What are the reagents for distinguishing KCl solution from K2CO3? What is the ion equation?

Of course, dilute strong acids to identify, such as HCL, the gas is potassium carbonate, and the unchanged is potassium chloride, you can't identify from potassium chloride, potassium chloride can produce precipitated potassium carbonate, so you can only consider potassium carbonate. Ion equation: 2H++CO32-=CO2+H2O

The reagent is dilute hydrochloric acid, and the ion equation is: 2H+ +CO3 2- == H2O + CO2

Produces colorless gases.

Reagent: dilute hydrochloric acid, KCl solution and hydrochloric acid do not react, K2CO3 and hydrochloric acid react to form colorless gas.

Ion equation: 2H+ +CO32- = H2O+CO2

There are many reagents, mainly depending on the difference between CL- and CO3 2-.

1.Add an excess of dilute hydrochloric acid, and it is K2CO3 that bubbles

i.e. CO3(2-)+2H(+)=H2O+CO22Add barium hydroxide solution, and the precipitate is K2CO3BA(2+)+CO3(2-)=BAC3

Dilute hydrochloric acid. Phenomenon: HCl: no phenomenon H2CO3: bubbles generated.

Ion equation: 2H+ CO3 2- H2O CO2.

Ca2+ +CO3 can be identified with calcium chloride, Ca2+ +CO2- ====CaCO3,

In fact, you can use the positive drop and reverse drip without other reagents If the hydrochloric acid solution is dropped first, it is a large amount of potassium carbonate solution, that is to say, there is a lot of carbonate, hydrogen ions go in, and hydrogen ions go in and react with carbonate first to generate bicarbonate, so there is no phenomenon in the solution at the beginning.

On the contrary, if potassium carbonate solution is used to drop hydrochloric acid solution, at this time, there are a large number of hydrogen ions, so it will react with carbonate immediately, and the initial phenomenon is bubbles

This is the positive and reverse drip without the help of other reagents.

The question is vague.

In fact, these two reagents can detect each other. Add dropwise to solution B with solution A, and gas will be produced immediately, then B is hydrochloric acid and A is potassium carbonate. Add B to A dropwise, and then there is no phenomenon and then gas is generated, then A is potassium carbonate and B is hydrochloric acid.

Or with barium hydroxide, barium chloride. And silver nitrate can not be used.

Divide the samples into three parts, add carbonic acid, strong acid to make weak acid, and use pH test paper.

It is acidified with hydrochloric acid first, and then barium chloride is added.

The ion equation of dilute hydrochloric acid is: CO32-+2H+=CO2 (gas symbol) + H2O

Dilute hydrochloric acid, a reagent for the identification of KCl solution and K2CO3.

CO32-+2H+=CO2 (gas symbol) + H2O Reagent to remove a small amount of NaHCO3 impurities mixed with NaCl solution Dilute hydrochloric acid HCO3-+H+=CO2 (gas symbol) + H2O to remove NaHCO3 impurities mixed in Na2CO3 powder can be heated to 2NaHCO3=Na2CO3+CO2+H2O alum in water The ionization equation kal(SO4)2= K++ AL3+ +2SO42-