative electrode to lose electrons to form positive divalent and positive trivalent iron ions, carbon is the positive electrode, oxygen gets electrons, and iron ions combine to form rust.

In standard condition, it is liquid.

2.Move towards a certain pole.

3.Colloids are a dispersion system, which is a mixture. It should be called colloidal particle 4Carbon and iron in carbon steel can form galvanic cells and accelerate the rusting of iron.

1. Chloroform is liquid under standard conditions 2. This forgot 3. Colloid is a kind of dispersion system with a diameter of dispersed particles between the coarse dispersion system and the solution, and the size of the dispersed particles is between 1nm and 100nm. Therefore, it is not true that particles with a diameter between 1 and 100 nm are called colloids 4 This involves the principle of galvanic cells, and carbon steel constitutes galvanic cells in the process of transportation, and the reaction speed is fast. It is recommended that you read more books on concepts. Come on.

It's liquid 2Move towards a certain level because the colloids are either uncharged or have a charge.

3.It should be a decentralized system.

4.Carbon steels can cause galvanic corrosion.

A can be based on the amount of nitric acid substances equal to the amount of sodium hydroxide substances plus the amount of gaseous substances to sum is correct.

b The number of electrons obtained by oxygen should be equal to the number of electrons transferred by the search to generate Cu2+, and the volume of oxygen in the photograph is calculated as correct.

c The electrons transferred during the lifting and dismantling of the reaction are wrong.

d By the sequence of transferred electrons, nitrogen dioxide can be calculated as correct.

Let the quantity of repentance or poor quality of no be x and the quantity of no2 be y, and the electron gain and loss will be conserved.

x+y= x+3y=

Let the amount of matter of no be x, and the amount of no2 is the hole y, and the electron gain and loss are conserved.

This question needs to consider the case of three molecules of urea forming rings. (similar to cyclic tripeptides) so there are 3 kinds of products:

Dimers (similar to dipeptides), chain trimers (similar to linear tripeptides), cyclic trimers (similar to cyclic tripeptides).

Let the amount of the substance of the dimer be x, the amount of the substance of the chain trimer is y, and the amount of the substance of the cyclic trimer is z

Conservation of carbon atoms, 2x + 3y + 3z = 120 from the removed NH3, x + 2y + 3z = 80 from the fraction of the amount of the dimeric substance, x (x+y+z) = solution x=30 mol, y = 10 mol, z=10 mol, so the ratio of the amount of matter is 3:1:1

The same metal element should be aluminum.

Select, m-al, q-s, r-be, t-o

a.Correctly, BE can react with both acids and bases.

B, False, Al is done by electrolytically molten Al2O3 because AlCl3 is a covalent compound and does not conduct electricity in the molten state.

c.False, H2S is more reductive than H2O, and H2O is more stable than H2S.

d.False, the largest ionic radius is S2-, and the order is S2->O2->Mg2+>Al3+> Be2+

Comparison principle: first look at the number of electron layers, the number of electron layers is larger.

If the number of electronic layers is the same, look at the number of nuclear charges, and the radius of the large number of nuclear charges is small.

I guess it's not the right choice.

Atomic radius nm

The main valencies +2 +3 +6, -2 +2 -2 can be obtained.

L-Mg, M-Al, Q-S, R-Be, T-Obe and Al are similar in nature according to the diagonal rule, and its oxide is also an amphoteric oxide, which can react with both acids and bases. So a yes.

B, Al is prepared by electrolytic molten Al2O3, and Mg is electrolytically molten MgCl2, both of which are obtained by electrolysis of its molten salt, so B is also right.

d. The largest ionic radius is S2-, and the order is S2->O2->Mg2+>Al3+> Be2+, so D pairs.

Then choose C, H2S has strong reducibility and poor thermal stability. Hope it helps.

Al m q r t are magnesium, aluminum, sulfur, beryllium, beryllium oxide and aluminum by diagonal elements with similar properties, it is easy to know that beryllium oxide and beryllium hydroxide both have amphoteric mg can be made of molten salts, while al metallicity is not strong, will be covalently bonded, and its molten salts do not conduct electricity, so they cannot be obtained by electrolysis.

Hydrogen sulfide is very reducible, and dihydrate is not reducible. The stability of water is stronger than hydrogen sulfide radius: be 2+

I didn't calculate this problem, because the idea is more important, and the starting point of this problem is the relationship between atomic radius and valence, and it is easy to distinguish which main group it is.