How much ampere current can a 2 5 aluminum bar withstand?

18A current.

The cross-sectional area of the aluminum bar is 20*mm², and it can withstand 50*3a-5a under normal circumstances, that is to say, 150a-250a;

i=p*heating equipment) 12kw*

Configuration of aluminum bars.

Calculate the load of the equipment to determine the heat exchange area of the aluminum bar.

qq= q1 + pq2+ q3+ q4

QQ - load of cold room cooling equipment, W;

Q1 -- Heat transfer of maintenance structure, w;

Q2 - Cargo heat, w;

Q3 -- Ventilation heat flow, w;

Q4 – Operating heat flow, w;

p – load factor. The cooling room, the freezing room p take, the other cold room take;

By substituting the known technical parameters into the above formula, the load value of the cooling equipment of the cold storage can be obtained, that is, the refrigeration capacity that the evaporator needs to provide, and the large cold storage should be strictly in accordance with the above calculation process.

The cross-sectional area of the aluminum bar is 20*mm², and it can withstand 50*3a-5a under normal circumstances, that is to say, 150a-250a;

i=p*heating equipment) 12kw*

The 150 square meter aluminum bar can withstand 18A current, which is no problem in the 230 environment (the aluminum bar is larger).

Hello, I'm glad to answer for you, 1, a single aluminum row load loss volume = width (mm) x thickness coefficient 2, aluminum row carrying capacity = width (mm) x thickness coefficient experience coefficient) 3, can also be by the number of squares, aluminum should be 3-5a Pingzhou trembling square. Hope it helps.

18A current, 18A current. Or the cross-sectional area of the aluminum bar is 20 * square millimeters, and it can withstand 50 * 3a - 5a under normal letter and simplicity, that is to say, 150a - 250a; i=p*heating equipment)12kw*aluminum bar configuration calculation equipment load to determine the aluminum bar heat exchange surface sliding dough trouser volume cooling equipment load calculation: you can refer to the relevant cold storage design manual for detailed calculation.

How much current can an aluminum bar of 100 10 have.

The maximum current value that can be supported by a 100 10 aluminum bar depends on many different factors, such as the construction temperature of the battery and circuit on the bar, the ambient temperature, the width and thickness of the aluminum bar and the length of the bar. Depending on the parameters, the maximum current values that can be supported by 100 10 aluminum bars can range from 2 amps to 50 amps. In addition, the aluminum bar should comply with industry standards, such as NEMA, IPCJ-STD-006, IPC-7525 and other standards, so that it is fixed and achieves the best conduction state during use.

Before any electronic operation, the aluminum bar should be cleaned as much as possible to prevent changes in conductivity caused by ingress dust, etc. In addition, the pressure in the discharge should be adjusted vertically at the contact point to ensure that the temperature of the contact is as low as possible and the conductivity of the discharge is protected as much as possible.

Summary. How many currents can the aluminum bar 30 6 pass pro, hello! 30 6 aluminum bars 30 current 30x6 square aluminum wire maximum current carrying capacity of 30a, but considering the ambient temperature and heat dissipation, so the maximum safe current carrying capacity is 24a, then the maximum load capacity is 24 * 220 = 5280w30 * 6 square aluminum core wire to about 4 square copper core wire, can withstand 30a current, to close the kilowatt of single-phase 220v, if it is with single-phase 380v kilowatt; Three-phase 380 220V can be connected with kilowatts.

Hope it helps!

How many currents can be passed through the aluminum bar 30 6.

How many currents can the aluminum bar 30 6 pass pro, hello! 30 6 aluminum bar 30 current 30x6 square aluminum wire maximum current carrying capacity of 30a, but considering the ambient temperature and heat dissipation, so the maximum safe current carrying capacity of 24a, then the maximum load capacity of 24 * 220 = 5280w30 * 6 square aluminum core wire to about 4 square copper core wire, can withstand 30A current, to close the kilowatt of single-phase 220V, if it is with a single phase of 380V kilowatt; Three-phase 380 220V can be connected with kilowatts. Hope it helps!

Town Beam. No, my aluminum bar is 3 cm, the thickness is 6 mm, and the current should not be bearing, so small.

No, my aluminum bar is 3 cm, the thickness is He Zheng belt 6 mm, the current should not be subjected, so small, dear, hello! Each square millimeter of aluminum wire has a bearing rated current value, you can calculate the cross-sectional area of each aluminum wire, you can know the total area of the cable, and you can calculate the total allowable current, I hope to help you!

How many currents can be passed through the aluminum bar 30 6.

Hello, glad to answer for you: 30 6 aluminum bars 30 current. The maximum current carrying capacity of 30x6 square aluminum wire is 30A, but considering the ambient temperature and heat dissipation, the maximum safe current carrying capacity is 24A, then the maximum load capacity is 24*220 = the aluminum core wire of Pingbei's square Yinfeng to the copper core wire of about 4 square fronts, which can withstand 30A current, and close the kilowatt with single-phase 220V, if it is with single-phase 380V kilowatt.

How many currents can be passed through the aluminum bar 30 6.

How many currents can be passed by aluminum bar 30 6 Hello dear, I am glad to answer for you. 30 "30 6 aluminum bars 30 current 30x6 square aluminum wire has a maximum current carrying capacity of 30a, but considering the ambient temperature and heat dissipation, the maximum safe current carrying capacity is 24a, then the maximum load is 24 * 220 = 5280w30 * 6 square aluminum core wire to about 4 square copper core wire, can withstand 30A current, to close the imitation of single-phase 220V kilowatts, if it is with single-phase 380V kilowatts; Three-phase 380 220V can be connected with kilowatts. Hope it helps!

Hope it helps. If my answer is helpful to you, please give a thumbs up (in the lower left corner), I look forward to your like, your efforts are very important to me, and your support is also the motivation for my progress. Finally, I wish you good health and a happy mood!

Summary. Hello, I am glad to serve you The answer to how much A current does the 250*6 double aluminum bar bear: Under the three-phase electricity 380V, the current carrying capacity of the three-core 6 square aluminum wire is found to be 38A.

The formula for calculating the load is as follows: p= =21kw (the power factor is taken as a single-phase electricity of 220V, and the resistive load is calculated as follows: p=ui=220*38=.)

How much A current does a 250*6 double aluminum bar withstand.

Hello, I am glad to serve you The answer to how much A current does the 250*6 double aluminum bar bear: Under the three-phase electricity 380V, the three-core 6 square aluminum wire is found to have a current carrying capacity of 38A. The formula for calculating the load is as follows:

P==21KW (The power type hit-ride factor is taken as a single-phase electric noise of 220V, and the resistive load is calculated as follows: P=UI=220*38=.)

I hope the above can be helpful to you and have a great life.

You can check it on the Internet, there is a copper and aluminum line current calculation algorithm, which is an empirical algorithm actually summed up by the old-timers, and the difference between the top and bottom is not too much, this is a thing I have archived before I hope it will be useful to you:

Estimation formula: 2.5 times 9, subtract one straight up and go.

Thirty-five times 3.5, double in a group minus five.

The conditions have been changed and converted, and the high-temperature nine-fold copper has been upgraded.

The number of pipe roots is two, three, four, eight, seven and six folds full of load current.

Note: (1) The current carrying capacity (safety current) of various insulated wires (rubber and plastic insulated wires) is not directly indicated in this section"The cross-section is multiplied by a multiplier"to express, through mental arithmetic. As can be seen from Table 5 3, the multiplier decreases with the increase of the cross-section.

Multiply by nine at 2.5 and subtract one by one straight up"It is said that the aluminum-core insulated wire of various cross-sections of 2 5mm' and below, its current carrying capacity is about 9 times the number of cross-sections. For example, 2 5mm' wire, the current carrying capacity is 2 5 9 22 5 (a). The relationship between the current carrying capacity and the number of cross-sections of the wire from 4mm' and above is to go up along the wire number, and the multiple is gradually reduced to L, that is, 4.

Thirty-five times 3.5, double in a group minus five. ", talking about 35mm"The current carrying capacity of the wire is 3 5 times the number of cross-sections, i.e. 35 3 5 122 5 (a). From 50mm' and above wires, the multiplier relationship between the current carrying capacity and the number of cross-sections becomes two two wire numbers in a group, and the multiples are subtracted by 0 5 in turn. That is, the current carrying capacity of the mm' wire is 3 times the number of cross-sections"The current carrying capacity of the wire is 2 5 times the number of its cross-sectional area, and so on.

The conditions have been changed and converted, and the high-temperature nine-fold copper has been upgraded. "。The above formula is based on the aluminum core insulated wire and the open application at an ambient temperature of 25. If the aluminum core insulated wire is laid in an area where the ambient temperature is higher than 25 for a long time, the current carrying capacity of the wire can be calculated according to the above formula calculation method, and then it can be discounted; When using not aluminum wire but copper core insulated wire, its current carrying capacity is slightly larger than that of aluminum wire of the same specification, and the current carrying capacity of one wire number can be calculated according to the above formula method.

For example, the current carrying capacity of 16mm' copper wire can be calculated as 25mm2 aluminum wire.